<Success style= "margin-top:16rem;text-align:center;"><B>Solutions<br> Lecture-2</B></Success>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Colligative property</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p><strong>Relative lowering of vapour pressure</strong></p> </li> <li> <p>$ P_1=x_1 P_1^0 $</p> </li> <li> <p>$\Delta P=P_1^0-P_1=P_1^0-x_1 P_1^0 $</p> </li> <li> <p>$\Delta P=P_1^0\left(1-x_1\right)=P_1^0 X_2 $</p> </li> <li> <p>$\frac{\Delta P}{P_1^0}=x_2=\frac{n_2}{n_1+n_2}=\frac{P_1^0-P_1}{P_1^0} $</p> </li> <li> <p>$\frac{n_2}{n_1}=\frac{P_1^0-P_1}{P_1}=\frac{W_2 / M W_2}{W_1 / M W_1}$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> <span style="color:blue">Colligative property</span> $\rightarrow$ Problem $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>The vapour pressure of pure benzene at a certain temperature is 0.850 bar . A non - volatile , non - electrolyte solid weighing 0.5g is added to 39.0g of benzene (molar mass 78g/mol) . The vapour pressure of the solution then is 0.845bar . What is the molecular mass of the solid substance?</li> </ul> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-01.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p><strong>Solution</strong></p> </li> <li> <p>On putting all values we will get</p> </li> <li> <p>As $P_1^{0} = 0.850$</p> </li> <li> <p>$W_2$ = 0.5 g</p> </li> <li> <p>$W_1$ = 39g</p> </li> <li> <p>$MW_1$ = 12×6+6 = 78</p> </li> <li> <p>$P_1$ = 0.845</p> </li> </ul> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-01.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p><strong>Solution continued</strong></p> </li> <li> <p>$ P_1=X_1 P_1^0 $</p> </li> <li> <p>$\Delta P=P_1^0-P_1=P_1^0-x_1 P_1^0 $</p> </li> <li> <p>$\Delta P=P_1^0\left(1-x_1\right)=P_1^0 x_2 $</p> </li> <li> <p>$\frac{\Delta P}{P_1^0}=x_2=\frac{n_2}{n_1+n_2}=\frac{P_1^0-P_1}{P_1^0} $</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>$\frac{n_2}{n_1}$ $=\frac{P_1^0-P_1^2}{P_1}=\frac{W_2 / M W_2}{W_1 / M W_1}$</p> </li> <li> <p>$\frac{n_2}{n_1}$ $=\frac{5 \times 10^{-3}}{845}$</p> </li> <li> <p>$M_2=\frac{05 / \mathrm{m} \mathrm{w}_2}{39 / 78}$</p> </li> <li> <p>$M_2=169 g/mol$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Elevation in boiling point</B></primary></p> <hr> <main> <div style='float: left; width:65%;font-size:22px;text-align:left'> <ul> <li> <p>$A_L \leftrightarrows A_g$</p> </li> <li> <p>$P_1 = P^0_1 x$</p> </li> <li> <p>$P^0_1 = 1 atm$</p> </li> <li> <p>$\Delta P = P^0_1 x_2$</p> </li> <li> <p>$\Delta T \propto m$</p> </li> <li> <p>$\Delta T = K_b m$</p> </li> </ul> </div> <div style='float: right; width:35%;'> <img src="https://imagedelivery.net/YfdZ0yYuJi8R0IouXWrMsA/ad56cad3-c7b6-4e34-6833-2dbc7d601500/public" style='width:90%'> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Problem $\rightarrow$ <span style="color:blue">Elevation in boiling point</span> $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>18 g Glucose $C_6H_{12}O_6$ in 1 kg of water18 g of glucose , is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil (1.013 bar pressure) ? $K_b$ for water is 0.52 K kg$mol^{−1}$</li> </ul> <p><strong>Solution</strong></p> <ul> <li> <p>$K_b = 0.52$</p> </li> <li> <p>$\Delta T = K_b m$</p> </li> <li> <p>$m=\frac {n_2}{w_1} = \frac {18/180}{1} = 0.1M$</p> </li> <li> <p>$\Delta T = 0.52×{0.1} = 0.052$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>The boiling point of benzene is 353.23 K.When 1.80 g of a non-volatile solute was dissolved in 90 g benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute.($K_b$ for benzene is 2.53Kkg$mol^{−1}$)</li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p><strong>Solution</strong></p> </li> <li> <p>$T_b^0=353.23 \mathrm{K} $</p> </li> <li> <p>$W_2=1.80$</p> </li> <li> <p>$W_1=90$</p> </li> <li> <p>$T_b=354.11K$</p> </li> <li> <p>$K_b=2.53 \mathrm{KKg mol^{-1}}$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>$\Delta T=K_b m $</p> </li> <li> <p>$\Delta T=T_b^{0} - T_b$</p> </li> <li> <p>$\Delta T=0.88 K $</p> </li> <li> <p>$m = \frac{n_2}{W_1} =\frac{1.80 / \mathrm{MW}}{90 / 1000}$</p> </li> <li> <p>$0.88K = \frac{2.53 \times 1.80 \times 1000}{90\times MW} $</p> </li> <li> <p>$M W = 57.5$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Depression in freezing point</B></primary></p> <hr> <main> <div style='float: left; width:65%;font-size:22px;text-align:left'> <ul> <li> <p>$K_b = \frac { R\times M \times T_b^{2}}{1000 \times \Delta_{vap}H}$</p> </li> <li> <p>$K_f = \frac { R\times M \times T_f^{2}}{1000 \times \Delta_{fus}H}$</p> </li> </ul> </div> <div style='float: right; width:35%;'> <img src="https://imagedelivery.net/YfdZ0yYuJi8R0IouXWrMsA/5b897ac8-ab09-4706-5cc6-90333e81cb00/public" style='width:90%;'> <!----> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Problem $\rightarrow$ Elevation in boiling point $\rightarrow$ <span style="color:blue">Depression in freezing point</span> $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>45g of ethylene glycol is mixed with 600g of water. What is the freezing point of the solution ? kf = 1.86Kkg $mol^{−1}$</li> </ul> <p><strong>Solution</strong></p> <ul> <li> <p>$\Delta T_f = K_f m$</p> </li> <li> <p>$ 45 g \quad C_2H_6O_2\qquad \Delta T_f = 1.86\times m$</p> </li> <li> <p>$m = \frac{45/62}{0.6} = 1.2$</p> </li> <li> <p>$ \Delta T_f = 1.86\times 1.2 = 2.2K$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>1.00 g of a non electrolyte solute when dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. Find the molar mass of the solute</li> </ul> <p><strong>Solution</strong></p> <ul> <li> <p>$ \Delta T=0.4 $</p> </li> <li> <p>$ M_2=150 \mathrm{g} $</p> </li> <li> <p>$ M_1=50 \mathrm{g} $</p> </li> <li> <p>$ T_f=5.12 K kg/mol$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>$ \Delta T_f=K_f m $</p> </li> <li> <p>$ 0.4=5.12 \times \frac{1.0 / MW}{0.5} $</p> </li> <li> <p>$ M W=256$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>Vapour pressure of pure water at 298 K is 23.8 mm Hg. 50 g of urea $(NH_2CONH_2)$ is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering</li> </ul> <p><strong>Solution -</strong></p> <ul> <li> <p>$ P_1^0=23.8 \mathrm{~mm} \mathrm{Hg} $</p> </li> <li> <p>$ M_2=50$</p> </li> <li> <p>$ M_1=850 $</p> </li> </ul> </div> <div style='float: right; width:0%;'> <!----> <!----> <!----> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ <span style="color:blue">Problem</span> $\rightarrow$ Reaction </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Reaction</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p><strong>Solution continued</strong></p> </li> <li> <p>$ \Delta P=P_1^0 x_2$</p> </li> <li> <p>$ x_2=\frac{n_2}{n_1+n_2} $</p> </li> <li> <p>$\Delta P = 0.42$</p> </li> <li> <p>$ \frac{\Delta P}{P_1^0}=x_2$</p> </li> <li> <p>$ x_2=\frac{n_2}{n_1+n_2} $</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Problem $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ <span style="color:blue">Reaction</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Reaction</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>$ n_2=50 / 60 $</p> </li> <li> <p>$ n_1=850 / 18 $</p> </li> <li> <p>$ x_2=\frac{50 \times 18}{60 \times 850}$</p> </li> <li> <p>$\Delta P =23.8 \times \frac{50 \times 18}{60 \times 850} $</p> </li> <li> <p>$\Delta P = 0.42$</p> </li> <li> <p>$ \frac{\Delta P}{P_1^0}=x_2 = 0.42$</p> </li> </ul> </div> <div style='float: right; width:0%;'> <!----> <!----> <!----> <!----> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Problem $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ <span style="color:blue">Reaction</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>Boiling point of water at 750 mm Hg is 99.63°C. How much sucrose is to be added to 500 g of water such that it boils at 100°C. Molal elevation constant for water is 0.52 K kg$mol^{−1}$</li> </ul> <p><strong>Solution</strong></p> <ul> <li> <p>$ T^{o}_b=99.63^{\circ}C$</p> </li> <li> <p>$T_b=100^{\circ}C$</p> </li> <li> <p>$W_1=500g$</p> </li> <li> <p>$M_2 = 44 + 22 + 176 = 342$</p> </li> </ul> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-09.jpg"> <img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-9.1.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p><strong>Solution</strong></p> </li> <li> <p>$\Delta T = K_b m$</p> </li> <li> <p>$m$ = $\frac {moles \hspace{1mm} of \hspace{1mm} solute} {Weight \hspace{1mm} of \hspace{1mm} Solvent}$</p> </li> <li> <p>$m = \frac {W_2/342}{0.5}$</p> </li> <li> <p>$0.37 = 0.52 \times \frac{W_2}{342.5}$</p> </li> <li> <p>$W_2 = 121.7g$</p> </li> </ul> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-09.jpg"> <img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-9.1.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>Calculate the mass of a non - volatile solute (molar mass 40g$mol^{−1}$) which should be dissolved in 114g octane to reduce its vapour pressure to 80%</p> </li> <li> <p>$m_2=? , MW_2=40g/mol$</p> </li> <li> <p>$M_1=114g, C_8H{18}(96+18=114)$</p> </li> <li> <p>$n_2=\frac {m_2}{40}$</p> </li> <li> <p>$n_1=1$</p> </li> <li> <p>$P_1=0.8P^0_1$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>$P_1=x_1P^0_1$</p> </li> <li> <p>$x_1=\frac {0.8}{1}=\frac{n_1}{n_1+n_2}$</p> </li> <li> <p>$x_1=\frac{1}{1+\frac{m_2}{40}}$</p> </li> <li> <p>$\frac {0.8}{1-0.8}=\frac{1}{1+\frac{m_2}{40}-1}$</p> </li> <li> <p>$4=\frac{1}{\frac{m_2}{40}}$</p> </li> <li> <p>$m_2=\frac{40}{4}=10g$</p> </li> </ul> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-010.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate -</li> </ul> <p>(i) Molar mass of the solute</p> <p>(ii) Vapour pressure of water at 298 K</p> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-011.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li><strong>Solution</strong></li> </ul> <p>(1) 30g solute in 90g $H_2O$</p> <ul> <li>$P_1=2.8kpa$</li> </ul> <ul> <li> <p>$P_1=x_1P^0_1$</p> </li> <li> <p>$P_1=\frac{5}{5+\frac{30}{MW_2}}$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>$x_1=\frac{n_1}{n_1+n_2}=\frac{5}{5+\frac{30}{MW_2}}$</p> </li> <li> <p>$P_1=x_1P^0_1$</p> </li> <li> <p>$P_1=\frac{5}{5+\frac{30}{MW_2}\times P_1^{o}} = 2.8$……(i)</p> </li> </ul> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-011.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li><strong>Solution</strong></li> </ul> <p>(2) 30g solute in 108g $H_2O,P_1 = 2.9kpa$</p> <ul> <li> <p>$MW_2=?=\frac{30}{1.3}=23$</p> </li> <li> <p>$P^0_1=?$</p> </li> <li> <p>$2.9=\frac{6}{6+\frac{30}{mW_2}}P^0_1$…..(ii)</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li>on dividing equation (i) by (ii)</li> </ul> <ul> <li> <p>$\frac{2.8}{2.9}=\frac{5}{5+\frac{30}{M_2}×{6+\frac{30}{M_2}}}$</p> </li> <li> <p>$\frac{28}{29}=\frac{5(M_2+5)}{6(M_2+6)}$</p> </li> <li> <p>$\frac{28}{29}=\frac{(M_2+5)}{(M_2+6)}$</p> </li> </ul> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style="float:center;text-align:center;font-size:28px;"> <B>Solutions Lecture-2</B></Success></p> <p><primary style="float:center;text-align:center;font-size:24px;"> <B>Problem</B></primary></p> <hr> <main> <div style='float: left; width:100%;font-size:22px;text-align:left'> <ul> <li> <p>28($M_2$+6)=29($M_2$+5)</p> </li> <li> <p>28$M_2$+168=29$M_2$+145</p> </li> <li> <p>168-145=$M_2$</p> </li> <li> <p>$M_2$=23</p> </li> </ul> </div> <div style='float: right; width:0%;'> <p><img alt="image" src="/subject-images/iitpal/image/chemistry-class-12-unit-02-chapter-02-solutions-l-2_3-onpconfjy_c-011.jpg"></p> </div> </main> <hr> <footer style="font-size:18px;"> Colligative property $\rightarrow$ Elevation in boiling point $\rightarrow$ Depression in freezing point $\rightarrow$ Reaction $\rightarrow$ <span style="color:blue">Problem</span> </footer>

<p><Success style= "margin-top:16rem;text-align:center;"><B>Thank you</B></Success></p>