Atomic Structure Question 1

Question: The ionisation potential of a hydrogen atom is -13.6 eV. What will be the energy of the atom corresponding to $ n=2 $ [Pb. CET 2000]

Options:

A) -3.4 eV

B) -6.8 eV

C) -1.7 eV

D) - 2.7 eV

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Answer:

Correct Answer: A

Solution:

Energy of an electron $ E=\frac{-E_0}{n^{2}} $ For energy level $ (n=2) $

$ E=-\frac{13.6}{{{(2)}^{2}}}=\frac{-13.6}{4}=-3.4eV $ .



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