Problem Solving Newtons Second Law L-8
Problem Solving Newton's Second Law
→ \rightarrow → → \rightarrow → Problem Solving Newton's Second Law → \rightarrow → Newton's Second Law → \rightarrow → Multiple Bodies
Problem Solving Newtons Second Law L-8
Newton's Second Law
→ \rightarrow → Problem Solving Newton's Second Law → \rightarrow → Newton's Second Law → \rightarrow → Multiple Bodies → \rightarrow → Multiple Bodies
Problem Solving Newtons Second Law L-8
Multiple Bodies
For example: hanging pulley
Top pulley may be fixed, the bottom pulley, may be moving.
We could have complex cases like this example.
Problem Solving Newton's Second Law → \rightarrow → Newton's Second Law → \rightarrow → Multiple Bodies → \rightarrow → Multiple Bodies → \rightarrow → Newton's 3rd Law
Problem Solving Newtons Second Law L-8
Multiple Bodies
In general the accelerations of bodies 1, 2 and 3 may not be equal.
You may have to find a relation between a 1 a_1 a 1 , a 2 a_2 a 2 & a 3 a_3 a 3 .
The free body diagrams of bodies 1, 2, and 3 separately.
Newton's Second Law → \rightarrow → Multiple Bodies → \rightarrow → Multiple Bodies → \rightarrow → Newton's 3rd Law → \rightarrow → Newton's Law for Rod
Problem Solving Newtons Second Law L-8
Newton's 3rd Law
Mutual forces applied by two bodies on each other are equal and opposite.
Multiple Bodies → \rightarrow → Multiple Bodies → \rightarrow → Newton's 3rd Law → \rightarrow → Newton's Law for Rod → \rightarrow → Newton's Law for Rod
Problem Solving Newtons Second Law L-8
Newton's Law for Rod
Multiple Bodies → \rightarrow → Newton's 3rd Law → \rightarrow → Newton's Law for Rod → \rightarrow → Newton's Law for Rod → \rightarrow → Friction
Problem Solving Newtons Second Law L-8
Newton's Law for Rod
F 1 ⃗ = F 2 ⃗ \vec{F_1}= \vec{F_2} F 1 = F 2
Case:1 Rod is in compression.
Case:2 Rod is in tension.
Newton's 3rd Law → \rightarrow → Newton's Law for Rod → \rightarrow → Newton's Law for Rod → \rightarrow → Friction → \rightarrow → Friction
Problem Solving Newtons Second Law L-8
Friction
No slip then friction f is an unknown force.
Newton's Law for Rod → \rightarrow → Newton's Law for Rod → \rightarrow → Friction → \rightarrow → Friction → \rightarrow → Friction
Problem Solving Newtons Second Law L-8
Friction
Impending slip, → \rightarrow → f=μ s N \mu_s N μ s N
Actual slip, → \rightarrow → f=μ k N \mu_k N μ k N
Friction ∝ \propto ∝ N
1) Assume no slip
When there is no movement acceleration of body is 0.
Find the value of f, from equation.
Σ F = 0 \Sigma F =0 Σ F = 0 .
No slip then friction f is an unknown force.
Newton's Law for Rod → \rightarrow → Friction → \rightarrow → Friction → \rightarrow → Friction → \rightarrow → Friction
Problem Solving Newtons Second Law L-8
Friction
Check:
is f <μ s N \mu_s N μ s N
f <μ k N \mu_k N μ k N
You will have to go to the y direction equations get the value of N.
f < μ s N = f<\mu_s N= f < μ s N = Assumption
Else resolve the problem assume slip, f = μ k N f=\mu_k N f = μ k N
Friction → \rightarrow → Friction → \rightarrow → Friction → \rightarrow → Friction → \rightarrow → Strings and pulleys
Problem Solving Newtons Second Law L-8
Friction
a → \rightarrow → Unknown, solve for 'a'
Check:
Is f <μ s N \mu_s N μ s N
f <μ k N \mu_k N μ k N
You will have to go to the y direction equations get the value of N.
f < μ s N = f<\mu_s N= f < μ s N = Assumption
Else resolve the problem assume slip, f = μ k N f=\mu_k N f = μ k N
Friction → \rightarrow → Friction → \rightarrow → Friction → \rightarrow → Strings and pulleys → \rightarrow → Free Body Diagram
Problem Solving Newtons Second Law L-8
Strings and pulleys
Pulley P 1 P_1 P 1 (fixed) on end of string, ties to mass m 1 m_1 m 1 , other end to mass m 2 m_2 m 2 .
Assumed that the pulleys are frictionless and light.
String is inextensible which means the length of the string is constant.
Find acceleration a 1 a_1 a 1 and acceleration a 2 a_2 a 2 of masses m 1 m_1 m 1 and m 2 m_2 m 2 .
Friction → \rightarrow → Friction → \rightarrow → Strings and pulleys → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram
Problem Solving Newtons Second Law L-8
Free Body Diagram
Friction → \rightarrow → Strings and pulleys → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram
Problem Solving Newtons Second Law L-8
Free Body Diagram
Strings and pulleys → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram
Problem Solving Newtons Second Law L-8
Free Body Diagram
T = m 2 ( g − a ) T =m_2(g-a) T = m 2 ( g − a )
T = m 1 a T =m_1 a T = m 1 a
m 1 a = m 2 ( g − a ) m_1 a =m_2(g-a) m 1 a = m 2 ( g − a )
( m 1 + m 2 ) a = m 2 g (m_1+m_2) a =m_2 g ( m 1 + m 2 ) a = m 2 g
a =m 2 g ( m 1 + m 2 ) \frac{m_2 g}{(m_1+m_2)} ( m 1 + m 2 ) m 2 g
Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Fixed Pulley
Problem Solving Newtons Second Law L-8
Free Body Diagram
If we add friction on the table for mass 1
m 2 g − T = m 2 a m_2 g-T =m_2 a m 2 g − T = m 2 a
N 1 = m 1 g N_1 =m_1 g N 1 = m 1 g
T − f = m 1 a T-f =m_1 a T − f = m 1 a
Where: f = μ k N 1 f = \mu_k N_1 f = μ k N 1
Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Fixed Pulley → \rightarrow → Free Body Diagram
Problem Solving Newtons Second Law L-8
Fixed Pulley
Pulley P 1 P_1 P 1 (Fixed)
At the two ends the magnitude of accelerations will be equal.
The tension will be the same throughout the string.
We assume frictionless contacts at the slope as well as at the table.
Draw the free body diagram of body 1.
Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Fixed Pulley → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram
Problem Solving Newtons Second Law L-8
Free Body Diagram
Free Body Diagram → \rightarrow → Fixed Pulley → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Pulley
Problem Solving Newtons Second Law L-8
Free Body Diagram
N 2 = m 2 g cos θ N_2=m_2 g \cos \theta N 2 = m 2 g cos θ
m 2 g sin θ − T = m 2 a m_2 g \sin \theta -T = m_2 a m 2 g sin θ − T = m 2 a
There are two unknowns T and a .
Fixed Pulley → \rightarrow → Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Pulley → \rightarrow → Pulley
Problem Solving Newtons Second Law L-8
Pulley
Free Body Diagram → \rightarrow → Free Body Diagram → \rightarrow → Pulley → \rightarrow → Pulley → \rightarrow → Movable Pulley
Problem Solving Newtons Second Law L-8
Pulley
Problems with multiple accelerating pulleys and string, set up equations relating accelerations of various blocks/ bodies connected by string.
Done by relating coordinate of moving blocks and pulleys to the length of the string which is fixed.
Using the length of the string is fixed, find the accelerations and relation between them.
Free Body Diagram → \rightarrow → Pulley → \rightarrow → Pulley → \rightarrow → Movable Pulley → \rightarrow → Movable Pulley
Problem Solving Newtons Second Law L-8
Movable Pulley
Pulley is not fixed.
m 1 m_1 m 1 , m 2 m_2 m 2 and F are given.
Frictionless contact
Coordinate of mass m 1 m_1 m 1 (reference should be a fixed )
x 1 x_1 x 1 = coordinate of m 1 m_1 m 1
x 2 x_2 x 2 = centre of pulley.
Pulley → \rightarrow → Pulley → \rightarrow → Movable Pulley → \rightarrow → Movable Pulley → \rightarrow → Movable Pulley
Problem Solving Newtons Second Law L-8
Movable Pulley
What is the length of the string going on the pulley
Express length in terms of x 1 x_1 x 1 and x 2 x_2 x 2 .
L = 2 x 2 − x 1 L=2 x_2-x_1 L = 2 x 2 − x 1
Differentiate with respect to time.
0 = 2 x ˙ 2 − x ˙ 1 0=2 \dot{x}_2-\dot{x}_1 0 = 2 x ˙ 2 − x ˙ 1
Differentiate 2 nd 2^{\text {nd }} 2 nd time
0 = 2 x ¨ 2 − x ¨ 1 0=2 \ddot{x}_2-\ddot{x}_1 0 = 2 x ¨ 2 − x ¨ 1
x 1 = 2 x ¨ 2 {x} _1=2 \ddot{x} _2 x 1 = 2 x ¨ 2
Pulley → \rightarrow → Movable Pulley → \rightarrow → Movable Pulley → \rightarrow → Movable Pulley → \rightarrow → Free Body Diagram
Problem Solving Newtons Second Law L-8
Movable Pulley
Movable Pulley → \rightarrow → Movable Pulley → \rightarrow → Movable Pulley → \rightarrow → Free Body Diagram → \rightarrow → Free body Diagram of the Pulley
Problem Solving Newtons Second Law L-8
Free Body Diagram
F − T 2 = m 2 a 2 F - T_2 = m_2a_2 F − T 2 = m 2 a 2
Free body diagram of body 1.
T 1 = m 1 a 1 T_1 = m_1a_1 T 1 = m 1 a 1
Movable Pulley → \rightarrow → Movable Pulley → \rightarrow → Free Body Diagram → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Free body Diagram of the Pulley
Problem Solving Newtons Second Law L-8
Free body Diagram of the Pulley
Movable Pulley → \rightarrow → Free Body Diagram → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley
Problem Solving Newtons Second Law L-8
Free body Diagram of the Pulley
T 1 = m 1 a 1 T_1=m_1 a_1 T 1 = m 1 a 1
F − T 2 = m 2 a 2 F-T_2=m_2 a_2 F − T 2 = m 2 a 2
a 1 = 2 a 2 a_1=2 a_2 a 1 = 2 a 2
2 T 1 = T 2 2T_1 = T_2 2 T 1 = T 2
T 1 = m 1 a 1 = 2 m 1 a 2 T_1=m_1 a_1=2 m_1 a_2 T 1 = m 1 a 1 = 2 m 1 a 2
F − 2 ( 2 m 1 a 2 ) = m 2 a 2 F-2 (2 m_1 a_2)=m_2 a_2 F − 2 ( 2 m 1 a 2 ) = m 2 a 2
F=( 4 m 1 + m 2 ) a 2 (4 m_1+m_2) a_2 ( 4 m 1 + m 2 ) a 2 ⟵ \longleftarrow ⟵ a 2 a_2 a 2 & a 1 a_1 a 1
Free Body Diagram → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley
Problem Solving Newtons Second Law L-8
Fixed and Movable Pulley
Find a 1 , a 2 , a 3 a_1, a_2, a_3 a 1 , a 2 , a 3 assume frictioless surface, pulleys light pulley. constant length String.
Free body Diagram of the Pulley → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Free body Diagram of the Pulley
Problem Solving Newtons Second Law L-8
Fixed and Movable Pulley
Draw free body diagram of bodies 2 and 3.
m 2 g − T 2 = m 2 a 2 m_{2} g-T_2=m_2 a_2 m 2 g − T 2 = m 2 a 2
m 2 g − T 2 = m 3 a 3 m_{2} g-T_2=m_3 a_3 m 2 g − T 2 = m 3 a 3
Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley
Problem Solving Newtons Second Law L-8
Free body Diagram of the Pulley
Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley
Problem Solving Newtons Second Law L-8
Fixed and Movable Pulley
a 1 , a 2 , a 3 a_1 , a_2 , a_3 a 1 , a 2 , a 3 , and T 2 T_2 T 2
We have four unknowns and we have three equations.
Find relation between accelerations
x ← \leftarrow ← Distance of mass 1 form right .
x 1 + x p = l 1 x_1 + x_p = l_1 x 1 + x p = l 1
Where: l 1 l_1 l 1 is length of the first string.
Fixed and Movable Pulley → \rightarrow → Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Thank You
Problem Solving Newtons Second Law L-8
Fixed and Movable Pulley
( x 2 − x p ) + ( x 3 − x p ) = l 2 (x_2-x_p)+(x_3-x_p)=l_2 ( x 2 − x p ) + ( x 3 − x p ) = l 2
( x 2 − x p ) + ( x 3 − x p ) = l 2 (x_2-x_p)+(x_3-x_p)=l_2 ( x 2 − x p ) + ( x 3 − x p ) = l 2
x 2 + x 3 − 2 x p = l 2 x_2+x_3-2 x_p=l_2 x 2 + x 3 − 2 x p = l 2
x 2 + x 3 − 2 ( l 1 − x 1 ) = l 2 x_2+x_3 -2(l_1 - x_1)=l_2 x 2 + x 3 − 2 ( l 1 − x 1 ) = l 2
x 2 + x 3 + 2 x 1 = l 2 + 2 l 1 x_2 + x_3 + 2 x_1 = l_2 + 2 l_1 x 2 + x 3 + 2 x 1 = l 2 + 2 l 1
l 2 + 2 l 1 l_2 + 2 l_1 l 2 + 2 l 1 = Consant
x ¨ 1 = − a 1 \ddot{x}_1 = -a_1 x ¨ 1 = − a 1
a 2 + a 3 − 2 a 1 = 0 a_2 + a_3 -2a_1 =0 a 2 + a 3 − 2 a 1 = 0
Free body Diagram of the Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Thank You → \rightarrow →
Problem Solving Newtons Second Law L-8
Thank You
Fixed and Movable Pulley → \rightarrow → Fixed and Movable Pulley → \rightarrow → Thank You → \rightarrow → → \rightarrow →
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Problem Solving Newtons Second Law L-8 Problem Solving Newton's Second Law $\rightarrow$ $\rightarrow$ Problem Solving Newton's Second Law $\rightarrow$ Newton's Second Law $\rightarrow$ Multiple Bodies