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By pyridinium chlorochromate(PCC)
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dissolve in PCC solvent
Lecture-4
By pyridinium chlorochromate(PCC)
CrO3 dissolve in HClTreatmentwithPy PCC →CH2Cl2 solvent
1o RCH2OHCu/300oC−H2RCHO
2o R2CHOH−H2Cu/300oCR2CO+H2↑
3o R3C−OH→R2C=CH2+H2O
R=>CH3
(Removal of 9−H2O)
(i) Chemical
(ii) Catalytic
Reaction
−H∣C∣−OH∣C∣−concH2SO4conc.H3PO4,Δ−C∣=C∣−+H2O
Elimination reaction- rearrangement (E1) →−∣C+−
Reactivity 3o>2o>1o alcohols
CH3CH2CH2CH2OHconcH2SO4ΔE1,−H2OCH3CH2CH=CH2+CH3CH=CH−CH3 (Major)
C6H5−CH3∣C−OH∣CH3−H2SO4−H2O,ΔC6H5−C∣CH3=CH2
Catalytic →Al2O3 at 350oC pass vapours of alcohol over alumina
Iodoform
CH3−C∣∣O− (alyl)
CH3−C∣∣O−R → Methyl Ketones
CH3−OH∣C∣H−R secondary alcohol →CH3−O∣∣C−R
CH3−OH∣C∣H−H primary alcohol →CH3−O∣∣C−H
CH3−C∣∣O−H only aldehyde
Compound + X2/alkali → halo form
Compound + Cl2→ chloroform (colorless)
Compound + Br2→ bromoform (pale yellow)
Compound + I2→ iodoform (pale yellow)
(i) Oxidation
(ii) Halogenation
(iii) Hydrolysis
CH3−OH∣C∣−
CH3−C∣∣O−R
CH3CH2OH+X2+2NaOH→CH3CHO+2NaX+2H2O
CH3CHO+3X2+3NaOH→CX3.CHO+3NaX+3H2
CX3.CHO+NaOH→CHX3(Haloform)+HCOONa
CH3−C∣∣O−R+3X2+3NaOH→CX3−C∣∣O−R+3NaX+3H2O
CX3−C∣∣O−R+NaOH→CHX3+R−C∣∣O−O−Na
(a) Distinguish ketone / alcohol CH3−C∣∣O−
(b) CHCl3,CHBr3,CHI3
CH3−C∣∣O−OHIodoform× yellow ppt.
CH3−C∣∣O−NH2→ ×
CH3−C∣∣O−OCH3→ ×
Acid & acid derivatives don’t give positive iodoform reaction
(I) From alkenes →
(a) aq. or alkaline KMnO4→
(b) OSO4
(c) Epoxide / Hydrolysis
(d) Hypohalous acid follow by hydrolysis
(II) From alkyl halides
(a) hydrolysis with carbonate solution
(3) From alkylens diamine Treatment with nitrous acid
(4) Reduction of various carbonyl compounds “electrolytic red”
(a) due to -O-H group
(b) due to R & OH group
(2) with acids - monoester & diester
(3) with acetic - anhydride acetylation
(4) With halogen acids
(a) HCl or HBr
(b) with HI/PI3
(5) with nitric acid
(6) With PCl5,PBr3
(7) with aldehydes & Ketones acetals and ketals cyclic compounds
(9) Dehydration → (a) heat (b) ZnCl2 anhydrous (c) H3PO4 (d) conc H2SO4
(a) 2CH2OHΔ500oC(CH2)2O(epoxide)+H2O
(b) 2CH2OHZnCl2Δ,−H2OH2C=CHOH(vinylalcohol)→H3C−CHO ( acetaldehyde)
(c) 2CH2OHH3PO4−H2OHOH2C−CH2−O−CH2−CH2OH (diethylene glycol)
(d) 2CH2OHconc.H2SO4−2H2O,Δ2(CH2−O−CH2) (dioxane)