Equivalent Circuits - Understanding Series and Parallel Combination of Resistance

  • In electrical circuits, resistors can be connected in different ways - series and parallel.
  • Series combination: Resistors are connected end to end, forming a single path for current.
  • Parallel combination: Resistors are connected side by side, providing multiple paths for current.
  • Series combination increases the total resistance, while parallel combination decreases it.
  • It is crucial to understand and analyze equivalent circuits for solving complex problems.

Series Combination

  • In series combination, resistors are connected one after another.
  • The total resistance is the sum of individual resistances.
  • Formula: Rt = R1 + R2 + R3 + …
  • Example: Three resistors of values 2Ω, 3Ω, and 4Ω in series.
    • Rt = 2Ω + 3Ω + 4Ω = 9Ω
  • In series combination, the current remains the same throughout the circuit.
  • Voltage across each resistor is different and varies according to their respective resistances.

Series Combination - Voltage Distribution

  • In a series combination, the total voltage across the circuit is the sum of voltages across individual resistors.
  • Example: In a circuit with three resistors of 2Ω, 3Ω, and 4Ω in series, and a total voltage of 12V.
    • Vt = V1 + V2 + V3 = 12V
  • Voltage across each resistor can be obtained using Ohm’s law: V = I * R.
  • The current remains the same throughout the series combination.

Series Combination - Current Distribution

  • In a series combination, the same current flows through all the resistors.
  • The total current entering the series combination is equal to the current flowing through each resistor.
  • Example: In a circuit with three resistors of 2Ω, 3Ω, and 4Ω in series, and a total current of 3A.
    • It = I1 = I2 = I3 = 3A
  • The current remains constant throughout the series combination.

Parallel Combination

  • In a parallel combination, resistors are connected side by side.
  • The total resistance reduces as more paths are available for current to flow.
  • Formula: 1/Rt = 1/R1 + 1/R2 + 1/R3 + …
  • Example: Three resistors of values 2Ω, 3Ω, and 4Ω in parallel.
    • 1/Rt = 1/2Ω + 1/3Ω + 1/4Ω
    • 1/Rt = (6 + 4 + 3)/12
    • 1/Rt = 13/12
    • Rt = 12/13 Ω (~0.92 Ω)

Parallel Combination - Voltage Distribution

  • In a parallel combination, the voltage across each resistor is the same.
  • Example: In a circuit with three resistors of 2Ω, 3Ω, and 4Ω in parallel, and a total voltage of 10V.
    • V1 = V2 = V3 = 10V
  • The voltage remains constant across all the resistors in the parallel combination.

Parallel Combination - Current Distribution

  • In a parallel combination, the total current entering the combination splits among the resistors.
  • The sum of currents through each resistor adds up to the total current.
  • Example: In a circuit with three resistors of 2Ω, 3Ω, and 4Ω in parallel, and a total current of 5A.
    • It = I1 + I2 + I3 = 5A
  • The current splits among the parallel resistors based on their individual resistances.
  • The inverse of resistance determines the fraction of current flowing through each resistor.

Equivalent Resistance - Series Combination

  • In a series combination, the total resistance (Rt) is equal to the sum of individual resistances (R1, R2, R3…).
  • Example: In a circuit with three resistors of 4Ω, 5Ω, and 6Ω in series.
    • Rt = 4Ω + 5Ω + 6Ω
    • Rt = 15Ω
  • The equivalent resistance in series is always greater than the individual resistances.

Equivalent Resistance - Parallel Combination

  • In a parallel combination, the reciprocal of the total resistance (1/Rt) is equal to the sum of reciprocals of individual resistances (1/R1, 1/R2, 1/R3…).
  • Example: In a circuit with three resistors of 8Ω, 10Ω, and 12Ω in parallel.
    • 1/Rt = 1/8Ω + 1/10Ω + 1/12Ω
    • 1/Rt = (15 + 12 + 10)/120Ω
    • 1/Rt = 37/120Ω
    • Rt = 120/37Ω (~3.24Ω)
  1. Superposition of Voltage and Current Sources
  • In some circuits, both voltage and current sources may be present.
  • Superposition theorem allows us to handle such circuits by considering only one source at a time.
  • To apply superposition, we turn off all sources except one, and calculate the corresponding response.
  • We repeat this process for each source separately and then sum the responses.
  1. Superposition Example: Voltage Source
  • Consider a circuit with a voltage source of 10V and a current source of 2A.
  • To apply superposition, we turn off the current source and analyze the circuit with only the voltage source.
  • The voltage across each resistor is calculated using Ohm’s law: V = I * R.
  • The total voltage is obtained by summing up the individual voltages.
  1. Superposition Example: Current Source
  • In the same circuit, we turn off the voltage source and analyze the circuit with only the current source.
  • The current flowing through each resistor is calculated using Ohm’s law: I = V / R.
  • The total current is obtained by summing up the individual currents.
  1. Total Response from Superposition
  • After analyzing the circuit with each source separately, we obtain the individual voltages and currents.
  • The total voltage and current for the original circuit are obtained by summing up the corresponding values obtained from each source.
  1. Equivalent Resistance for Complex Circuits
  • For more complex circuits, finding the equivalent resistance becomes essential.
  • We can simplify complex circuits into an equivalent circuit with a single resistor.
  • The equivalent resistance is the resistance value that, when connected to a voltage source, produces the same current flow as the original circuit.
  1. Finding Equivalent Resistance - Series and Parallel Combination
  • In complex circuits, we can use the concepts of series and parallel combinations to find the equivalent resistance.
  • Identify regions of the circuit that can be simplified using series or parallel combinations.
  • Replace each identified region with the appropriate equivalent resistance.
  • Repeat until the entire circuit is reduced to a single equivalent resistance.
  1. Equivalent Resistance Example - Complex Circuit
  • Consider a complex circuit with resistors connected in series and parallel combinations.
  • Identify the different regions that can be simplified using series and parallel combinations.
  • Replace each region with the equivalent resistance, reducing the circuit step by step.
  1. Equivalent Resistance Example - Continued
  • Keep simplifying the circuit until it is reduced to a single equivalent resistance.
  • The equivalent resistance is found by replacing all the resistors with their equivalent values and computing the overall resistance.
  1. Equivalent Resistance Example - Final Equivalent Circuit
  • After simplifying the entire circuit, we are left with a single equivalent resistance and the voltage source.
  • The original complex circuit is reduced to a simple circuit that can be easily analyzed using the known laws and principles.
  1. Summary
  • Equivalent circuits allow us to simplify complex circuits by finding a single resistance.
  • Series and parallel combinations are used to determine the equivalent resistance.
  • Superposition theorem is utilized when both voltage and current sources are present.
  • Understanding and analyzing equivalent circuits is crucial in solving complex problems effectively.
  1. Properties of Resistors in Series
  • The current flowing through each resistor in series is the same.
  • The total resistance in a series combination is equal to the sum of individual resistances.
  • The voltage across each resistor in series is proportional to its resistance.
  • The total voltage across the series combination is the sum of individual voltages.
  1. Example of Resistors in Series
  • Consider three resistors connected in series: R1 = 4Ω, R2 = 6Ω, R3 = 8Ω.
  • The total resistance in series would be: Rt = R1 + R2 + R3 = 4Ω + 6Ω + 8Ω = 18Ω.
  • The current flowing through each resistor would be the same, let’s say I = 2A.
  • The voltage across each resistor in series can be calculated using Ohm’s law: V = I * R.
  • Example calculations: V1 = 2A * 4Ω = 8V, V2 = 2A * 6Ω = 12V, V3 = 2A * 8Ω = 16V.
  • The total voltage across the series combination would be: Vt = V1 + V2 + V3 = 8V + 12V + 16V = 36V.
  1. Properties of Resistors in Parallel
  • The voltage across each resistor in parallel is the same.
  • The total resistance in a parallel combination is less than the resistance of the smallest resistor.
  • The current splits between the parallel resistors based on their individual resistances.
  • The sum of the currents flowing through each resistor in parallel is equal to the total current.
  1. Example of Resistors in Parallel
  • Consider three resistors connected in parallel: R1 = 4Ω, R2 = 6Ω, R3 = 8Ω.
  • The total resistance in parallel can be calculated using the formula: 1/Rt = 1/R1 + 1/R2 + 1/R3.
  • Example calculations: 1/Rt = 1/4Ω + 1/6Ω + 1/8Ω = (6 + 4 + 3)/(24) = 13/24.
  • Inverse of the total resistance: Rt = 24/13Ω (~1.85Ω).
  • Let’s assume the total current flowing through the parallel combination is I = 3A.
  • The current flowing through each resistor can be calculated using Ohm’s law: I = V / R.
  • Example calculations: I1 = 3A * (1.85Ω/4Ω) = 1.3875A, I2 = 3A * (1.85Ω/6Ω) = 0.925A, I3 = 3A * (1.85Ω/8Ω) = 0.694A.
  • The sum of the currents flowing through each resistor: It = I1 + I2 + I3 = 1.3875A + 0.925A + 0.694A = 3A.
  1. Analysis of Complex Circuits
  • Complex circuits may contain a combination of series and parallel resistors.
  • The circuit can be simplified step by step using series and parallel combinations.
  • Identify regions of the circuit that can be simplified using these combinations.
  • Replace each region with the corresponding equivalent resistance.
  • Repeat the process until the entire circuit is simplified.
  1. Example Complex Circuit Analysis
  • Consider a complex circuit with multiple resistors connected in series and parallel.
  • Break down the circuit into simpler sections and simplify one section at a time.
  • Replace each section with its equivalent resistance and adjust the overall circuit accordingly.
  1. Equivalent Resistance - Further Analysis
  • It is possible for a complex circuit to have multiple equivalent resistances.
  • Identify sections of the circuit that can be simplified individually.
  • Calculate the equivalent resistance for each section and replace it in the circuit.
  1. Step-by-Step Simplification Example
  • Consider a complex circuit with resistors connected in various combinations.
  • Start by identifying simple series and parallel combinations.
  • Replace each combination with its equivalent resistance.
  • Gradually simplify the circuit until only one equivalent resistance remains.
  1. Final Equivalent Circuit Example
  • After simplifying the entire complex circuit, we end up with a single equivalent resistance.
  • The original complex circuit is now reduced to a simple circuit with minimum components.
  • This equivalent circuit can be easily analyzed using known formulas and principles.
  1. Importance of Equivalent Circuits
  • Equivalent circuits provide a way to simplify complex circuit configurations.
  • They allow us to focus on the important aspects of the circuit without getting overwhelmed.
  • The analysis of equivalent circuits helps in understanding the behavior and characteristics of electrical circuits.
  • Equivalent circuits are extensively used in various electrical engineering applications.