Topic: Drift Velocity and Resistance
- Introduction to drift velocity and resistance
- Relationship between current and drift velocity
- Calculation of resistance using drift velocity
- Overview of the problem on drift velocity
Introduction to Drift Velocity
- Definition: Drift velocity is the average velocity acquired by charge carriers in a conductor due to an electric field
- Drift motion: Electrons in a conductor experience random thermal motion, but they also move in a steady direction due to the electric field
- Relation to current: Drift velocity determines the flow of current in a conductor
Factors Affecting Drift Velocity
- Charge carrier mobility: Mobility is the ability of charged particles to move in response to an electric field
- Electric field strength: The strength of the electric field determines the acceleration of charge carriers
- Collisions with lattice ions: Charge carriers experience collisions with lattice ions, which decrease their drift velocity
Relationship between Current and Drift Velocity
- Current: Current is the rate of flow of charge
- Equation: Current (I) = Charge (Q) / Time (t)
- Relation with drift velocity: Current is directly proportional to drift velocity (v) and cross-sectional area (A)
Calculation of Resistance using Drift Velocity
- Resistance (R): Resistance is the measure of opposition to the flow of current in a conductor
- Ohm’s Law: Relationship between current, voltage, and resistance
- Equation: Resistance (R) = Voltage (V) / Current (I)
- Relation with drift velocity: Resistance is indirectly proportional to drift velocity
Problem on Drift Velocity - Statement
- Given parameters: Length of the conductor (l), area of cross-section (A), drift velocity (v), charge carriers (n)
- Finding: Calculate the drift velocity and resistance of a conductor
Problem on Drift Velocity - Solution (Step 1)
- Known values: Length of the conductor (l) = 10 m, area of cross-section (A) = 2 cm^2, charge carriers (n) = 10^28/m^3
- Formula: Drift velocity (v) = (Current / (n * A * q))
- Substituting the given values, we get v = (I / (10^28 * 2 * 10^-4 * q))
Problem on Drift Velocity - Solution (Step 2)
- Finding the current: The current is not given in the problem statement. Let’s assume the current value to be 5A.
- Substituting the value of current (5A) in the equation for drift velocity, we get v = (5 / (10^28 * 2 * 10^-4 * q))
Problem on Drift Velocity - Solution (Step 3)
- Charge of an electron: The charge of an electron (q) is -1.6 x 10^-19 C
- Substituting the value of q in the equation for drift velocity, we get v = (5 / (10^28 * 2 * 10^-4 * q))
- Calculating the drift velocity: Solve the equation to find the value of drift velocity (v)
Problem on Drift Velocity - Solution (Step 4)
- Calculating the resistance: Resistance (R) = Voltage (V) / Current (I)
- Assume the voltage to be 10V in the problem statement
- Substituting the values of voltage (10V) and current (5A), we get R = (10 / 5)
Drift velocity and resistance - Problem on Drift Velocity
- Given parameters: Length of the conductor (l), area of cross-section (A), drift velocity (v), charge carriers (n)
- Finding: Calculate the drift velocity and resistance of a conductor
Problem on Drift Velocity - Solution (Step 1)
- Known values: Length of the conductor (l) = 10 m, area of cross-section (A) = $2 cm^2$, charge carriers (n) = $10^28/m^3$
- Formula: Drift velocity (v) = $\frac{I}{nAq}$
- Substituting the given values, we get $v = \frac{I}{10^28 \times 2 \times 10^{-4} \times q}$
Problem on Drift Velocity - Solution (Step 2)
- Finding the current: The current is not given in the problem statement. Let’s assume the current value to be 5A.
- Substituting the value of current (5A) in the equation for drift velocity, we get $v = \frac{5}{10^28 \times 2 \times 10^{-4} \times q}$
Problem on Drift Velocity - Solution (Step 3)
- Charge of an electron: The charge of an electron (q) is -1.6 x $10^{-19}$ C
- Substituting the value of q in the equation for drift velocity, we get $v = \frac{5}{10^28 \times 2 \times 10^{-4} \times q}$
- Calculating the drift velocity: Solve the equation to find the value of drift velocity (v)
Problem on Drift Velocity - Solution (Step 4)
- Calculating the resistance: Resistance (R) = Voltage (V) / Current (I)
- Assume the voltage to be 10V in the problem statement
- Substituting the values of voltage (10V) and current (5A), we get $R = \frac{10}{5}$
Resistance and Ohm’s Law
- Ohm’s Law: States that the current passing through a conductor is directly proportional to the voltage applied across it, provided the temperature and other physical conditions remain constant.
- Mathematical expression: $V = IR$, where V is the voltage, I is the current, and R is the resistance.
- Inversely proportional relationship: Resistance is inversely proportional to current for a given voltage.
Factors Affecting Resistance
- Length of the conductor: Longer the conductor, higher the resistance
- Area of cross-section: Larger the cross-sectional area, lower the resistance
- Temperature: As temperature increases, resistance also increases
- Resistivity: Property of materials determining their resistance (represented by the symbol ‘rho’)
Resistivity and Conductivity
- Resistivity ($\rho$): Intrinsic property of a material that determines its resistance to the flow of electric current
- Conductivity ($\sigma$): Reciprocal of resistivity ($\sigma = \frac{1}{\rho}$)
- Units: Resistivity is typically measured in ohm-meter (Ω∙m) and conductivity is measured in siemens per meter (S/m)
Resistivity and Temperature
- Temperature coefficient of resistivity ($\alpha$): Represents the change in resistivity per degree Celsius change in temperature
- Positive temperature coefficient: Most metals have a positive temperature coefficient, meaning their resistivity increases with temperature
- Negative temperature coefficient: Some materials, like superconductors and semiconductors, have a negative temperature coefficient, meaning their resistivity decreases with temperature
Examples of Materials with Different Resistivities
- Silver: Lowest resistivity among commonly used materials (1.59 x $10^{-8}$ Ω∙m)
- Copper: High conductivity and low resistivity (1.68 x $10^{-8}$ Ω∙m)
- Aluminum: Lower conductivity and higher resistivity compared to copper (2.82 x $10^{-8}$ Ω∙m)
- Nichrome: Alloy used in heating elements due to its high resistivity (1.10 x $10^{-6}$ Ω∙m)
- Carbon: Carbon resistors have resistivity ranging from 3 x $10^{-3}$ to 9 x $10^{5}$ Ω∙m
Resistors and Ohmic Devices
- Resistors: Passive electronic components that limit the flow of electric current
- Ohmic devices: Devices that follow Ohm’s Law and have a linear current-voltage relationship
- Examples: Carbon resistors, wire wound resistors, and various electronic components
Factors Affecting Resistance of a Resistor
- Resistivity of the material: Different materials have different resistivities, affecting the resistance of a resistor
- Length and thickness of the resistor: Longer resistors offer more opposition to current flow, while thicker resistors offer less opposition
- Temperature: Resistance of some resistors changes with temperature due to their temperature coefficient of resistance
- Power rating: Power ratings determine the maximum power the resistor can dissipate without damage
Calculation of Resistance
- Resistors in series: Total resistance (Rt) is the sum of individual resistances (R1, R2, R3, …)
- Equation: Rt = R1 + R2 + R3 + …
- Resistors in parallel: Reciprocal of the total resistance (1/Rt) is the sum of reciprocals of individual resistances (1/R1 + 1/R2 + 1/R3 + …)
- Equation: Rt = (1/R1 + 1/R2 + 1/R3 + …)^(-1)
Capacitors
- Capacitor: Passive electronic component that stores and releases electrical energy in an electric field
- Construction: Consists of two conductive plates separated by an insulating material (dielectric)
- Units: Capacitance is measured in farads (F), where 1 farad = 1 coulomb/volt
Capacitance
- Capacitance (C): Property of a capacitor that determines the amount of charge it can store per unit voltage
- Equation: C = Q/V, where Q is the charge stored and V is the voltage across the capacitor
- Factors affecting capacitance: Area of the plates, distance between the plates, and the type of dielectric used
Series and Parallel Capacitors
- Capacitors in series: Total capacitance (Ct) is the reciprocal of the sum of reciprocals of individual capacitances (1/Ct = 1/C1 + 1/C2 + 1/C3 + …)
- Capacitors in parallel: Total capacitance (Ct) is the sum of individual capacitances (C1 + C2 + C3 + …)
Inductors
- Inductor: Passive electronic component that stores energy in a magnetic field when current flows through it
- Construction: Consists of a coil of wire wound around a core made of ferromagnetic material
- Units: Inductance is measured in henries (H), where 1 henry = 1 volt-second/ampere
Inductance
- Inductance (L): Property of an inductor that determines the amount of magnetic field generated for a given current
- Equation: V = L(di/dt), where V is the voltage across the inductor and (di/dt) represents the rate of change of current
- Factors affecting inductance: Number of turns, cross-sectional area, length of the wire, and the type of core material used
Series and Parallel Inductors
- Inductors in series: Total inductance (Lt) is the sum of individual inductances (L1 + L2 + L3 + …)
- Inductors in parallel: Total inductance (Lt) is the reciprocal of the sum of reciprocals of individual inductances (1/Lt = 1/L1 + 1/L2 + 1/L3 + …)
Summary
- Drift velocity is the average velocity of charge carriers in a conductor due to an electric field
- Resistance is the opposition to the flow of current in a conductor
- Ohm’s Law relates voltage, current, and resistance (V = IR)
- Resistivity and conductivity are properties of materials that affect their resistance
- Capacitors store electrical energy in an electric field, while inductors store energy in a magnetic field