Solutions Lecture-1
Concept of solubility
$A \rightarrow B$
NaCl in Water
AgCl
NaCl & sugar ${\rightarrow}$ Water
Ionic $\quad$H-O $\quad$ H-bonding
Non-polar $\quad\quad$ Polar
Solute + solvent $\xleftrightharpoons [{dissolution}]{precipitation}$ solution
le chatelier’s pressure and temperature
Saturated solution
Exothermic & Endothermic reaction
According to le chatelier’s principle
$\Delta H<0$ $\rightarrow$ exothermic reaction move backward
$\Delta H>0$ endothermic reactionmove forward
$A_g$ ${\rightarrow}$ $A_l$ condensation
Vapour pressure of Liquid- Liquid solution
Raoult’s law:
$P_A \propto x_A$
$P_B \propto x_B$
$P_A$ = $P_A^0$ $x_A$ , $P_B$ = $P_B^0$ $x_B$
$P_T$ =$P_A$ + $P_B$
$\ x_A=1, \quad P_A=P_A^o $
$\ x_B= 1, \quad P_B=P_B^o $
$P_T=P^o_A x_A + P^o_B x_B$
$P_T=P^o_A x_A + P^o_B(1-x_A)$
$P_T=P^o_B + (P^o_A - P^o_B)x_A$
Example
$A=CH Cl_3$ , $P_A^{o}$= 200mmHg $\quad 119.5 \quad 0.213$
$B = CH_2 Cl_2$ ,$P_B^{o}$=415mmHg $\quad 85 g/ms \quad 0.470$
Calculate vapour pressure of the solution prepared 25.5g $CH Cl_3$ and 40g of $CH_2 Cl_2$
Solution
$P_A=x_A P_A^0$
$P_B=x_B P_B^0$
$x_A=\frac{n_A}{n_A+n_B}=\frac{0.213}{0.213+0.478}$
$x_B=1-x_A$
$x_A= \frac {n_A} {n_A + n_B} =\frac {0.213} {0.213+0.470}=0.312$
$x_B=1-x_A =1-0.312=0.688$
$P_A=x_A P^0_A$ = 0.312×200=62.4 mmHg
$P_B$ =0.688×415=285.5 mmHg
$P_T$= $P_A+ P_B$=347.9 mmHg
$PV=nRT$
$P_AV=n_ART$
$X_A=\frac {n_A} {n_A + n_B} = \frac {P_A} {P_A + P_B}$
$0.179= \frac {62.4} {347.9} = 0.179$
$X_B = 0.821$
$P_A^{o}$=450 mmHg
$P_A^{o}$=700 mmHg
$P_A=P_A^{o}X_A = 450X_A$
$P_B=P_A^{o}X_B = 700(1-X_A)$
$P_T=P_A+P_B$
$P_T=600 mmHg=450X_A+700(1-X_A)$
$600=450X_A+700-700X_A$
$600=700-250X_A$
$X_A=\frac {100} {250}=0.4$
$X_B= 1-0.4=0.6$
$P_A= 450\times 0.4=180$
$P_B= 700\times 0.6=420$
$X^V_A=\frac {P_A} {P_T}$
$=\frac {180} {600}=0.3$
$X^V_B=\frac {420} {600}=0.7$
Vapour pressure of solution of solid in liquid
$P_A=x_A P^0_A$
$P_B=x_B P^0_B=0$
$P^0_B=0$
Ideal Solution & Non-Ideal Solution
$\Delta_{mix} V=0$
$\Delta_{mix} H=0$
1 L of Solvent A + 2 L of Solvent B $\rightarrow$ 3 L of Solution
Negative deviation A-A & B-B interaction is stronger than A-B interaction
Positive deviation A-A & B-B interaction is weaker than A-B interaction
Azeotropes
Richer in more volatile component
Same concentration of liquid phase & vapour phase
Weaker interaction
Positive deviation
Minimum boiling
Negative deviation
Maximum boiling $68$%$HNO_3+H_2O$
Thank you