λ1=Ry(n121−n221)
Ry=1.0973731568508(65)×107m−1
n1n2 integers
Spectral series
Lyman: n1=1,n2=2,3,⋯
Balmer: n1=2,n2=3,4⋯
Paschen: n1=2,n2=3,4,⋯
Brackett, Pfund, Humphreys, Strong and Hansen
Only discrete orbits are allowed
Quantization of Angular Momentum
mvnrn=nℏ≡2πnh
Modes of vibration
Analogy with vibrating strings revise.
mvnrn=nℏℏ=2πh
rnmvn2=r2k;k=4πϵ0ze2
z=1
mrnn2ℏ2=k
rn=mkn2ℏ2
rnn2=constant
rn=mkn2ℏ2
Vn=−rnk=n2ℏ2−mk2
Tn=21mvn2
mvnrn=nℏ
vn2=m2rn2n2ℏ2=21mm2rn2n2ℏ2
Tn=21m2mn2ℏ2n4(ℏ)4m2k2
Tn=21n2ℏ2mk2
Vn=−n2ℏ2mk2
En=−21n2ℏ2mk2
All the result
Scaling laws
rn∼n2
vn∼n1
Tn,Vn∼n21
En∼n21
Tn=−21Vn
En<0 for all n
Method: Test the model in a different setting
Two examples:
Franck-hertz experiment
Vibrational states of molecules
Mercury(Vapour): Hg
In discharge tubes, Hg emitted radiation of about 250nm. (sharpline)
Franck hertz experiment
Additional evidence
Scattering of electrons by mercury
Franck hertz experiment
Take a small quantity of mercury (in the vacuum tube) and evaporate
Low density Hg vapour in the Vacum tube distributed all over.
They injected accelerated electrons in the tube.
Energy range was a fraction of eV to about 80eV
1eV−80eV
The cathode ray particles (electron) interact with the electrons in Hg Atom.
ΔE=E1−Eg
Additional evidence
Scattering of electrons by mercury
Energy of scattered e− in zero
7−4.9=2.1eV
Cathorde e− energy in 7eV
Ein10.8eV
Final energy is 10.8−9.8=1.0eV
14.7eV4⋅9×3
Waited: Excited vapour emits light of energy 4.9eV
Additional evidence
Scattering of electrons by mercury
Modern day Experiment
Neon → already a gas atoms
Emitted radiation is in the visible range
Franck hertz experiment
Additional evidence
Scattering of electrons by neon
Example:- Van-der Waals
r6A−r7B
V(r) has a Vanishing derivative at r=R;
Which is a position for minima:
∂r2∂2V∣r=R >0
∂r∂V∣r=R=0
Make a Taylor expansion of V(r) around r=R
∂r2∂2Vr=R=K>0
V(r)=V(R)+21K(r−R)2+ higher order
ρ=∣r−R∣.
V=V0+21KP2
Harmonic oscillator potential
K→ Spring constant
Apply the Bohr model hypothesis to SHO
E=21mv2+21kx2=21mv2+21mω2x2
F=−k
E=21mv2+21kr2=21mv2+21mω2r2
F=−kr Hooke's law in three dimension
Circular orbits + Bohr quantization.
rnmvn2=+krn=−mω2r
mvnrn=nℏ
m(rn2vn2)=k= constant
vn=mrnnℏ
vn2=m2rn2n2ℏ2
∴mrn2vn2=mm2rn2n2ℏ2rn21
Constant = {k} = rn4=mkn2ℏ2=m2ω2n2ℏ2.
rn4=m2ω2n2ℏ2
rn2=n(mωℏ)⇒Vn∝n
Quantum mechanics Bohr model in giving a new length scale