Answer.
Given d=1µm, therefore, r=0.5 µm, and H=2µm
Now, Volume of a (cylinder) single bacterium = πr2 h = 3.142x0.5 x 106x 0.5 x 106x 2 x 106 (1µm=106m) = 1.57 x 1023m³
From the previous example we calculated that for 1g protein 2.007 x1015 cells would be required.
Now, the volume of 2.007 x 1015 cells would be —– 2.007 x1015 x 1.57 x-18 m³
=3.15 x 10-3 m3 = 3.15 L