Slide 1

  • Topic: Potential Due To Different Charge Distributions
  • Calculation of Potential due to a charged conducting sphere

Slide 2

  • Electric potential is defined as the amount of work done in bringing a unit positive charge from infinity to the point in question.
  • It is calculated using the formula: V = k(Q/r), where V is the electric potential, k is the electrostatic constant, Q is the charge, and r is the distance.

Slide 3

  • The potential due to a charged conducting sphere is given by: V = (kQ)/(2R), where V is the potential, Q is the charge on the sphere, R is the radius of the sphere, and k is the electrostatic constant.

Slide 4

  • The potential due to a charged conducting sphere is independent of the location of the point within or outside the sphere.
  • The potential is constant throughout the interior of the sphere, and it is equal to the potential on the surface of the sphere.

Slide 5

  • A conducting sphere with a positive charge will have a positive potential.
  • A conducting sphere with a negative charge will have a negative potential.

Slide 6

  • Example: Calculate the potential due to a uniformly charged conducting sphere with a charge of 6 μC and a radius of 2 cm.
  • Solution: Using the formula V = (kQ)/(2R),
    • V = (9 x 10^9 Nm^2/C^2)(6 x 10^-6 C) / (2 x 0.02 m)
    • V = 13.5 x 10^6 V

Slide 7

  • The electric field due to a charged conducting sphere is given by: E = (kQ)/(R^2), where E is the electric field, Q is the charge on the sphere, R is the radius of the sphere, and k is the electrostatic constant.

Slide 8

  • The electric field inside a conducting sphere is zero.
  • The electric field is non-zero only outside the sphere.

Slide 9

  • The potential due to a charged conducting shell is constant throughout the interior and exterior of the shell.
  • The potential inside the shell is equal to the potential on its surface.

Slide 10

  • The potential due to a charged conducting shell is given by: V = (kQ)/R, where V is the potential, Q is the charge on the shell, R is the radius of the shell, and k is the electrostatic constant.

Slide 11

  • An electric dipole is formed by two equal and opposite charges separated by a small distance.
  • The dipole moment (p) is defined as the product of the magnitude of one of the charges and the separation between the charges.
  • The equation for the dipole moment is given as: p = q * d, where p is the dipole moment, q is the magnitude of the charge, and d is the distance between the charges.

Slide 12

  • The potential due to an electric dipole at any point in space is given by: V = (kp * cosθ)/r^2, where V is the potential, kp is the electrostatic constant times the dipole moment, θ is the angle between the dipole axis and the line joining the point to the dipole, and r is the distance between the point and the dipole.

Slide 13

  • The electric field due to an electric dipole at any point in space is given by: E = (kp * sinθ)/(r^2), where E is the electric field, kp is the electrostatic constant times the dipole moment, θ is the angle between the dipole axis and the line joining the point to the dipole, and r is the distance between the point and the dipole.

Slide 14

  • The potential energy of a dipole in an electric field is given by the equation: U = -p * E, where U is the potential energy, p is the dipole moment, and E is the electric field.

Slide 15

  • The torque experienced by a dipole in an electric field is given by the equation: τ = p * E * sinθ, where τ is the torque, p is the dipole moment, E is the electric field, and θ is the angle between the dipole moment and the electric field direction.

Slide 16

  • When a dipole is placed in a uniform electric field, it experiences a net force and aligns itself with the field.
  • The net force experienced by a dipole in an electric field is given by the equation: F = p * dE/dx, where F is the net force, p is the dipole moment, dE/dx is the gradient of the electric field along the x-axis, and d is the separation between the charges.

Slide 17

  • Example: Calculate the electric potential at a point P located at a distance of 3 cm from an electric dipole of dipole moment 5 Cm.
  • Solution: Using the equation V = (kp * cosθ)/r^2,
    • V = (9 x 10^9 Nm^2/C^2)(5 Cm * cos(0))/(0.03 m)^2
    • V = 1.5 x 10^6 V

Slide 18

  • The electric field due to a uniformly charged infinite line of charge is given by: E = (2kλ)/(r), where E is the electric field, k is the electrostatic constant, λ is the linear charge density, and r is the distance from the line of charge.

Slide 19

  • The potential due to a uniformly charged infinite line of charge is given by: V = (2kλ)/(r), where V is the potential, k is the electrostatic constant, λ is the linear charge density, and r is the distance from the line of charge.

Slide 20

  • The electric field due to a uniformly charged infinite plane sheet of charge is given by: E = (σ)/(2ε₀), where E is the electric field, σ is the surface charge density, and ε₀ is the electric constant.

Slide 21

  • Summary of the topic so far:
    • Calculation of potential due to a charged conducting sphere
    • Potential is independent of location within or outside the sphere
    • Electric field is zero inside the sphere, non-zero outside

Slide 22

  • Potential due to a point charge: V = (kQ)/r
  • Potential due to a uniformly charged conducting sphere: V = (kQ)/(2R)
  • Potential due to a charged conducting shell: V = (kQ)/R

Slide 23

  • Electric field due to a charged conducting sphere: E = (kQ)/(R^2)
  • Electric field is zero inside the sphere and non-zero outside

Slide 24

  • Potential due to an electric dipole: V = (kp * cosθ)/r^2
  • Electric field due to an electric dipole: E = (kp * sinθ)/(r^2)

Slide 25

  • Electric field due to a uniformly charged infinite line of charge: E = (2kλ)/(r)
  • Potential due to a uniformly charged infinite line of charge: V = (2kλ)/(r)

Slide 26

  • Electric field due to a uniformly charged infinite plane sheet of charge: E = (σ)/(2ε₀)
  • Calculate the electric field at a point P located at a distance r from the sheet of charge using the formula

Slide 27

  • Summary of the formulas discussed in the lecture:
    • Potential due to a charged conducting sphere: V = (kQ)/(2R)
    • Potential due to a charged conducting shell: V = (kQ)/R
    • Electric field due to a charged conducting sphere: E = (kQ)/(R^2)
    • Electric field due to a charged conducting shell: E = (kQ)/(R^2) for points outside the shell

Slide 28

  • Summary of the formulas discussed in the lecture (contd.):
    • Potential due to an electric dipole: V = (kp * cosθ)/r^2
    • Electric field due to an electric dipole: E = (kp * sinθ)/(r^2)
    • Electric field due to a uniformly charged infinite line of charge: E = (2kλ)/(r)
    • Potential due to a uniformly charged infinite line of charge: V = (2kλ)/(r)

Slide 29

  • Summary of the formulas discussed in the lecture (contd.):
    • Electric field due to a uniformly charged infinite plane sheet of charge: E = (σ)/(2ε₀)
    • Calculation of potential and electric field at different points with relevant formulas

Slide 30

  • Important concepts covered in this lecture:
    • Calculation of potential and electric field for different charge distributions
    • Potential due to charged conducting sphere and shell
    • Electric field due to charged conducting sphere and shell, as well as a dipole, infinite line of charge, and infinite plane sheet of charge.