SATHEE: Atomic Structure Question 197

Atomic Structure Question 197

Question: A certain metal when irradiated to light (v = 3.2 $\times 10^{16}$ Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by ligh1 (v = 2.0 $\times 10^{16}$ Hz) The $v_{0}$ (threshold frequency) of metal is

Options:

A) $1.2 \times 10^{14} H z$

B) $8 \times 10^{15} H z$

C) $1.2 \times 10^{16} H z$

D) $4 \times 10^{12} H z$

Show Answer

Answer:

Correct Answer: B

Solution:

$K E = h v_{0} - h v_{0}$

$h v_{1} - h v_{0} = 2 (h v_{2} - h v_{0})$

$v_{0} = 2 (v_{2} - v_{1})$

$= 2 (2.0 \times 10^{16}) - (3.2 \times 10^{16})$

$= 8 \times 10^{15} s^{- 1} = 8 \times 10^{15} H Z$

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Atomic Structure Question 197

Question: A certain metal when irradiated to light (v = 3.2 ×1016 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by ligh1 (v = 2.0 ×1016 Hz) The v0 (threshold frequency) of metal is

Options:

Answer:

Solution:

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Question: A certain metal when irradiated to light (v = 3.2 $\times 10^{16}$ Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by ligh1 (v = 2.0 $\times 10^{16}$ Hz) The $v_{0}$ (threshold frequency) of metal is