physics-class-12-unit-03-chapter-13-wheatstones-bridge-meter-bridge-and-potentiometer-l-10-11-whsf4kxg8wo

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Example </primary>
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- A B C D E F A

- $ 2 I "+I "+I "+2 I "-I-I=0 $

- $ I "=\frac{I}{3} \mid $

- $ I _{ in }=2 I+2 I " $

- $ =2 I+\frac{2}{3} I=\frac{8 I}{3} $

- $ V=\frac{8 I}{3} R_{e q} \equiv 2 I R $

- $ R_{e q}=\frac{3}{4}$ R

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<footer style = "font-size: 18px">Wheatstone's Bridge, Meter Bridge and Potentiometer $\rightarrow$ Rules $\rightarrow$ <span style = "color:blue"> Example </span> $\rightarrow$ Examples $\rightarrow$ Example </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Examples </primary>
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- **Right hand loop**	
	
- $-(I_2 - I_3).2 + (I_2+I_3-I_1) \times 2 + 5=0$

- $ 2I_1 + 4 I_2 - 4 I_3 = 5$-------(1)
	
- **Upper Left Loop**
- $-I_2 \cdot 4-\left(I_ 2+I_ 3\right) \cdot 2-I_1 +10=0$

- $I_1+6 I_2+2 I_3=10$-------(2)

- $-(I_1 - I_2)4 + (I_2+I_3-I_1) \times 2-I_1 \cdot 1=0$

- $ 7I_1 + 6 I_2 + 2 I_3 = 10$-------(3)

- $ I_1=\frac{5}{2} \mathrm{A} $,$ I_2=\frac{5}{8} \mathrm{A} $,$ I_3=\frac{15}{8} \mathrm{A}$

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<footer style = "font-size: 18px">Rules $\rightarrow$ Example $\rightarrow$ <span style = "color:blue"> Examples </span> $\rightarrow$ Example $\rightarrow$ Example </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Example </primary>
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- **LOOP BCDAB**

- $-2 I_1 R-\left(I_1-I_2\right) R+I_2 R=0$

- $I_2=\frac{3}{2} I_1$

- **ADFEXYA**

- $-I_2 R-2 I_1 R =V$ 
; $I_1=\frac{2}{7} \frac{V}{R}$

- $I_1+I_2=\frac{5}{4} \cdot \frac{V}{R}=\frac{V}{R {eq}}$

- $\therefore R_{eq}=\frac{7}{5} R$

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<footer style = "font-size: 18px">Example $\rightarrow$ Examples $\rightarrow$ <span style = "color:blue"> Example </span> $\rightarrow$ Example $\rightarrow$ Wheatstone's Bridge </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Example </primary>
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- **EFOE:(LOOP)**

- $-I_3 R-I_3 R+\left(I_2-I_3\right) R  =0 $

- $ \Rightarrow I_3=I_2 / 3$

- **EOAE :**

- $ -I_2 R-I_3 R+I_1 R=0 $

- $ I_2=\frac{3}{4} I_1$

- $ I_1+I_2=\frac{7}{4} I_1,$

- $ 2 I_1 R=V $;

- $I_1=\frac{V}{2 R} $
- $ = \frac{7}{8}\frac{V}{R}=\frac{V}{R_{eq}}$

- $R_{eq}=\frac{8}{7} ?$

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<footer style = "font-size: 18px">Examples $\rightarrow$ Example $\rightarrow$ <span style = "color:blue"> Example </span> $\rightarrow$ Wheatstone's Bridge $\rightarrow$ Example </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Wheatstone's Bridge </primary>
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- Measure resistance in range $1 \Omega$ to $10^6 \Omega$ with 1% accuracy.

- $R_1, R_2$ known, $R_3$ can be varied, and $R_4$ unknown.

- Null Deflection resistance

- Adjust the variable resistance $R_3$ till No current passes through ammeter.

- $ {I_1}{R_1} = {I_2}{R_2}$

- ${I_1}{R_3} = {I_2}{R-x}$

- $\frac{R_1}{R_3}=\frac{R_2}{R_x} \Rightarrow R_x=\frac{R_2}{R_1} \cdot R_3 $

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<footer style = "font-size: 18px">Example $\rightarrow$ Example $\rightarrow$ <span style = "color:blue"> Wheatstone's Bridge </span> $\rightarrow$ Example $\rightarrow$ Example </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Wheatstone's and Meter Bridge </primary>
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- Is a balanced wheatstone's bridge.
 
- No current through CD.
 
- $R_{eq} = R$
 
- **Meter Bridge**
 
- No ourrent through Galvanometes.

- $ \frac{R}{S}=\frac{R_{A D}}{R_{D B}}=\frac{\rho l / A}{\rho (100-1) / A} $

- $\rho$ is in  $\Omega-\mathrm{cm}$

- l in cm
- $ =\frac{l}{100-l}  $

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<footer style = "font-size: 18px">Example $\rightarrow$ Example $\rightarrow$ <span style = "color:blue"> Wheatstone's and Meter Bridge </span> $\rightarrow$ Null Deflection $\rightarrow$ Finding Internal Resistance of a Battery </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Null Deflection </primary>
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- **Three way key**

- $\frac{\varepsilon_1}{\varepsilon_2}=\frac{l_1}{l_2}$

- **Null Deflection**

- $AP\varepsilon_{1}r_{1}13GN_{1}$, No current

- There is a potential drop in the wire $A B$

- Potential Drop across $A N_1=P . D$.

- $I R_{A N_1}=\rho \frac{L_1}{A}=\varepsilon_1$ across $P\varepsilon_1$, N

- $I R_{AN_2}$ = $\rho \frac{L_2}{A}$ = $\varepsilon_2$

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<footer style = "font-size: 18px">Example $\rightarrow$ Wheatstone's and Meter Bridge $\rightarrow$ <span style = "color:blue"> Null Deflection </span> $\rightarrow$ Finding Internal Resistance of a Battery $\rightarrow$ Potential Drop </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Finding Internal Resistance of a Battery </primary>
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- $k_1$ closed and $k_2$ is open Null Deflection is obtained at $N_1$

- current through $A B: I=\frac{V}{R_V+R^{\prime}}$

- $R^{\prime}=$ Resistance of Length $A B$ (of Length L)
 
- **Potential Gradient**

- $\Phi=\frac{V \cdot R^{\prime}}{R_V+R'}, / L$

- $: \quad \varepsilon=\Phi R_1$

- For Null Deflection

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<footer style = "font-size: 18px">Wheatstone's and Meter Bridge $\rightarrow$ Null Deflection $\rightarrow$ <span style = "color:blue"> Finding Internal Resistance of a Battery </span> $\rightarrow$ Potential Drop $\rightarrow$ Thank You </footer>

### <Success style="font-size:25px"> Wheatstones Bridge Meter Bridge And Potentiometer L-10 </Success>
### <primary style="font-size:24px"> Potential Drop </primary>
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- K2 closed: the cell $\varepsilon$ sends a current.

- $I^{\prime}=\frac{\varepsilon}{R+r}$

- Potential drop across $C D$ is

- $ \varepsilon-I{ }^{\prime} r=\Phi l_2 $

- $=\frac{\epsilon R}{R+r} $

- $ \varepsilon=\Phi l_1 $

- $ r=\frac{l_1-l_2}{l_2} \cdot R$

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![image](https://temp-public-img-folder.s3.ap-south-1.amazonaws.com/sathee.prutor.images/subject-images/iitpal/image/physics-class-12-unit-03-chapter-13-wheatstones-bridge-meter-bridge-and-potentiometer-l-10_11-whsf4kxg8wo-14.jpg)

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<footer style = "font-size: 18px">Null Deflection $\rightarrow$ Finding Internal Resistance of a Battery $\rightarrow$ <span style = "color:blue"> Potential Drop </span> $\rightarrow$ Thank You $\rightarrow$  </footer>