chemistry-class-11-unit-06-chapter-06-chemical-thermodynamics-l-6-8-lx0x7ifkzgg

### <Success style="font-size:25px"> Chemical Thermodynamics L-6 </Success>
### <primary style="font-size:24px"> Recap </primary>
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- Essential concepts and definitions
- Heat, work & energy, internal energy
- First Law of thermodynamics
- Calculation of work, heat in different process for an ideal gas
- Enthalpy and heat capacity
- Determination of $\Delta U$ and $\Delta H$
- Change in enthalpy in different processes / reactions
- Enthalpy of reaction
- Enthalpy of formation
- Enthalpy of phase transition
- Enthalpy of other processes / reactions

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![image](https://temp-public-img-folder.s3.ap-south-1.amazonaws.com/sathee.prutor.images/subject-images/iitpal/image/chemistry-class-11-unit-06-chapter-06-chemical-thermodynamics-l-6_8-lx0x7ifkzgg-023-0045.6.jpg)

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<footer style = "font-size: 18px"> $\rightarrow$ Thermodynamics $\rightarrow$ <span style = "color:blue"> Recap </span> $\rightarrow$ Enthalpy $\rightarrow$ Thermochemical equation </footer>

### <Success style="font-size:25px"> Chemical Thermodynamics L-6 </Success>
### <primary style="font-size:24px"> Problem </primary>
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- **Solution**

- $\Delta_c H^0_{C_6H_6} = - 3267 KJ mol^{-1}$
- $\Delta_f H^0_{CO_2}(g) = -393.5 KJ mol^{-1}$
- $\Delta_f H^0_{H_2O}(l) = -285.8 KJ mol^{-1}$
- $\Delta_f H^0_{C_6H_6}(g)= ?$
- $C_6H_6(l) + \frac{15}{2}O_2(g)\rightarrow 6CO_2(g) + 3H_2O(l)$
- $\Delta_c H^0_{c_6H_6}(l) = \Delta_rH^o$ = $∑a_i\Delta_f H^0_i(products) - ∑b_i\Delta_f H^0_i(reactants)$
- $-3267 = 6×(-393.5) + 3×(-285.8) - \Delta_f H^0_{c_6H_6}(l)-\frac{15}{2}\Delta_f H^0O{_2}(g) = 0$
- $\Delta_f C_6H_6 (l) = 49.8kJ mol^{-1}$

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<footer style = "font-size: 18px">Enthalpy $\rightarrow$ Problem $\rightarrow$ <span style = "color:blue"> Problem </span> $\rightarrow$ Thank you $\rightarrow$  </footer>