Atomic Structure Question 100

Question: An element have atomic weight 40 and it-s electronic configuration is $ 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}. $ Then its atomic number and number of neutrons will be [RPMT 2002]

Options:

A) 18 and 22

B) 22 and 18

C) 26 and 20

D) 40 and 18

Show Answer

Answer:

Correct Answer: A

Solution:

$ Ar_{18}^{40} $ = atomic number 18 and no. of Neutron in case of $ Ar_{22} $

Neutron = Atomic mass - Atomic number $ =40-18=22 $



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