Probability - Making new events using set theory
Slide 1: Introduction to Making New Events using Set Theory
- In probability theory, we often need to create new events using set theory
- Set theory allows us to combine or manipulate events to obtain different outcomes
- In this lecture, we will learn how to make new events using set theory in probability
Slide 2: Basic Concepts in Set Theory
- In set theory, we deal with sets, which are collections of objects
- Objects in a set are called elements
- We represent a set by listing its elements inside curly braces, separated by commas
- Example: A = {1, 2, 3, 4, 5} represents a set named A with elements 1, 2, 3, 4, and 5
Slide 3: Union of Two Sets
- The union of two sets A and B, denoted as A ∪ B, is the set that contains all the elements of A and B
- A ∪ B = {x : x belongs to A or x belongs to B}
- Example: A = {1, 2, 3} and B = {3, 4, 5}, then A ∪ B = {1, 2, 3, 4, 5}
Slide 4: Intersection of Two Sets
- The intersection of two sets A and B, denoted as A ∩ B, is the set that contains all the common elements of A and B
- A ∩ B = {x : x belongs to A and x belongs to B}
- Example: A = {1, 2, 3} and B = {3, 4, 5}, then A ∩ B = {3}
Slide 5: Complement of a Set
- The complement of a set A, denoted as A’, is the set that contains all the elements that are not in A but are in the universal set
- A’ = {x : x is in the universal set and x is not in A}
- Example: A = {1, 2, 3, 4, 5} and the universal set is {1, 2, 3, 4, 5, 6, 7}, then A’ = {6, 7}
Slide 6: Difference between Two Sets
- The difference between two sets A and B, denoted as A - B, is the set that contains all the elements of A that are not in B
- A - B = {x : x belongs to A and x does not belong to B}
- Example: A = {1, 2, 3} and B = {3, 4, 5}, then A - B = {1, 2}
Slide 7: Disjoint Sets
- Two sets A and B are said to be disjoint if their intersection is an empty set
- A ∩ B = {}
- Example: A = {1, 2, 3} and B = {4, 5, 6} are disjoint sets
Slide 8: Example Problem 1
- Let A = {1, 2, 3, 4} and B = {3, 4, 5, 6}
- Find A ∪ B, A ∩ B, A’, and B'
- Solution:
- A ∪ B = {1, 2, 3, 4, 5, 6}
- A ∩ B = {3, 4}
- A’ = {}
- B’ = {}
Slide 9: Example Problem 2
- Let A = {1, 2, 3, 4} and B = {3, 4, 5, 6}
- Find A - B and B - A
- Solution:
- A - B = {1, 2}
- B - A = {5, 6}
Slide 10: Summary and Conclusion
- Set theory allows us to create new events in probability
- We can combine sets using union and intersection operations
- Complement and difference operations help us manipulate sets further
- Understanding set theory is essential in probability for creating new events
Slide 11: Union and Intersection of Multiple Sets
- We can extend the concepts of union and intersection to more than two sets
- Union of Multiple Sets:
- The union of three sets A, B, and C, denoted as A ∪ B ∪ C, is the set that contains all the elements of A, B, and C
- A ∪ B ∪ C = {x : x belongs to A or x belongs to B or x belongs to C}
- Intersection of Multiple Sets:
- The intersection of three sets A, B, and C, denoted as A ∩ B ∩ C, is the set that contains all the elements that are common to A, B, and C
- A ∩ B ∩ C = {x : x belongs to A and x belongs to B and x belongs to C}
- Example: A = {1, 2, 3}, B = {2, 3, 4}, and C = {3, 4, 5}
- A ∪ B ∪ C = {1, 2, 3, 4, 5}
- A ∩ B ∩ C = {3}
Slide 12: Complement of Multiple Sets
- Similar to complement of a single set, we can find the complement of multiple sets
- The complement of multiple sets A, B, and C, denoted as (A ∪ B ∪ C)’, is the set that contains all the elements that are not in A, B, or C but are in the universal set
- (A ∪ B ∪ C)’ = {x : x is in the universal set and x is not in A, B, or C}
- Example: A = {1, 2, 3}, B = {2, 3, 4}, C = {3, 4, 5}, and the universal set is {1, 2, 3, 4, 5, 6, 7}
Slide 13: Venn Diagrams
- Venn diagrams are graphical representations of sets
- They help us visualize how sets are related and how they overlap
- In a Venn diagram, each set is represented by a circle or an oval, and the elements of the set are placed inside the circle
- The overlapping region between circles represents the common elements between sets
- Venn diagrams are useful in understanding set operations and solving problems involving multiple sets
Slide 14: Example Problem 3
- Let A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, and C = {4, 5, 6, 7}
- Represent these sets using a Venn diagram
- Solution:
- Draw three circles to represent sets A, B, and C
- Place the elements of each set inside the corresponding circle
- The overlapping regions represent the common elements between sets
Slide 15: Sample Venn Diagram
- A Venn diagram representing sets A, B, and C
- In this Venn diagram, the overlapping region between circles A, B, and C represents the common element 4
Slide 16: Disjoint Sets and Intersection
- If the intersection of two sets A and B is an empty set, then the sets are called disjoint sets
- Disjoint sets have no elements in common
- Example: A = {1, 2, 3}, B = {4, 5, 6}
- A ∩ B = {} (empty set)
- A and B are disjoint sets
Slide 17: Subset and Superset
- If every element of set A is also an element of set B, then we say that A is a subset of B, denoted as A ⊆ B
- Example: A = {1, 2}, B = {1, 2, 3}
- If set A is a subset of set B and B is not a subset of A, then we say that A is a proper subset of B, denoted as A ⊂ B
- Example: A = {1, 2}, B = {1, 2, 3}
Slide 18: Probability of Events using Set Theory
- Set theory plays a crucial role in calculating probabilities of events
- Probability is essentially measuring the likelihood of an event occurring
- We can use set operations to calculate probabilities by counting the number of favorable outcomes and total possible outcomes
Slide 19: Example Problem 4
- Let S be the sample space of rolling a fair die
- Define two events A and B as follows:
- A: An even number appears on the die
- B: A prime number appears on the die
- Find P(A), P(B), and P(A ∪ B)
- Solution:
- A = {2, 4, 6} (3 even numbers out of 6 possible outcomes)
- B = {2, 3, 5} (3 prime numbers out of 6 possible outcomes)
- P(A) = 3/6 = 1/2
- P(B) = 3/6 = 1/2
- P(A ∪ B) = 4/6 = 2/3
Slide 20: Summary and Conclusion
- Set theory provides useful tools for creating new events and manipulating sets in probability
- Union, intersection, complement, and difference operations are often used to combine or analyze events
- Venn diagrams help visualize the relationships between sets
- Understanding set theory is essential in probability for calculating probabilities of events
- Slide: Conditional Probability
- Conditional probability is the probability of an event A occurring given that another event B has already occurred
- It is denoted as P(A|B), read as “probability of A given B”
- The formula for conditional probability is:
- P(A|B) = P(A and B) / P(B)
- Example: Suppose we roll two fair dice, A = {1, 2, 3, 4, 5, 6} and B = {2, 4, 6}. Find P(A|B).
- P(A and B) = {2, 4, 6} = 3/36 = 1/12
- P(B) = {2, 4, 6} = 3/36 = 1/12
- P(A|B) = (1/12) / (1/12) = 1
- Slide: Independent Events
- Two events A and B are said to be independent if the occurrence of one event does not affect the probability of the other event
- Mathematically, if P(A|B) = P(A), then A and B are independent
- Example: Tossing a fair coin and rolling a fair die are independent events since the outcome of one does not affect the other
- Slide: Mutually Exclusive Events
- Two events A and B are said to be mutually exclusive if they cannot occur at the same time
- Mathematically, if A and B are mutually exclusive, then P(A and B) = 0
- Example: Tossing a coin and getting a head (A) and getting a tail (B) are mutually exclusive events
- Slide: Addition Rule of Probability
- The addition rule of probability states that the probability of the union of two events A and B is equal to the sum of their individual probabilities minus the probability of their intersection
- Mathematically, P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
- Example: A fair die is rolled. Find the probability of getting an even number (A) or a prime number (B).
- P(A) = 3/6 = 1/2 (3 even numbers out of 6 possible outcomes)
- P(B) = 3/6 = 1/2 (3 prime numbers out of 6 possible outcomes)
- P(A ∩ B) = 0 (no number is both even and prime)
- P(A ∪ B) = 1/2 + 1/2 - 0 = 1
- Slide: Multiplication Rule of Probability
- The multiplication rule of probability states that the probability of the intersection of two independent events A and B is equal to the product of their individual probabilities
- Mathematically, P(A ∩ B) = P(A) * P(B)
- Example: A fair coin is tossed twice. Find the probability of getting two heads (A) and two tails (B).
- P(A) = 1/2 * 1/2 = 1/4 (probability of getting a head on the first and second toss)
- P(B) = 1/2 * 1/2 = 1/4 (probability of getting a tail on the first and second toss)
- P(A ∩ B) = 0 (no outcome satisfies both A and B)
- Slide: Complementary Events
- Complementary events are two events that together cover all possible outcomes
- The probability of an event A and its complement A’ is always equal to 1
- Mathematically, P(A) + P(A’) = 1
- Example: The probability of getting a head (A) on a fair coin is 1/2, and the probability of getting a tail (A’) is also 1/2.
- Slide: Sample Space and Event Space
- The sample space of an experiment is the set of all possible outcomes of the experiment
- It is denoted as S
- Example: For rolling a single fair die, the sample space is S = {1, 2, 3, 4, 5, 6}
- An event space is a subset of the sample space that contains specific outcomes of interest
- Example: In the same die experiment, the event space for getting an odd number is A = {1, 3, 5}
- Slide: Law of Total Probability
- The law of total probability states that if an experiment results in a partition of the sample space into mutually exclusive events A₁, A₂, …, An, then the probability of an event B is given by the sum of the probabilities of B given each Ai, weighted by the probability of Ai
- Mathematically, P(B) = P(B|A₁) * P(A₁) + P(B|A₂) * P(A₂) + … + P(B|An) * P(An)
- Example: Two factories produce electronic components A and B, with probabilities A = 0.2 and B = 0.8. The defect rate for components manufactured by A is 0.1, while the defect rate for components manufactured by B is 0.2. Find the probability that a randomly selected component is defective.
- P(defective|A) = 0.1
- P(defective|B) = 0.2
- P(defective) = 0.1 * 0.2 + 0.2 * 0.8 = 0.18
- Slide: Bayes’ Theorem
- Bayes’ theorem is a formula that allows us to update the probability of an event based on new information or evidence
- Mathematically, it is given by:
- P(A|B) = (P(B|A) * P(A)) / P(B)
- Example: A blood test for a certain disease is 98% accurate, with a false positive rate of 3%. If the prevalence of the disease in the population is 0.5%, find the probability that a person has the disease given that the test is positive.
- P(A) = 0.005 (prevalence of the disease)
- P(B|A) = 0.98 (accuracy of the test)
- P(B|A’) = 0.03 (false positive rate)
- P(A|B) = (0.98 * 0.005) / (0.98 * 0.005 + 0.03 * 0.995) ≈ 0.14
- Slide: Summary and Conclusion
- Set theory and probability theory go hand in hand, allowing us to analyze and calculate probabilities of events
- Conditional probability, independent events, mutually exclusive events, and probability rules play a vital role in probability calculations
- Understanding these concepts and applying them correctly is essential in problem-solving for probability-related questions
- Keep practicing and applying these concepts to gain a better understanding and mastery of probability