Electrochemistry Lecture-2
Variation of conductivity and molar conductivity with concentration
Debye-Huckel-Onsager equation
$\Lambda_m = \Lambda^0_m-A\sqrt C$
The value of the constant ‘A’ for a given solvent and temperature depends on the type of electrolyte
$CH_3COOH \rightleftharpoons CH_3COO^- + H^+$
$\Lambda_m=K.V$
$\Lambda_m^o(CH_3COOH) = \Lambda_m^0(HCl) + \Lambda_m^o(CH_3COO^{-}Na^{+}) - \Lambda_m^o(NaCl)$
$\Lambda^o_m (HCl) = \lambda^o_{Cl^-} + \lambda^o_{H^+}$
$\lambda^o \quad (S cm^2 mol^{-1})$
$H^+ \quad 349.8$
$Li^+ \quad 38.6$
Electrochemistry
Reaction
$CH_3COO^-\quad 40.9$
$OH^- \quad 199.1$
$Cl^- \quad 76.4$
$\Lambda^o_m (HCl) = \lambda^o_{H^+} + \lambda^o_{Cl^-}$
$\lambda_+ = Fu_+$
$\lambda^o_+ = Fu_+^o$
$\Lambda_m^o(CH_3COOH) = \Lambda_m^o(HCl) +$ $\Lambda_m^o(CH_3COONa)-\Lambda_m^o(NaCl)$
Degree of dissociation of weak electcrolytes
$\lambda^{o} _{m} (HCl) = \lambda^{o} _{H^{+}} + \lambda^{o} _{Cl^{-}}$
$\alpha = \frac{\Lambda_m}{\Lambda_m^o}$
$HA \leftrightharpoons H^+ + A^-$
$c(1-\alpha)\quad c\alpha \quad c \alpha$
$Ka = \frac{c \alpha^2}{(1 - \alpha)} = \frac{C \Lambda m^2}{\Lambda_m^o(\Lambda_m^o - \Lambda m)}$
Molar conductance
$\Lambda_m = \frac{K}{C}$
$K \rightarrow Sm^{-1}$
$C \rightarrow mol/m^3$
$K \rightarrow Scm^{-1}$
$\Lambda_m \rightarrow Scm^2 mol^{-1}$
$C \rightarrow mol/cm^3$
$\Lambda_m = \frac{1000 K}{C}$
$m \rightarrow Scm^2 mol^{-1}$
$C \rightarrow$ molar Conductance
Equivalent conductivity = $(\Lambda_{eq})$ $(\Lambda)$
$\Lambda_m = Z \Lambda_{eq}$ $\quad Z = V_+ Z_+ = V_- Z_-$
Questions
Question Calculate $\Lambda^o_m$ for $CaCl_2$ or $MgSO_4$ using Standard data.
$\quad \lambda_+^o,\lambda_-^o$
Question Estimate the value of $\Lambda^o_m$ for CH₃COOH.
It $\Lambda^o_m$ for Nacl, HCl & Na Acetate is given
Question Estimation of dissociation Constant of weak electrolyte from Conductance data.
Question Why k decreases with dilution & white $\Lambda_m$ increases?
Question Why AC(alternating current) is used to measure conductance of electrolyte solution and why platinized Pt electrodes are used?
Electrochemical cell
Making use of Chemical energy to produce electrical energy
$Zn(s) + CuSO_4 → ZnSO_4 + Cu(s)$
1.1 v
$[Zn^{2+}]=[Cu^{2+}]= 1mol/dm³$
$Zn(s) + CuSO_4 → ZnSO_4 + Cu(s) \rightarrow$
Such a device is called a galvanic or a voltaic cell
Daniell cell
Cell reactions and representations
Half cell reactions
Reduction process
$Cu^{2+} + 2e \rightarrow Cu(s)$ $\quad \Delta G = -nFE$
Oxidation reaction
$Zn(s) \rightarrow Zn^{2+} + 2e$
Galvanic cell
Metal(1) | Electrolyte solution
Electrolyte (1) || Electrolyte (2)
$Zn\rightarrow Zn^{2+} + 2e$
$Zn^{2+} + 2e \rightarrow Zn =>\phi_{Zn^{2+}/Zn}$
$Cu^{2+} + 2e \rarr Cu =>\phi_{Cu^{2+}/Cu}$
$E^o_{cell} = \phi_R - \phi_L > 0 $(Reduction Scheme)
Standard reaction potential
Half cell Potential
$\phi ^o \quad \sim$ unity and conscentration activity
EMF= limit cell Potential
Current is 0 (Poggendorf compensation method)