Atomic Structure Question 172

Question: What will be de-Broglie wavelength of an electron moving with a velocity of $ 1.2\times 10^{5},m{s^{-1}} $

Options:

A) $ 6.068\times {10^{-9}} $

B) $ 3.133\times {10^{-37}} $

C) $ 6.626\times {10^{-9}} $

D) $ 6.018\times {10^{-7}} $

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Answer:

Correct Answer: C

Solution:

$ \lambda =\frac{h}{p} $ , $ p=mv $

$ \lambda =\frac{h}{mv} $

$ =\frac{6.62\times {10^{-34}}}{9.1\times {10^{-31}}\times 1.2\times 10^{5}} $

$ \lambda =6.626\times {10^{-9}}m $ .



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