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Recap of the previous lecture
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Important concepts covered:
- Quantum mechanics
- Wave-particle duality
- Photon
- Photoelectric effect
- Atomic spectrums
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Today’s agenda
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Overview of the topics to be covered:
- Bohr’s model of the atom
- Atomic structure
- Radioactivity
- Nuclear reactions
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Bohr’s model of the atom
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Key points:
- Proposed by Niels Bohr in 1913
- Explains the stability of atoms and atomic spectra
- Electrons orbit the nucleus in discrete energy levels
- Emit or absorb energy when transitioning between levels
- Equations: E = -13.6/n^2 eV, v = R_H(1/n_1^2 - 1/n_2^2)
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Atomic structure
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Key points:
- Protons, neutrons, and electrons
- Protons and neutrons in the nucleus
- Electrons in energy levels around the nucleus
- Atomic number and mass number
- Isotopes and ions
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Radioactivity
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Key points:
- Discovered by Henri Becquerel in 1896
- Types of radioactive decay: alpha, beta, gamma
- Half-life and decay constant
- Equations: N(t) = N_0 e^(-λt), N(t) = N_0/2^(t/T), λ = 0.693/T
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Nuclear reactions
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Key points:
- Nuclear fission and fusion
- Fission: splitting of a heavy nucleus into lighter nuclei
- Fusion: combining of light nuclei to form a heavier nucleus
- Mass-energy equivalence (Einstein’s equation)
- Equations: E = mc^2, ΔE = Δm c^2
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Example: Bohr’s model of the atom
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Consider an electron transition from n = 3 to n = 2.
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Find the energy change and the frequency of the emitted photon.
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Solution:
- Energy change: ΔE = -13.6(1/2^2 - 1/3^2) eV
- Frequency: v = R_H(1/n_1^2 - 1/n_2^2)
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Example: Atomic structure
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Calculate the number of protons, neutrons, and electrons in ^56_26Fe.
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Solution:
- Number of protons: atomic number = 26
- Number of neutrons: mass number - atomic number = 56 - 26
- Number of electrons: same as number of protons
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Example: Radioactivity
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A sample of a radioactive substance has an initial activity of 640 Bq. The half-life of the substance is 10 days. Calculate the activity of the substance after 30 days.
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Solution:
- Decay constant: λ = 0.693 / T
- Activity after 30 days: N(t) = N_0 e^(-λt)
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Example: Nuclear reactions
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Calculate the energy released in the fusion of two deuterium nuclei.
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Given: mass of deuterium nucleus = 2.014 u
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Solution:
- Mass-energy equivalence: E = mc^2
- Energy released: ΔE = Δm c^2
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Recap of today’s lecture
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Key topics covered:
- Bohr’s model of the atom
- Atomic structure
- Radioactivity
- Nuclear reactions
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Important equations and examples
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Next lecture: Special theory of relativity