Slide 1
Given: l = 2 m, A = πr^2, r = 0.5 x 10^-3 m, ρ = 1.68 x 10^-8 Ω.m
R = (1.68 x 10^-8 Ω.m) x (2 m) / (π x (0.5 x 10^-3 m)^2) Slide 10
Evaluating the expression, we find:
R = (1.68 x 10^-8 Ω.m) x (2 m) / (π x (0.5 x 10^-3 m)^2)
R = 0.034 Ω (approximately)
Thus, the resistance of the copper wire is approximately 0.034 Ω. Slide 11
Evaluating the expression, we find:
Thus, the light bulb consumes 100 watts of power. Slide 24