Chemical kinetics
Lecture-5
Chemical kinetics Lecture-5
Rate of reaction
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CH3CHO(g)→ CH4(g)+CO(g)
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nCH3CHOo 0 0
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nCH3CHOo−ξ ξ ξ
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Example-
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CH3CHO(g)→ CH4(g)+CO(g)
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The rate of this reaction can be followed by measuring the pressure in the system at constant volume and temperature
Chemical kinetics Lecture-5
Assume ideal gas behaviour of the gases
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nCH3CHO=nCH3CHOo+viξ
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nCH3CHO=nCH3CHOo − ξ
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nCH4=nCH4o+viξ
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nCH4=nCH4o+ξ
Chemical kinetics Lecture-5
Assume ideal gas behaviour of the gases
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nCH4=ξ [nCH4o=0]
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nCO=nCOo+vi ξ
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nCO=0 + ξ
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nCO =ξ
Chemical kinetics Lecture-5
Expression of the total pressure
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Initial number of moles
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nCH3CHOo=n0
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Total pressure =PCH3CHO+PCH4+PCO
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ideal gas PV=nRT
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PCH3CHO=(no−ξ) VRT
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PCH4 = ξ VRT
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PCO = ξ VRT
Chemical kinetics Lecture-5
Expression of the total pressure
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Go for expression of the total pressure
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Ptotal = PCH3CHO+PCH4+PCO
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P=[(n0−ξ)+ξ+ξ]VRT
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p=(no+ξ)VRT
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p=VnoRT+VξRT
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no was the initial number of moles
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VnoRT→ initial pressure Po
Chemical kinetics Lecture-5
Expression of the total pressure
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P=Po+VξRT
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dtdP=dtdPo+dtd[ξVRT]
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dtdP=VRTdtdξ
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dtdP=VRTdtdξ
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V1dtdξ=RT1dtdP
Chemical kinetics Lecture-5
Kinetic analysis of experimental data
Chemical kinetics Lecture-5
Kinetic reaction profile
Chemical kinetics Lecture-5
Instantaneous rate
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Bydrawing a catalyst a tangent at that instant or that time point,t1
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Take the slope of the tangent
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For products:r(inst)=dtd[P]
Chemical kinetics Lecture-5
Initial rate of reaction
Chemical kinetics Lecture-5
Initial rate of reaction
Chemical kinetics Lecture-5
Key points
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It is preferred to do the initial rate calculation based on product appearance
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Initial rate calculation has to be done very close to the starting point of the reaction → within 5% of the reaction
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Except chain reactions the initial rate line or tangent will be the one which is the steepest
Chemical kinetics Lecture-5
Dependence of reaction rate on concentration