Chemical kinetics Lecture-11
Temperature dependence of reaction rates
Reaction rates depend upon temperature
Arrhenius equation
k = A$e^{-Ea/RT} \cdots$ 1(a)
k = A exp ($\frac{-E_a}{RT}$) $\cdots$ 1(b)
Where-
A - Pre-exponential factor or frequency factor or arrhenius factor
$E_a$ - Activation energy arrhenius activation energy
k - rate constant
R - gas constant
Van’t Hoff equation
$(\frac{ā lnKc}{āT})_p=\frac{\Delta U^o}{RT^2}……(2)$
$K_c=\frac{k_1}{k_{-1}}$
$\frac{d ln^{k_1/k_{-1}}}{dt}=\frac{\Delta U^o}{RT^2}$
Van’t hoft argued$\rarr k_1$ and $k_{-1}$ will be influenced by 2 different
Energy factors : $E_1$ and $E_{-1}$
$\frac{d (ln k_1)}{dT}=\frac{E_1}{RT^2}$
$\frac{d (ln k_{-1})}{dT}=\frac{E_{-1}}{RT^2}$
$E_1 - E_2=\Delta U^o $
$\frac{d (lnk)} {dT}=\frac{E}{RT^2}$
ln k $\hspace{2mm}$ = $\hspace{2mm}$constant$-\frac{E}{RT}$
k = A$e^{-Ea/RT}$
Arrhenius importance
This is a general concept of how reactions occur
Inversion of cane sugar
Inversion was not brought about by a simple cane sugar molecule but a substance he mentioned as active cane sugar molecule
Rate of reaction
$\quad \quad \downarrow$ proportional
Reaction Coordinate
Relation between H and U
$H = U + PV$
$\Delta H=\Delta U + \Delta(PV)$
$\Delta H=\Delta U + P\Delta V + V\Delta P$
$\frac{d(lnK_c)}{dt};(\frac{\partial (InK_c)}{\partial T})_p$
at constant pressure, $\Delta P=0$
$\Delta H=\Delta U + P \Delta V$
For reactions in solids & solutions,$\Delta Vā0$
$\Delta H=\Delta U$
Gas-phase reactions
$\Delta H=\Delta U + P\Delta V$
Consider ideal gas
$PV = nRT$
at fixed $T,P$
$P\Delta V = \Delta nRT$
$\Delta H =\Delta U = \Delta nRT$
$\Delta n$ = Change in number of moles
if $\Delta n = 0, then \hspace{3mm}\Delta H=\Delta U$
Important point
A distribution of kinetic energies exist in the system
$\quad \quad \quad \quad \quad \downarrow$
Maxwell and boltzmann distribution curve
Total number of molecules is N
Fraction = $\frac{N_E}{N}$
$N_E$ is the number of molecules having kinetic energy E
Peak of distribution $\rarr$ most probable kinetic energy
Fraction of molecules vs kinetic energy curve
The distribution becomes broader
The peak of distribution shifts to higher value of kinetic Energy
The shaded portion which shows the fraction of molecules having energy more than Ea and area of shaded portion increases as the temperature is increased
Fraction of molecules having excess energy is energy in excess of Ea is given by $e^{-E_a/RT}$
$\quad \quad \downarrow$
Thank you