chemistry-class-11-unit-07-chapter-04-chemical-equillibrium-l-4-8-wpsy1h34m

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Change in pressure </primary>
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* Pressure can be changed by introducing inert gas

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<footer style = "font-size: 18px">Le chatelier's principle $\rightarrow$ Effect of increase in P $\rightarrow$ <span style = "color:blue"> Change in pressure </span> $\rightarrow$ Effect of increase in pressure $\rightarrow$ Effect of increase in pressure </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of increase in pressure </primary>
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- ${PCl}_5(g) \rightarrow {PCl}_3(g)+{Cl}_2(g)$
- $K_p=\frac{P_{PCl_3}\times P_{Cl_2}}{P_{PCl_5}}$
- $K_p=\frac{x_{PCl_3}\times P \times x_{Cl_2} \times P}{x_{PCl_5}\times P}$
- $K_p=\frac{\frac{n_{PCl_3}}{n_T}\times P \times {\frac{n_{Cl_2}}{n_T}}\times P}{n_{PCl_5/n_T}\times P}$
- $K_p=\frac{n_{PCl_3} \times n_{Cl_2}}{n_{PCl_5}}\times \frac{P}{n_T}$

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![image](https://temp-public-img-folder.s3.ap-south-1.amazonaws.com/sathee.prutor.images/subject-images/iitpal/image/chemistry-class-11-unit-07-chapter-04-chemical-equillibrium-l-4_8-wpsy1h34m-8.jpg)

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<footer style = "font-size: 18px">Effect of increase in P $\rightarrow$ Change in pressure $\rightarrow$ <span style = "color:blue"> Effect of increase in pressure </span> $\rightarrow$ Effect of increase in pressure $\rightarrow$ In a closed container (constant v) </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> In a closed container (constant v) </primary>
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* if inert gas is introduced,total pressure remains constant but volume changes
* $V_2>V_1$

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<footer style = "font-size: 18px">Effect of increase in pressure $\rightarrow$ Effect of increase in pressure $\rightarrow$ <span style = "color:blue"> In a closed container (constant v) </span> $\rightarrow$ In a closed container (constant v) $\rightarrow$ In a closed container (constant v) </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> In a closed container (constant v) </primary>
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- $\mathrm{PCl}_5(\mathrm{g}) \rightleftharpoons \mathrm{PCl}_3(\mathrm{g})+\mathrm{Cl}_2(\mathrm{g})$
- $K_p=\frac{P_{PCl_3}\times P_{Cl_2}}{P_{PCl_5}}$
- $K_p=\frac{\frac{n_{PCl_3}}{n_T}\times P \times {\frac{n_{Cl_2}}{n_T}}\times P}{n_{PCl_5/n_T}\times P}$
- $K_p=\frac{n_{PCl_3}\times n_{Cl_2}}{n_{PCl_5}}\times \frac{P}{n_T}$

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![image](https://temp-public-img-folder.s3.ap-south-1.amazonaws.com/sathee.prutor.images/subject-images/iitpal/image/chemistry-class-11-unit-07-chapter-04-chemical-equillibrium-l-4_8-wpsy1h34m-11.jpg)

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<footer style = "font-size: 18px">Effect of increase in pressure $\rightarrow$ In a closed container (constant v) $\rightarrow$ <span style = "color:blue"> In a closed container (constant v) </span> $\rightarrow$ In a closed container (constant v) $\rightarrow$ Effect of temperature on equilibrium </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of temperature on equilibrium </primary>
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- If reaction is exothermic
- $ \Delta H = negative $
- $ A+B \rightleftharpoons$ C + D + heat released
- If we increase the temperature, the reaction will shift to the direction where heat is absorbed
- Exothermic reactions are favoured at low temperature

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<footer style = "font-size: 18px">In a closed container (constant v) $\rightarrow$ Effect of temperature on equilibrium $\rightarrow$ <span style = "color:blue"> Effect of temperature on equilibrium </span> $\rightarrow$ Effect of temperature on equilibrium $\rightarrow$ Effect of temperature on $K_P$ </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of temperature on $K_p$ </primary>
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- The equation which governs the effect of temperature on $K_p$ is
- $\left(\frac{\partial \ln K_P}{\partial T}\right)_p$ $=\frac{\Delta H^{\circ}}{R T^2}$
- In endothermic reaction, $K_p$ increases with increases in temperature

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<footer style = "font-size: 18px">Effect of temperature on equilibrium $\rightarrow$ Effect of temperature on $K_P$ $\rightarrow$ <span style = "color:blue"> Effect of temperature on $K_p$ </span> $\rightarrow$ Effect of temperature on $K_p$ $\rightarrow$ Summary </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of temperature, pressure and volume </primary>
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- $H_2 (g)+Cl_2 (g)\rightleftharpoons2HCl+92 kJ$
- Δn = 2 - (1 + 1) = 0
- Increase or decrease in pressure  will not affect the reaction
- Only temperature will affect the reaction

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<footer style = "font-size: 18px">Effect of pressure $\rightarrow$ Effect of pressure $\rightarrow$ <span style = "color:blue"> Effect of temperature, pressure and volume </span> $\rightarrow$ Effect of temperature, pressure and volume $\rightarrow$ Effect of temperature, pressure and volume </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of temperature, pressure and volume </primary>
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- $H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$
- $\Delta H=+25\hspace{0.5mm}kJ$
- It is an endothermic reaction 
- Effect of pressure and volume
- $\Delta n=2-(1+1)=0$
- No effect of pressure and volume
- No effect of inert gas
- High temperature will increase the product

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<footer style = "font-size: 18px">Effect of pressure $\rightarrow$ Effect of temperature, pressure and volume $\rightarrow$ <span style = "color:blue"> Effect of temperature, pressure and volume </span> $\rightarrow$ Effect of temperature, pressure and volume $\rightarrow$ Effect of catalyst on the equilibrium </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of temperature, pressure and volume </primary>
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- $2NO_2 (g)\rightleftharpoons N_2O_4 (g) $
- $\Delta H=\text {negative}$
- $\Delta n=(1-1) = -1$
- Increase in the pressure, forward reaction will be favoured
- Increase in  the volume, reverse reaction will be favoured
- Increases the temperature, reverse reaction will be favoured

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<footer style = "font-size: 18px">Effect of temperature, pressure and volume $\rightarrow$ Effect of temperature, pressure and volume $\rightarrow$ <span style = "color:blue"> Effect of temperature, pressure and volume </span> $\rightarrow$ Effect of catalyst on the equilibrium $\rightarrow$ Effect of catalyst on the equilibrium </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of catalyst on the equilibrium </primary>
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* Effect of catalyst on the equilibrium remains constant

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<footer style = "font-size: 18px">Effect of temperature, pressure and volume $\rightarrow$ Effect of temperature, pressure and volume $\rightarrow$ <span style = "color:blue"> Effect of catalyst on the equilibrium </span> $\rightarrow$ Effect of catalyst on the equilibrium $\rightarrow$ Effect of catalyst on the equilibrium </footer>

### <Success style="font-size:25px"> Chemical Equilibrium L-4 </Success>
### <primary style="font-size:24px"> Effect of catalyst on the equilibrium </primary>
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- K = $\frac{k_f}{K_b}$ = $\frac{k_f^{'}}{K_b^{'}}$
- Ratio of $R_f$ and $R_b$ does not change

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<footer style = "font-size: 18px">Effect of catalyst on the equilibrium $\rightarrow$ Effect of catalyst on the equilibrium $\rightarrow$ <span style = "color:blue"> Effect of catalyst on the equilibrium </span> $\rightarrow$ Summary $\rightarrow$ Thank you </footer>