- **Problem** - The bp of propane , $\mathrm {n-}$ butane , $\mathrm {n-}$pentane , and $\mathrm {n-}$ hexane are respectively , $[-42.1^o\mathrm {c} , 0.5^o\mathrm {c},36.1^o\mathrm {c} \text { and } 68.7^o\mathrm {c}]$ explain this trend
| Molecule | $\text {Molecule mass}$ | $\text {BP}$ |
| -------- | -------- | -------- |
| $CH_3~ CH_2~ CH_3$| $44$ | $\downarrow$ |
| $n-C_4~ H_{10}$ | $58$ | $\downarrow$ |
| $n-C_5~ H_{12}$ | $72$ | $\downarrow$ |
| $n-C_6~ H_{14}$ | $86$ | $\downarrow$ |
- **Ans**
- London - dispersion forces
- Dipole - induced dipole
- Induced dipole - induced dipole
