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Go for expression of the total pressure
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$P_{total}$ = $P_{CH_3CHO} + P_{CH_4} + P_{CO} $
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$P = [(n^0-\xi)+ \xi + \xi] \frac{R T}{V}$
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$p = (n^o + \xi) \frac{R T}{V}$
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$p = \frac{n^o R T}{V}+ \frac{\xi R T}{V}$
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$n^o$ was the initial number of moles
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$\frac{n^o R T}{V} \rightarrow$ initial pressure $P^o $