SATHEE: Atomic Structure Question 178

Atomic Structure Question 178

Question: Calculate de-Broglie wavelength of an electron travelling at 1% of the speed of light

[DPMT 2004]

Options:

A) $2.73 \times 10^{- 24}$

B) $2.42 \times 10^{- 10}$

C) $242.2 \times 10^{10}$

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

One percent of the speed of light is $v = (\frac{1}{100}) (3.00 \times 10^{8} m s^{- 1})$ = $3.00 \times 10^{6} m s^{- 1}$ Momentum of the electron $(p)$ = $m ν$ = $(9.11 \times 10^{- 31} k g), (3.00 \times 10^{6} m s^{- 1})$ = $2.73 \times 10^{- 24} k g, m s^{- 1}$ The de-broglie wavelength of this electron is $λ = \frac{h}{p} = \frac{6.626 \times 10^{- 34}}{2.73 \times 10^{- 24} k g m s^{- 1}}$

$λ = 2.424 \times 10^{- 10} m$ .

Atomic Structure Question 178

Question: Calculate de-Broglie wavelength of an electron travelling at 1% of the speed of light

Options:

Answer:

Solution:

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Atomic Structure Question 178

Question: Calculate de-Broglie wavelength of an electron travelling at 1% of the speed of light

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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