There is no bond in Be2 example - Be2 molecule does not exist
Chemical Bonding Molecular Structure L-7
Molecular orbital diagram
B2 - 1s2 , 2s22p1
B.O = 22 = 1
B2 is not diamagnetic , experimentally B2 paramagnetic
C2 - it has 12 electrons
Chemical Bonding Molecular Structure L-7
Mixing of orbitals
Energies of orbitals should be similar
Symmetries of orbitals should be same
For Li2 to N2
Mixing of 2s with 2p orbital
The mixing of orbitals depend upon effective nuclear charge Z∗
Z∗ increases from left to right
Chemical Bonding Molecular Structure L-7
Mixing of orbitals
From Li to F , Z∗ increases , electrons present in different orbitals attracted towards nucleus in differnt ways as a result there is mixing of 2s and 2p orbitals
From O2 to F2 , Z∗ increases , the gap between 2s and 2p orbital is large so there is no mixing of 2s with 2p orbital
Chemical Bonding Molecular Structure L-7
Molecular orbital diagram
Chemical Bonding Molecular Structure L-7
Molecular orbital diagram
For B2−1s22s22p1
Bond order = 1
B2 is paramagnetic
For C2 - number of electrons are 12
Bond order = 24−0 = 2
C2 is diamagnetic
For N2 - number of electrons are 14
Bond order = 26−0 = 3
N≡N
Chemical Bonding Molecular Structure L-7
Molecular orbital diagram
For O2 - there are two unpaired electrons example - it is paramagnetic
According to valence bond theory , O2 is diamagnetic
So , this is the failure of valence bond theory
According to MOT , 1 electron is enough for bond formation
Chemical Bonding Molecular Structure L-7 Chemical bonding molecular structure $\rightarrow$ $\rightarrow$ Chemical bonding molecular structure $\rightarrow$ Molecular orbital diagram $\rightarrow$ Molecular orbital diagram