title: Vectors - Problems - Condition for Obtuse Angle Between Vectors
Vectors - Problems - Condition for Obtuse Angle Between Vectors
Problem
Find the condition for an obtuse angle between two vectors a and b.
- a = (a₁, a₂, a₃)
- b = (b₁, b₂, b₃)
Solution
- The angle between two vectors a and b can be found using the dot product formula:
- a · b = |a| |b| cos θ, where θ is the angle between a and b
- To find the condition for an obtuse angle, we need to consider the sign of cos θ.
- Cosine of an obtuse angle is negative.
- Therefore, the condition for an obtuse angle between two vectors is:
Example
Find the condition for an obtuse angle between the vectors a = (1, -2, 3) and b = (4, 5, -6).
Solution
- Dot product of a and b = a · b = (1)(4) + (-2)(5) + (3)(-6) = 4 - 10 - 18 = -24
- The condition for an obtuse angle between a and b is a · b < 0.
Equation
The condition for an obtuse angle between two vectors a and b can be written as:
a · b < 0
Summary
- The condition for an obtuse angle between two vectors a and b is a · b < 0.
- This condition can be obtained by using the dot product formula.
- An obtuse angle has a negative cosine value.
- Hence, the dot product of the vectors must be negative for an obtuse angle.
End of Slides
title: Vectors - Problems - Determining Collinearity of Vectors
Vectors - Problems - Determining Collinearity of Vectors
Problem
Given three vectors a, b, and c, determine whether they are collinear.
- a = (a₁, a₂, a₃)
- b = (b₁, b₂, b₃)
- c = (c₁, c₂, c₃)
Solution
- Three vectors are collinear if they are scalar multiples of each other.
- To check if vectors a, b, and c are collinear, we need to verify the following condition:
- Here, k is a scalar value.
Example
Given three vectors a = (2, -1, 3), b = (4, -2, 6), and c = (-6, 3, -9), determine whether they are collinear.
Solution
- The vectors a, b, and c are collinear if they satisfy the condition: a = k b = k c
- Let’s find the value of k by comparing the corresponding components of the vectors.
- a₁ = 2, b₁ = 4, c₁ = -6 => 2 = k(4) = k(-6), k = 1/2 = -1/3
- a₂ = -1, b₂ = -2, c₂ = 3 => -1 = k(-2) = k(3), k = 1/2 = -1/3
- a₃ = 3, b₃ = 6, c₃ = -9 => 3 = k(6) = k(-9), k = 1/2 = -1/3
- The values of k obtained for all three components are the same. Hence, the vectors a, b, and c are collinear.
Equation
The condition for collinearity of three vectors a, b, and c can be written as:
a = k b = k c
Summary
- Three vectors are collinear if they are scalar multiples of each other.
- To check for collinearity, compare the components of the vectors and find a common scalar value.
- If the vectors satisfy the condition a = k b = k c, they are collinear.
- Collinear vectors lie on the same line or are parallel to each other.
End of Slides
title: Vectors - Problems - Condition for Obtuse Angle Between Vectors
Problem
Find the condition for an obtuse angle between two vectors a and b.
- a = (a₁, a₂, a₃)
- b = (b₁, b₂, b₃)
Solution
- The angle between two vectors a and b can be found using the dot product formula:
- a · b = |a| |b| cos θ, where θ is the angle between a and b
- To find the condition for an obtuse angle, we need to consider the sign of cos θ.
- Cosine of an obtuse angle is negative.
- Therefore, the condition for an obtuse angle between two vectors is:
Example
Find the condition for an obtuse angle between the vectors a = (1, -2, 3) and b = (4, 5, -6).
Solution
- Dot product of a and b = a · b = (1)(4) + (-2)(5) + (3)(-6) = 4 - 10 - 18 = -24
- The condition for an obtuse angle between a and b is a · b < 0.
Equation
The condition for an obtuse angle between two vectors a and b can be written as:
a · b < 0
Summary
- The condition for an obtuse angle between two vectors a and b is a · b < 0.
- This condition can be obtained by using the dot product formula.
- An obtuse angle has a negative cosine value.
- Hence, the dot product of the vectors must be negative for an obtuse angle.
End of Slides
title: Vectors - Problems - Determining Collinearity of Vectors
Problem
Given three vectors a, b, and c, determine whether they are collinear.
- a = (a₁, a₂, a₃)
- b = (b₁, b₂, b₃)
- c = (c₁, c₂, c₃)
Solution
- Three vectors are collinear if they are scalar multiples of each other.
- To check if vectors a, b, and c are collinear, we need to verify the following condition:
- Here, k is a scalar value.
Example
Given three vectors a = (2, -1, 3), b = (4, -2, 6), and c = (-6, 3, -9), determine whether they are collinear.
Solution
- The vectors a, b, and c are collinear if they satisfy the condition: a = k b = k c
- Let’s find the value of k by comparing the corresponding components of the vectors.
- a₁ = 2, b₁ = 4, c₁ = -6 => 2 = k(4) = k(-6), k = 1/2 = -1/3
- a₂ = -1, b₂ = -2, c₂ = 3 => -1 = k(-2) = k(3), k = 1/2 = -1/3
- a₃ = 3, b₃ = 6, c₃ = -9 => 3 = k(6) = k(-9), k = 1/2 = -1/3
- The values of k obtained for all three components are the same. Hence, the vectors a, b, and c are collinear.
Equation
The condition for collinearity of three vectors a, b, and c can be written as:
a = k b = k c
Summary
- Three vectors are collinear if they are scalar multiples of each other.
- To check for collinearity, compare the components of the vectors and find a common scalar value.
- If the vectors satisfy the condition a = k b = k c, they are collinear.
- Collinear vectors lie on the same line or are parallel to each other.