(y−y1)=m(x−x1)
x2+y2+2gx+2fy+c=0
x1+gy1+f×m=−1
m(y1+f)+(x1+g)=0
g=−x1−m(y1+f)
g2+f2−c
=(x1+g)2+(y1+f)2
c=g2+f2−(x1+g)2−(y1+f)2
x2+y2+2x(−x1−m(y1+f))+2fy+c=0
x2+y2+2x(−x1−my1)+f(2y−2mx)+g2+f2−(x1+g)2−(y1+f)2=0
x2+y2+2x(−x1−my1)+f(2y−2mx)−x12−y12−2gx1−2fy1=0.
substitute g=−x1−m(y1+f)
x2+y2+2x(−x1−my1)+f(2y−2mx)−x12−y12+2x1(x1+m(y1+f))−2fy1=0.
(x+g)2+(y−y1)2=(x1+g)2
x2+2gx+g2+(y−y1)2=x12+g2+2gx1
x2+(y−y1)2+2g(x−x1)−x12=0
(x−x1)2+2xx1−x12+(y−y1)2+2g(x−x1)−x12=0
(x−x1)2+(y−y1)2+2g(x−x1)+2xx1−2x12=0
(x−x1)2+(y−y1)2+(x−x1)(2g+2x1)=0
(x−x1)2+(y−y1)2+k(x−x1)=0
(x−x1)2+(y+f)2=(y1+f)2
(x−x1)2+(y−y1)2+k(y−y1)=0
x2+y2+2x(−x1−my1)+f(2y−2mx)−x12−y12+2x1(x1+m(y1+f))−2fy1=0
(x−x1)2+(y−y1)2+K[(y−y1)−m(x−x1)]=0
(x−x1)2+2xx1−x12+(y−y1)2+2yy1−y12−2xx1−2mxy1+2fy−2mfx−x12−y12+2x12+2mx1(y1+f)−2fy1=0
(x−x1)2+(y−y1)2+2y1(y−y1)−2y1m(x−x1)+2f(y−y1)−2mf(x−x1)=0
(x−x1)2+(y−y1)2+2y1((y−y1)−m(x−x1))+2f((y−y1)−m(x−x1))=0
(x−x1)2+(y−y1)2+2(y1+f)((y−y1)−m(x−x1))=0
x2+y2+2gx+2fy+c=0
slope of chord
=(x−x1)(y−y1)
∴(x−x1)(y−y1)(x1+g)(y1+f)=−1
(y−y1)(y1+f)+(x−x1)(x1+g)=0.
x2+y2+2gx+2fy+c=0
R=g2+f2−c
PO2=L2+R2
PO2=(x1+g)2+(y1+f)2
L=PO2−R2
=(x1+g)2+(y1+f)2−R2
L2=x12+2gx1+y12+2fy1+g2+f2−R2
S1=(x−x1)2+(y−y1)2−L2=0
S2=x2+y2+2gx+2fy+c=0
S1−S2=0
x2+y2+2gx+2fy+c−(x−x1)2
−(y−y1)2+L2=0
2xx1−x12+2yy1−y12+2gx+2fy+c+L2=0
i.e:
2x(g+x1)+2y(f+y1)−(x12+y12−L2−c)=0.
OM = h △T1MO∼△T1PO
Lx=Rh=R2+L2R
x=R2+L2RL,
h=R2+L2R2
T1T2=R2+L22RL
Area(PT1OT2)=LR
T2 Area (OT1T2)=hx
=(R2+L2)R3L
∴ Area (△PT1T2)
= Area (PT1OT2)− Area (OT1T2)
=LR−(R3L)/(R2+L2)=RL3/(R2+L2)
∠T1PT2=2tan−1(R/L)=tan−1(R/L)+tan−1(P/L)=tan−1[1−R2/L2(2R/L)]
S1=x2+y2+2gx+2fy+c=0
(x−x1)2+(y−y1)2=L2
S2=x2+y2−2xx1−2yy1+x12+y12−L2=0
S=S1+λS2=0(λ=−1)
x2+y2+2gx+2fy+c+λ(x2+y2−2xx1−2yy1+x12+y12−L2)=0
x12+y12+2gx1+2fy1+c+λ(x12+y12−2x12−2y12+x12+y12−L2)=0
⇒λ=L2(x12+y12+2gx1+2fy1+c)
=1