Slide 1
- Topic: Probability - Variance of Binomial Distribution
Slide 2
- Binomial Distribution:
- A probability distribution that summarizes the number of successes in a fixed number of independent Bernoulli trials.
- Each trial has two possible outcomes: success or failure.
- The probability of success remains constant for each trial.
Slide 3
- Formula for Variance of Binomial Distribution:
- Var(X) = np(1-p)
- Where:
- Var(X) is the variance of the binomial distribution
- n is the number of trials
- p is the probability of success in a single trial
Slide 4
- Example:
- Consider flipping a fair coin 10 times.
- The probability of getting heads (success) is 0.5.
- The number of trials, n = 10.
- Calculate the variance of the binomial distribution.
Slide 5
- Solution:
- n = 10, p = 0.5
- Variance of Binomial Distribution: Var(X) = np(1-p)
- Var(X) = 10 * 0.5 * (1 - 0.5)
- Var(X) = 10 * 0.5 * 0.5
- Var(X) = 2.5
Slide 6
- Interpretation:
- The variance of the binomial distribution for flipping a fair coin 10 times is 2.5.
- This indicates that there is a variability in the number of heads obtained in repeated experiments of flipping the coin 10 times.
Slide 7
- Properties of Variance:
- The variance is always non-negative.
- If all trials have the same probability of success, the binomial distribution will have the highest variance when p = 0.5.
Slide 8
- Importance of Variance:
- Variance provides a measure of the spread or dispersion of a probability distribution.
- It helps to understand the variability in the outcomes of a binomial experiment.
- Larger variances indicate greater spread or dispersion.
Slide 9
- Relationship between Variance and Standard Deviation:
- The standard deviation is the square root of the variance.
- It measures the average amount by which observations in the distribution differ from the mean.
Slide 10
- Example:
- Find the standard deviation of the binomial distribution used in the previous example.
Slide 11
- Solution:
- Variance of Binomial Distribution: Var(X) = np(1-p)
- Var(X) = 10 * 0.5 * (1 - 0.5)
- Var(X) = 10 * 0.5 * 0.5
- Var(X) = 2.5
- Interpretation:
- The variance of the binomial distribution for flipping a fair coin 10 times is 2.5.
- This indicates that there is a variability in the number of heads obtained in repeated experiments of flipping the coin 10 times.
- Properties of Variance:
- The variance is always non-negative.
- If all trials have the same probability of success, the binomial distribution will have the highest variance when p = 0.5.
- Importance of Variance:
- Variance provides a measure of the spread or dispersion of a probability distribution.
- It helps to understand the variability in the outcomes of a binomial experiment.
- Larger variances indicate greater spread or dispersion.
- Relationship between Variance and Standard Deviation:
- The standard deviation is the square root of the variance.
- It measures the average amount by which observations in the distribution differ from the mean.
Slide 12
- Example:
- Consider shooting free throws in basketball.
- The probability of making a free throw is 0.75.
- A player shoots 20 free throws.
- Calculate the variance of the binomial distribution.
Slide 13
- Solution:
- n = 20, p = 0.75
- Variance of Binomial Distribution: Var(X) = np(1-p)
- Var(X) = 20 * 0.75 * (1 - 0.75)
- Var(X) = 20 * 0.75 * 0.25
- Var(X) = 3.75
- Interpretation:
- The variance of the binomial distribution for shooting 20 free throws with a probability of success of 0.75 is 3.75.
- This indicates that there is a variability in the number of successful free throws obtained in repeated experiments of shooting 20 free throws.
Slide 14
- Example:
- Consider rolling a fair 6-sided die 50 times.
- The probability of rolling a 3 (success) is 1/6.
- Calculate the variance of the binomial distribution.
Slide 15
- Solution:
- n = 50, p = 1/6
- Variance of Binomial Distribution: Var(X) = np(1-p)
- Var(X) = 50 * (1/6) * (1 - 1/6)
- Var(X) = 50 * (1/6) * (5/6)
- Var(X) = 4.63
- Interpretation:
- The variance of the binomial distribution for rolling a fair 6-sided die 50 times with a probability of success of 1/6 is 4.63.
- This indicates that there is a variability in the number of times a 3 is rolled in repeated experiments of rolling the die 50 times.
Slide 16
- Example:
- Consider drawing a card from a standard deck of 52 cards 100 times.
- The probability of drawing a spade (success) is 1/4.
- Calculate the variance of the binomial distribution.
Slide 17
- Solution:
- n = 100, p = 1/4
- Variance of Binomial Distribution: Var(X) = np(1-p)
- Var(X) = 100 * (1/4) * (1 - 1/4)
- Var(X) = 100 * (1/4) * (3/4)
- Var(X) = 18.75
- Interpretation:
- The variance of the binomial distribution for drawing a card from a standard deck of 52 cards 100 times with a probability of success of 1/4 is 18.75.
- This indicates that there is a variability in the number of times a spade is drawn in repeated experiments of drawing a card 100 times.
Slide 18
- Example:
- Consider a genetics experiment where the probability of a certain trait being present (success) in a population is 0.2.
- The experiment is conducted on 500 individuals.
- Calculate the variance of the binomial distribution.
Slide 19
- Solution:
- n = 500, p = 0.2
- Variance of Binomial Distribution: Var(X) = np(1-p)
- Var(X) = 500 * 0.2 * (1 - 0.2)
- Var(X) = 500 * 0.2 * 0.8
- Var(X) = 80
- Interpretation:
- The variance of the binomial distribution for a genetics experiment conducted on 500 individuals with a probability of success of 0.2 is 80.
- This indicates that there is a variability in the number of individuals with the certain trait in repeated experiments.
Slide 20
- Summary:
- Variance of Binomial Distribution: Var(X) = np(1-p)
- The variance provides a measure of the spread or dispersion in the outcomes of a binomial experiment.
- Larger variances indicate greater spread or dispersion.
- The standard deviation is the square root of the variance. It measures the average amount by which observations differ from the mean.
Slide 21
- Properties of Binomial Distribution:
- It is a discrete probability distribution.
- It is symmetric when p = 0.5.
- It is right-skewed when p < 0.5 and left-skewed when p > 0.5.
- The mean of the binomial distribution is equal to np.
- The mode of the distribution is the value of x corresponding to the highest probability.
Slide 22
- Example:
- Consider rolling a fair 6-sided die 12 times.
- The probability of rolling a 6 (success) is 1/6.
- Calculate the mean and mode of the binomial distribution.
Slide 23
- Solution:
- n = 12, p = 1/6
- Mean = np = 12 * (1/6) = 2
- Mode = floor((n+1)p) = floor((12+1)(1/6)) = floor(2.166) = 2
- Interpretation:
- The mean of the binomial distribution for rolling a fair 6-sided die 12 times with a probability of success of 1/6 is 2.
- The mode is also 2, which indicates that rolling a 6 is the most probable outcome.
Slide 24
- Example:
- Consider drawing a card from a standard deck of 52 cards 20 times.
- The probability of drawing a heart (success) is 1/4.
- Calculate the mean and mode of the binomial distribution.
Slide 25
- Solution:
- n = 20, p = 1/4
- Mean = np = 20 * (1/4) = 5
- Mode = floor((n+1)p) = floor((20+1)(1/4)) = floor(5.25) = 5
- Interpretation:
- The mean of the binomial distribution for drawing a card from a standard deck of 52 cards 20 times with a probability of success of 1/4 is 5.
- The mode is also 5, which indicates that drawing a heart is the most probable outcome.
Slide 26
- Example:
- Consider conducting an experiment where the probability of a certain event happening (success) is 0.3.
- The experiment is repeated 100 times.
- Calculate the mean and mode of the binomial distribution.
Slide 27
- Solution:
- n = 100, p = 0.3
- Mean = np = 100 * 0.3 = 30
- Mode = floor((n+1)p) = floor((100+1)(0.3)) = floor(30.3) = 30
- Interpretation:
- The mean of the binomial distribution for an experiment with a probability of success of 0.3, repeated 100 times, is 30.
- The mode is also 30, indicating that the event occurring 30 times is the most probable outcome.
Slide 28
- Binomial Distribution and Normal Distribution:
- For large values of n, a binomial distribution can be approximated by a normal distribution.
- The mean of the normal distribution is equal to np.
- The standard deviation of the normal distribution is equal to √(np(1-p)).
Slide 29
- Example:
- Consider flipping a fair coin 1000 times.
- The probability of getting heads (success) is 0.5.
- Approximate the binomial distribution with a normal distribution.
Slide 30
- Solution:
- n = 1000, p = 0.5
- Mean = np = 1000 * 0.5 = 500
- Standard Deviation = √(np(1-p)) = √(1000 * 0.5 * (1 - 0.5)) = √(1000 * 0.5 * 0.5) = √250 = 15.81
- Interpretation:
- The mean of the approximated normal distribution for flipping a fair coin 1000 times is 500.
- The standard deviation is 15.81, indicating the spread of the distribution.
- This approximation is useful for large sample sizes, where the binomial distribution becomes similar to a normal distribution.