Potential Due To Different Charge Distributions

Calculation of potential due to a dipole at a general point in space

  • The potential due to a dipole is given by the equation:

    • V = k(q/r1 - q/r2)
    • where k = 1/4πε₀ and ε₀ is the permittivity of free space.
  • Here, q is the magnitude of the charge separated by a distance d and r1 and r2 are distances from the positive and negative charges to the point where potential is to be calculated.

  • Recall that the electric potential at a point is the amount of work done in bringing a unit positive charge from infinity to that point.

  • In this lecture, we will focus on calculating the potential at a general point due to a dipole.

Calculation of Potential Due to a Dipole

  • Consider a dipole with charges +q and -q, separated by a distance d.
  • Let’s assume that the positive charge is at the origin (0, 0, 0) and the negative charge is at (0, 0, d).
  • We want to calculate the potential at a general point P(x, y, z) due to this dipole.
  • To do this, we will calculate the potential due to the positive charge and the potential due to the negative charge separately, and then subtract them.

Calculating Potential Due to Positive Charge

  • To calculate the potential due to the positive charge at P(x, y, z), we use the equation:
    • V₁ = k(q/r₁)
    • where r₁ is the distance between the positive charge and the point P.
  • The distance r₁ can be calculated using the Pythagorean theorem:
    • r₁ = √(x² + y² + z²)
  • Plugging in the values, we get:
    • V₁ = k(q/√(x² + y² + z²))

Calculating Potential Due to Negative Charge

  • To calculate the potential due to the negative charge at P(x, y, z), we use the equation:
    • V₂ = k(-q/r₂)
    • where r₂ is the distance between the negative charge and the point P.
  • The distance r₂ can be calculated using the Pythagorean theorem:
    • r₂ = √(x² + y² + (d-z)²)
  • Plugging in the values, we get:
    • V₂ = k(-q/√(x² + y² + (d-z)²))

Total Potential Due to a Dipole

  • The total potential at point P(x, y, z) due to the dipole is given by:
    • V = V₁ - V₂
  • Substituting the values of V₁ and V₂:
    • V = k(q/√(x² + y² + z²)) - k(-q/√(x² + y² + (d-z)²))
  • Simplifying the equation further, we get:
    • V = kq[1/√(x² + y² + z²) + 1/√(x² + y² + (d-z)²)]

Example 1

  • Let’s consider a dipole with charges +2e and -2e, separated by a distance of 0.1 m.
  • We want to find the potential at a point P(0.2, 0.3, 0.4) m due to this dipole.
  • Using the formula derived earlier, we can calculate the potential as:
    • V = kq[1/√(x² + y² + z²) + 1/√(x² + y² + (d-z)²)]
  • Plugging in the values, we get:
    • V = (1/4πε₀)(2e)[1/√(0.2² + 0.3² + 0.4²) + 1/√(0.2² + 0.3² + (0.1-0.4)²)]

Calculation of Potential at Point P

  • Evaluating the expression further, we substitute the constant values:
    • V = (9 × 10^9 Nm²/C²)(2 × 1.6 × 10^-19 C)[1/√(0.2² + 0.3² + 0.4²) + 1/√(0.2² + 0.3² + (0.1-0.4)²)]
  • Performing the calculations, we get:
    • V ≈ 1.1 × 10^9 V
  • Hence, the potential at point P(0.2, 0.3, 0.4) due to the given dipole is approximately 1.1 × 10^9 volts.

Calculation of Potential Due to a Dipole - Summary

  • The potential at a general point due to a dipole can be calculated using the equation:
    • V = k(q/r1 - q/r2)
  • By considering the positive and negative charges separately, we can derive expressions for the potential at a general point due to the positive charge (V₁) and the negative charge (V₂).
  • The total potential at the point is obtained by subtracting the potential due to the negative charge from the potential due to the positive charge.
  • Calculations involve plugging the given values into the equations and simplifying the expressions accordingly.

Key Takeaways

  • The potential at a point due to a dipole is given by the equation V = k(q/r1 - q/r2), where k = 1/4πε₀.
  • The potential due to the positive charge can be calculated using V₁ = k(q/r₁), where r₁ is the distance between the positive charge and the point.
  • The potential due to the negative charge can be calculated using V₂ = k(-q/r₂), where r₂ is the distance between the negative charge and the point.
  • The total potential is obtained by subtracting V₂ from V₁.
  • Remember to plug in the given values and simplify the expressions to calculate the final potential at a general point.

Summary

  • In this lecture, we learned about calculating the potential at a general point due to a dipole.
  • We derived the formulas for potential due to the positive and negative charges separately, and then subtracted them to find the total potential at a point.
  • A practical example was solved to illustrate the calculation process.
  • Understanding and applying these concepts is essential for solving problems related to potential due to different charge distributions.

Electric Potential Due to a Uniformly Charged Sphere

  • A uniformly charged sphere with radius R and total charge Q can be used to calculate the electric potential at a point outside the sphere.
  • The equation for the electric potential due to a uniformly charged sphere at a point outside the sphere is given by:
    • V = (kQ) / (r)
  • where k = 1/4πε₀ and ε₀ is the permittivity of free space, Q is the charge of the sphere, and r is the distance between the center of the sphere and the point where the potential is to be calculated.
  • This equation assumes that the sphere is a solid, non-conducting sphere with a constant charge density.

Electric Potential Due to a Uniformly Charged Sphere (Contd.)

  • The electric potential inside the uniformly charged sphere is constant and equal to the potential at the surface of the sphere.
  • The equation for the electric potential inside the uniformly charged sphere is given by:
    • V = (kQ) / (R)
  • where R is the radius of the sphere.
  • The potential outside the sphere decreases inversely with the distance from the center of the sphere, while the potential inside the sphere remains constant.

Example: Electric Potential Due to a Uniformly Charged Sphere

  • Let’s consider a uniformly charged sphere with a radius of 0.5 m and a charge of 10 μC.
  • We want to find the electric potential at a point located 1 m away from the center of the sphere.
  • Using the formula for electric potential due to a uniformly charged sphere at a point outside the sphere, we have:
    • V = (kQ) / (r)
    • V = (9 × 10^9 Nm²/C²)(10 × 10^-6 C) / (1 m)
  • Calculating the value, we get:
    • V = 9 × 10^3 V
  • Hence, the electric potential at the given point is 9,000 volts.

Electric Potential Due to a Point Charge

  • The electric potential due to a point charge at a distance r from the charge can be calculated using the equation:
    • V = (kQ) / (r)
  • where k = 1/4πε₀, Q is the charge, and r is the distance between the point charge and the point where the potential is to be calculated.
  • The electric potential decreases with increasing distance from the point charge.
  • The electric potential at infinity is zero, as it represents the reference point with zero potential energy.

Electric Potential Due to Multiple Point Charges

  • The electric potential at a point due to multiple point charges is the algebraic sum of the individual potentials due to each charge.
  • To calculate the electric potential at a point due to multiple point charges, use the equation:
    • V = V₁ + V₂ + V₃ + …
  • where V₁, V₂, V₃, … are the individual potentials due to each point charge.
  • Make sure to include the signs of each potential, as potential is a scalar quantity.
  • This calculation applies to both point charges with the same and opposite signs.

Electric Potential Due to Multiple Point Charges (Contd.)

  • If the point charges have opposite signs and are close together, the potential near each charge is large compared to the potential far away.
  • In such cases, it is important to take into account the distance and the sign of each charge while calculating the potential.
  • Remember that the potential is a scalar quantity and can be either positive or negative depending on the sign of the charges and the observer’s reference point.
  • Electric potential is always positive for positive charges and negative for negative charges.

Example: Electric Potential Due to Multiple Point Charges

  • Let’s consider two point charges: +5 μC located at position A(0, 0, 0) and -2 μC located at position B(0, 0, 2 m).
  • We want to find the electric potential at a point P(1, 1, 1) m due to these charges.
  • First, calculate the electric potentials due to each point charge at point P using the equation V = (kQ) / (r).
  • Then, add the potentials together to find the total potential at point P.
  • Take into account the signs and distances of the charges while calculating the potentials.

Example: Electric Potential Due to Multiple Point Charges (Contd.)

  • The electric potential due to the +5 μC charge at point P(1, 1, 1) can be calculated as:
    • V₁ = (kQ₁) / (r₁)
    • V₁ = (9 × 10^9 Nm²/C²)(5 × 10^-6 C) / (√(1² + 1² + 1²) m)
  • The electric potential due to the -2 μC charge at point P(1, 1, 1) can be calculated as:
    • V₂ = (kQ₂) / (r₂)
    • V₂ = (9 × 10^9 Nm²/C²)(-2 × 10^-6 C) / (√(1² + 1² + (1-2)²) m)
  • Finally, add the two potentials V₁ and V₂ to find the total potential V at point P.

Example: Electric Potential Due to Multiple Point Charges (Contd.)

  • Evaluating the equations for V₁ and V₂ at point P(1, 1, 1) and performing the calculations, we get:
    • V₁ ≈ 4.1 × 10^5 V
    • V₂ ≈ -3.3 × 10^9 V
  • Adding the potentials V₁ and V₂, we get the total potential V:
    • V = V₁ + V₂
    • V ≈ 3.3 × 10^9 V
  • Hence, the electric potential at point P(1, 1, 1) due to the given point charges is approximately 3.3 × 10^9 volts.

Summary

  • The electric potential due to a uniformly charged sphere outside the sphere is given by the equation V = (kQ) / (r), where k = 1/4πε₀, Q is the charge, and r is the distance from the center of the sphere.
  • Inside the sphere, the potential is constant and equal to the potential at the surface of the sphere.
  • The electric potential due to a point charge is given by V = (kQ) / (r), where k = 1/4πε₀, Q is the charge, and r is the distance from the charge.
  • The electric potential due to multiple point charges is the algebraic sum of the individual potentials due to each charge.
  • Make sure to include the signs of each potential when calculating the total potential.

Potential Due To Different Charge Distributions

  • Calculation of potential due to a dipole at a general point in space
  1. The potential due to a dipole is given by the equation: V = k(q/r1 - q/r2), where k = 1/4πε₀ and ε₀ is the permittivity of free space.
  1. The potential due to the positive charge can be calculated using V₁ = k(q/r₁), where r₁ is the distance between the positive charge and the point.
  1. The potential due to the negative charge can be calculated using V₂ = k(-q/r₂), where r₂ is the distance between the negative charge and the point.
  1. The total potential is obtained by subtracting V₂ from V₁.
  1. Calculations involve plugging the given values into the equations and simplifying the expressions accordingly.

Electric Potential Due to a Uniformly Charged Sphere

  • The electric potential due to a uniformly charged sphere at a point outside the sphere is given by V = (kQ) / (r).
  • The electric potential inside the uniformly charged sphere is constant and equal to the potential at the surface of the sphere, given by V = (kQ) / (R).
  • The potential outside the sphere decreases inversely with the distance from the center of the sphere.
  • The potential at infinity is zero, representing the reference point with zero potential energy.
  • The potential at a point inside the sphere is constant and equal to the potential at the surface of the sphere.

Example: Electric Potential Due to a Uniformly Charged Sphere

  • Consider a uniformly charged sphere with radius R = 0.5 m and charge Q = 10 μC.
  • Calculate the electric potential at a point located 1 m away from the center of the sphere.
  • Use the formula V = (kQ) / (r), where k = 1/4πε₀ and r is the distance from the center of the sphere.
  • Plugging in the values, we get V = (9 × 10^9 Nm²/C²)(10 × 10^-6 C) / (1 m).
  • Solving the equation, the potential is found to be V ≈ 9 × 10^3 V.

Electric Potential Due to a Point Charge

  • The electric potential due to a point charge at a distance r from the charge is given by V = (kQ) / (r).
  • The potential decreases with increasing distance from the point charge.
  • The potential at infinity is zero, representing the reference point with zero potential energy.
  • The potential is positive for positive charges and negative for negative charges.
  • The difference in potential between two points represents the work done in moving a unit positive charge from one point to another.

Electric Potential Due to Multiple Point Charges

  • The electric potential at a point due to multiple point charges is the algebraic sum of the individual potentials due to each charge.
  • Calculate the electric potential at a point using the equation V = V₁ + V₂ + V₃ + …, where V₁, V₂, V₃, … are the individual potentials due to each point charge.
  • Consider the signs of each potential, as potential is a scalar quantity.
  • Positive potentials correspond to regions of high potential energy, while negative potentials correspond to regions of low potential energy.
  • Take into account the signs and distances of the charges while calculating the potentials.

Example: Electric Potential Due to Multiple Point Charges

  • Two point charges are present: +5 μC at position A(0, 0, 0) and -2 μC at position B(0, 0, 2 m).
  • Calculate the electric potential at a point P(1, 1, 1) m due to these charges.
  • Use the equation V = (kQ) / (r) to calculate the potentials due to each charge.
  • The potential due to the +5 μC charge can be calculated as V₁ = (9 × 10^9 Nm²/C²)(5 × 10^-6 C) / (√(1² + 1² + 1²) m).
  • The potential due to the -2 μC charge can be calculated as V₂ = (9 × 10^9 Nm²/C²)(-2 × 10^-6