SATHEE: Atomic Structure Question 312

Atomic Structure Question 312

Question: For principle quantum number $n = 4$ the total number of orbitals having $l = 3$

[AIIMS 2004]

Options:

A) 3

B) 7

C) 5

D) 9

Show Answer

Answer:

Correct Answer: B

Solution:

$n = 4, \to 1 s^{2},, 2 s^{2},, 2 p^{6},, 3 s^{2},, 3 p^{6},, 3 d^{10},, 4 s^{2},, 4 p^{6},, 4 d^{10},, 4 f^{14}$ So $l = (n - 1) = 4 - 1 = 3$ which is f orbit contain 7 orbital.

Atomic Structure Question 312

Question: For principle quantum number $n = 4$ the total number of orbitals having $l = 3$

Options:

Answer:

Solution:

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Atomic Structure Question 312

Question: For principle quantum number n=4 the total number of orbitals having l=3

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: For principle quantum number $n = 4$ the total number of orbitals having $l = 3$