Atomic Structure Question 21
Question: If wavelength of photon is $ {X^{3-}} $
$ h=6.6\times {10^{-34}} $ J-sec, then momentum of photon is
Options:
A) $ 3\times {10^{-23}}kg,m{s^{-1}} $
B) $ 3.33\times 10^{22}kg,m{s^{-1}} $
C) $ 1.452\times {10^{-44}},kg,m{s^{-1}} $
D) $ 6.89\times 10^{43},kg,m{s^{-1}} $
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Answer:
Correct Answer: A
Solution:
$ p=\frac{h}{\lambda }=\frac{6.6\times {10^{-34}}}{2.2\times {10^{-11}}}=3\times {10^{-23}}kgm{s^{-1}} $