Atomic Structure Question 123

Question: The energy of the electron in the first orbit of $ H{e^{+}} $ is $ -871.6\times {10^{-20}}J $ . The energy of the electron in the first orbit of hydrogen would be [Roorkee Qualifying 1998]

Options:

A) $ -871.6\times {10^{-20}}J $

B) $ -435.8\times {10^{-20}}J $

C) $ -217.9\times {10^{-20}}J $

D) $ -108.9\times {10^{-20}}J $

Show Answer

Answer:

Correct Answer: C

Solution:

$ {E_{1H{e^{+}}}}={E_{1H}}\times z^{2} $

$ -871.6\times {10^{-20}}=E_{1H}\times 4 $

$ {E_{1H}}=-217.9\times {10^{-20}}J $



NCERT Chapter Video Solution

Dual Pane