Series and Parallel Combination
Parallel Combination
Voltage across each member is same
ΔV=I1R1=I2R2=I3R3
Series Combination
Same current through each member
Vab=I(R1+R2+R3)
When switch is open
Ce : R1 is in series with R2
R12=12Ω
R34=20Ω
R12 and R34 are parallel
Req1=R121+R241
=121+201
Req=215Ω
I=15/221=2.8 A
ΔVce=ΔVdf=21 V
I1=1221=1.75 A
I2=2021=1.05 A
Va=21−I1R1=21−47×4=14 V
Vb=21−I3R3=21−2021×12=8.4 V
va=vb
vc=vd
ve=vf
a≡a′
b≡b′
R1∣∣R3⇒R13=R1+R3R1R3
=1648=3Ω
R2∣∣R4⇒R24=R2+R4R2R4=4Ω
I=3 A
Drop across ca is 9V
Drop acros ae is 12V
Drop across ca=9v
I1=49=2.25 A
Drop across ae = 12
I2=712=1.5 A
Iab=0.75 A
Req =2+42×4=68=34Ω
Net Resistance
Rfinal =4×34=316Ω
Req is Parallel to R
=Req+RReq⋅R=Req′
=Req′+2R=Req+RReqR+2R
Req+RReqR+2R=Req
2R2+3RReq=Req2+RReq
Req2−2RReq−2R2=0
Req=22R±4R2+8R2
=22R±23R=(1±3)R
Req =(1+3)R
ρ Resistivity
r = a + Lb−a x
dR(x)=ρ⋅π[a+Lb−ax]2dx
R=πρ∫0L[a+Lb−ax]2dx
=πρ×abb−a=πρ⋅abL
ρAL0=2.75×10−8Ωm
αAL=.004/∘C
ρc0=5×10−5Ωm
αc=−0.0005/0C
RAL+RC=RAL0(1+αAL⋅ΔT)
+Rc0(1+α0⋅ΔT)
RAL+RC≡RAL∘+RC0
RALαAL⋅ΔT=−Rc0αc⋅ΔT.
αALρAL0LAL=−αcρc0⋅LC
Lμ/Lc≈227
R4∣∣R5⇒R45
R2,R3 and R45 are in series R2345
R6 and R8 in series = R68
R9∣∣R10 ⇒R9′
R9in series withR68.
R689′ is parallel to R7′
⇒R′
More than 1 battery in the circuit
Cells in series
Vc−Ir2+ε2−Ir1+ε1=Va
Va−Vc=(εε1+ε2)−Ir1+r2)
An equivalent emf ε1+ε2 and effective internal resistance
r1+r2