Let C₁, C₂, C₃, …, Cn be the individual capacitances of the capacitors connected in parallel.
The total charge Q stored in the parallel combination is the sum of the charges on each capacitor, Q = Q₁ + Q₂ + Q₃ + … + Qn.
Using the equation Q = CV, where C is the capacitance and V is the potential difference,
Q₁ = C₁V, Q₂ = C₂V, Q₃ = C₃V, …, Qn = CnV.
Substituting the values of charges in the total charge equation, we get Q = C₁V + C₂V + C₃V + … + CnV.
Factoring out V, we get Q = V(C₁ + C₂ + C₃ + … + Cn).
The total capacitance C of the parallel combination is given by C = (C₁ + C₂ + C₃ + … + Cn).
Therefore, C = Q/V.
Combining the equations, we get C = (C₁ + C₂ + C₃ + … + Cn) = C₁ + C₂ + C₃ + … + Cn.
Hence, the total capacitance C of capacitors connected in parallel is equal to the sum of the individual capacitances C₁, C₂, C₃, …, Cn.
________ | | C₁ C₂ | | --
Difference between series and parallel combination of capacitors: Series Combination:
Parallel Combination: