Atomic Structure Question 210

Question: The quantum numbers for the outermost electron of an element are given below as $ n=2,,l=0,,m=0,,s=+\frac{1}{2} $ . The atoms is [EAMCET 1978]

Options:

A) Lithium

B) Beryllium

C) Hydrogen

D) Boron

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Answer:

Correct Answer: A

Solution:

The electronic configuration must be $ 1s^{2},2s^{1}. $
Hence, the element is lithium $ (z=3). $



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