- In this lecture, we will discuss the concept of power of a lens and the combination of thin lenses in contact.
- Power of a lens is a measure of its ability to converge or diverge light rays.
- It is denoted by the symbol ‘P’ and is measured in diopters (D).
- Power of a lens can be positive or negative, depending on its nature.
Power of a Lens
- Power of a lens is defined as the reciprocal of its focal length in meters.
- Mathematically, it can be expressed as:
- P = 1 / f
- Where P is the power of the lens and f is the focal length in meters.
- A lens with a shorter focal length will have a greater power and vice versa.
- Power of a lens is positive for a converging lens and negative for a diverging lens.
Calculation of Power of a Lens
- If the focal length of a lens is given in centimeters, it needs to be converted to meters before calculating the power.
- Example:
- If the focal length of a lens is 10 cm, the power can be calculated as follows:
- P = 1 / (10/100) = 1 / 0.1 = 10 D
- When two thin lenses are placed in contact with each other, their power can be combined.
- The combined power of two lenses can be calculated by adding their individual powers.
- Mathematically, it can be expressed as:
- P_total = P_1 + P_2
- Where P_total is the combined power and P_1, P_2 are the powers of the individual lenses.
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Example 1:
- A lens with power 4 D is placed in contact with a lens of power -2 D. What is the combined power?
- Solution:
- P_total = 4 D + (-2 D) = 2 D
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Example 2:
- A converging lens with power 10 D is placed in contact with a diverging lens of power -6 D. What is the combined power?
- Solution:
- P_total = 10 D + (-6 D) = 4 D
- The power of a lens also affects the image formation by the lens.
- For a converging lens (positive power), the image is formed on the opposite side of the lens and is real and inverted.
- For a diverging lens (negative power), the image is formed on the same side of the lens and is virtual and upright.
- The focal length of two thin lenses in contact can also be calculated using their individual focal lengths.
- Mathematically, it can be expressed as:
- 1/f_total = 1/f_1 + 1/f_2
- Where f_total is the combined focal length and f_1, f_2 are the focal lengths of the individual lenses.
- Example:
- A lens with a focal length of 20 cm is placed in contact with a lens of focal length 50 cm. What is the combined focal length?
- Solution:
- 1/f_total = 1/20 + 1/50
- f_total = 1 / (1/20 + 1/50)
- f_total = 1 / (0.05 + 0.02)
- f_total = 1 / 0.07 = 14.29 cm
- The concept of combination of thin lenses in contact is applicable only when the separation between the lenses is negligible compared to their focal lengths.
- The lenses should also have a small aperture size to avoid significant abberations.
- In practice, additional considerations and correction techniques may be required for more complex lens combinations.
Summary
- Power of a lens is a measure of its ability to converge or diverge light rays.
- Power is positive for converging lenses and negative for diverging lenses.
- The power of two lenses in contact can be combined by adding their individual powers.
- The focal length of two lenses in contact can be calculated using their individual focal lengths.
Power of a Lens - Calculation
- The power of a lens can also be calculated using the lens formula.
- The lens formula relates the focal length (f), object distance (u), and image distance (v) of a lens.
- Mathematically, the lens formula is given by:
- 1/f = 1/v - 1/u
- Where f is the focal length, v is the image distance, and u is the object distance.
- By rearranging the lens formula, we can calculate the power of a lens using the formula:
Power of a Combination of Lenses
- When multiple lenses are combined, each with its own focal length and power, the combined power can be calculated using the formula:
- P_total = P_1 + P_2 + P_3 + …
- Where P_total is the combined power and P_1, P_2, P_3 are the powers of the individual lenses.
- This formula allows us to calculate the overall power of complex lens systems.
Example of Power of a Combination of Lenses
- Example:
- A system consists of three thin lenses with powers -4 D, +6 D, and -3 D. What is the combined power of the system?
- Solution:
- P_total = -4 D + 6 D + (-3 D) = -1 D
- When two thin lenses are placed in contact, the object distance and image distance are measured from the optical center of the combined system.
- The object distance (u) is measured from the object to the optical center of the combined system.
- The image distance (v) is measured from the image formed by the combined system to the optical center.
- The image formation by a combination of lenses in contact follows the same rules as individual lenses.
- For a converging lens, the image will be real and inverted if the object is placed beyond the focal point.
- For a diverging lens, the image will be virtual and upright, regardless of the object position.
Magnification of a Combination of Lenses
- The magnification of a combination of lenses can be calculated using the formula:
- M = M_1 * M_2 * M_3 * …
- Where M is the combined magnification and M_1, M_2, M_3 are the magnifications of the individual lenses.
- The magnification of a lens is given by:
- The overall magnification of the system depends on the magnifications of the individual lenses.
Example of Magnification of a Combination of Lenses
- Example:
- A system consists of a converging lens with magnification +2 and a diverging lens with magnification -3. What is the combined magnification of the system?
- Solution:
- M = M_1 * M_2 = 2 * (-3) = -6
Lens Equation
- The lens equation relates the object distance, image distance, and focal length of a lens.
- Mathematically, the lens equation is given by:
- 1/f = 1/v - 1/u
- Where f is the focal length, v is the image distance, and u is the object distance.
- The lens equation allows us to calculate one of the variables when the other two are known.
Example of Lens Equation
- Example:
- A converging lens with a focal length of 20 cm is used to form an image. The object distance is 30 cm. Find the image distance.
- Solution:
- 1/f = 1/v - 1/u
- 1/20 = 1/v - 1/30
- 1/v = 1/20 + 1/30
- 1/v = (3 + 2)/60
- 1/v = 5/60
- v = 60/5 = 12 cm
Summary
- The power of a lens can be calculated using the lens formula or by taking the reciprocal of the focal length.
- When multiple lenses are combined, their powers can be added to obtain the combined power of the system.
- The object distance and image distance for combined lenses are measured from the optical center of the system.
- The image formation and magnification in lens combinations follow the same rules as individual lenses.
- The lens equation allows us to calculate object distance, image distance, or focal length when the other two are known.
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