- **Example:**
- The surface tension of a soap solution is 0.02 N/m what amount of work is requred for produsing a soap bubble of radius 0.05m ?
- **Solution**
- The work lone in making a soap bubble = Surface Tension $\times$ Total Surface Area
- Surface Tension $\times$ (inner + outer) surface area
- =$0.03_{N/m} \times 2\times 4\pi(0.05_m)^2 $
- $= 1.884 \times 10^{-3} J$
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