Probability – Addition rule of Probability using Axiomatic definition

  • Probability is a branch of mathematics that deals with the likelihood of events occurring.
  • This topic focuses on the addition rule of probability using the axiomatic definition.
  • The axiomatic definition states that the probability of the union of two or more mutually exclusive events is the sum of their individual probabilities.
  • Let’s understand this concept with an example.

Example 1:

  • Consider a deck of playing cards.

  • What is the probability of drawing a red card or a face card? Solution:

  • We have two mutually exclusive events: drawing a red card and drawing a face card.

  • The probability of drawing a red card is 26/52 or 1/2.

  • The probability of drawing a face card is 12/52 or 3/13.

  • By applying the addition rule of probability, the probability of drawing a red card or a face card is (1/2) + (3/13) = 11/26.

  • The addition rule of probability can be extended to more than two events as well.

  • Let’s understand this concept further with another example. Example 2:

  • Consider rolling a fair six-sided die.

  • What is the probability of getting an odd number or a number greater than 4? Solution:

  • We have two mutually exclusive events: getting an odd number and getting a number greater than 4.

  • The probability of getting an odd number is 3/6 or 1/2.

  • The probability of getting a number greater than 4 is 2/6 or 1/3.

  • By applying the addition rule of probability, the probability of getting an odd number or a number greater than 4 is (1/2) + (1/3) = 5/6.

  • In some cases, the events may not be mutually exclusive.

  • Let’s explore the addition rule of probability for non-mutually exclusive events. Example 3:

  • Consider drawing a card from a deck.

  • What is the probability of drawing a heart or a face card? Solution:

  • The events “drawing a heart” and “drawing a face card” are not mutually exclusive, as the card can be both a heart and a face card.

  • We need to consider the overlap between these events.

  • The probability of drawing a heart is 13/52 or 1/4.

  • The probability of drawing a face card is 12/52 or 3/13.

  • To find the probability of drawing a heart or a face card, we subtract the probability of drawing a heart and a face card (which is also double-counted) from the sum of individual probabilities.

  • Therefore, the probability of drawing a heart or a face card is (1/4) + (3/13) - (1/26) = 15/26.

  • The addition rule of probability using the axiomatic definition is a fundamental concept in probability theory.

  • It helps us calculate the probability of events occurring together or separately.

  • It is applicable to mutually exclusive events as well as non-mutually exclusive events.

  • Understanding this concept is crucial for solving various probability problems in mathematics and real-life scenarios.

  • Let’s practice more examples to strengthen our understanding.

Probability – Addition rule of Probability using Axiomatic definition

  1. Mutually Exclusive Events:
  • Event A and Event B are said to be mutually exclusive if they cannot both occur at the same time.
  • In other words, if Event A occurs, then Event B cannot occur, and vice versa.
  • For mutually exclusive events, the addition rule of probability is straightforward.
  • The probability of the union of two mutually exclusive events is the sum of their individual probabilities.
  • Mathematically, P(A or B) = P(A) + P(B).
  1. Example:
  • Consider rolling a fair six-sided die.
  • What is the probability of getting a 2 or a 4? Solution:
  • The events “getting a 2” and “getting a 4” are mutually exclusive.
  • The probability of getting a 2 is 1/6.
  • The probability of getting a 4 is also 1/6.
  • By applying the addition rule of probability, the probability of getting a 2 or a 4 is 1/6 + 1/6 = 1/3.
  1. Non-Mutually Exclusive Events:
  • Event A and Event B are said to be non-mutually exclusive if they can both occur at the same time.
  • In such cases, we need to consider the overlap between the events.
  • The addition rule of probability for non-mutually exclusive events is as follows:
    • P(A or B) = P(A) + P(B) - P(A and B).
  1. Example:
  • Consider drawing a playing card from a standard deck.
  • What is the probability of drawing a heart or a king? Solution:
  • The events “drawing a heart” and “drawing a king” are not mutually exclusive.
  • The probability of drawing a heart is 1/4.
  • The probability of drawing a king is 4/52.
  • To find the probability of drawing a heart or a king, we subtract the probability of drawing a king of hearts (which is double-counted) from the sum of individual probabilities.
  • Therefore, the probability of drawing a heart or a king is (1/4) + (4/52) - (1/52) = 15/52.
  1. General Addition Rule:
  • The addition rule of probability can be extended to more than two events.
  • For any two events A and B, the probability of their union is given by:
    • P(A or B) = P(A) + P(B) - P(A and B).
  • Similarly, the probability of the union of three events A, B, and C can be calculated using:
    • P(A or B or C) = P(A) + P(B) + P(C) - P(A and B) - P(A and C) - P(B and C) + P(A and B and C).
  1. Example:
  • Consider a bag containing red, blue, and green balls.
  • What is the probability of drawing a red or a blue ball or a green ball? Solution:
  • Suppose the probability of drawing a red ball is 3/10.
  • The probability of drawing a blue ball is 2/10.
  • The probability of drawing a green ball is 5/10.
  • The probability of drawing a red and blue ball is 1/10.
  • The probability of drawing a red and green ball is 2/10.
  • The probability of drawing a blue and green ball is 3/10.
  • By applying the general addition rule of probability, the probability is (3/10) + (2/10) + (5/10) - (1/10) - (2/10) - (3/10) = 14/10.
  1. Complementary Events:
  • Complementary events are mutually exclusive events whose probabilities sum up to 1.
  • Mathematically, if A is an event, then the probability of A plus the probability of not A is 1.
  • P(A) + P(not A) = 1.
  • The probability of not A is denoted as P(A’).
  1. Example:
  • Consider tossing a fair coin.
  • What is the probability of getting heads or tails? Solution:
  • Let’s say the probability of getting heads is P(H) = 1/2.
  • The probability of getting tails is P(T) = P(H’) = 1/2.
  • By applying the addition rule of probability, the probability of getting heads or tails is 1/2 + 1/2 = 1.
  1. Addition Rule for Mutually Exclusive Events:
  • Mutually exclusive events have no common outcomes.
  • If A and B are mutually exclusive, then P(A and B) = 0.
  • In this case, the addition rule of probability simplifies to:
    • P(A or B) = P(A) + P(B).
  1. Summary:
  • The addition rule of probability using the axiomatic definition states that the probability of the union of two or more mutually exclusive events is the sum of their individual probabilities.
  • For non-mutually exclusive events, we need to subtract the probability of their overlap to avoid double counting.
  • The general addition rule of probability can be used for more than two events.
  • Complementary events have probabilities that sum up to 1.
  • Understanding the addition rule of probability is essential for solving probability problems and analyzing real-world scenarios.
  1. Conditional Probability:
  • Conditional probability is the probability of an event occurring given that another event has already occurred.
  • It is denoted as P(A | B), read as “the probability of A given B.”
  • Mathematically, P(A | B) = P(A and B) / P(B).
  • This formula allows us to calculate the probability of A given that B has already occurred.
  1. Example:
  • Consider drawing two cards from a deck without replacement.
  • What is the probability of drawing a red card on the second draw, given that the first card drawn was red? Solution:
  • Let’s assume that the first card drawn was red.
  • The probability of drawing a red card on the second draw is the probability of drawing a red card and a red card on both draws divided by the probability of the first card being red.
  • The probability of drawing a red card and a red card is (26/52) * (25/51).
  • The probability of the first card being red is 26/52.
  • By applying the formula, we can find the conditional probability: P(red on 2nd draw | red on 1st draw) = ((26/52) * (25/51)) / (26/52) = 25/51.
  1. Independence of Events:
  • Two events A and B are said to be independent if the probability of one event occurring does not affect the probability of the other event occurring.
  • Mathematically, if A and B are independent events, then P(A | B) = P(A) and P(B | A) = P(B).
  • This means that the occurrence of one event does not provide any information about the occurrence of the other event.
  1. Example:
  • Consider rolling two fair six-sided dice.
  • What is the probability of getting a 4 on the first die and a 3 on the second die? Solution:
  • The probability of getting a 4 on the first die is 1/6.
  • The probability of getting a 3 on the second die is also 1/6.
  • Since the rolls of the dice are independent, the probability of both events happening is: P(4 on 1st die and 3 on 2nd die) = (1/6) * (1/6) = 1/36.
  1. Multiplication Rule for Independent Events:
  • The multiplication rule for independent events states that the probability of two independent events occurring together is the product of their individual probabilities.
  • Mathematically, if A and B are independent events, then P(A and B) = P(A) * P(B).
  • This rule can be extended to more than two independent events as well.
  1. Example:
  • Consider flipping a fair coin twice.
  • What is the probability of getting heads on both flips? Solution:
  • The probability of getting heads on the first flip is 1/2.
  • The probability of getting heads on the second flip is also 1/2.
  • By applying the multiplication rule for independent events, the probability of getting heads on both flips is: P(heads on 1st flip and heads on 2nd flip) = (1/2) * (1/2) = 1/4.
  1. Total Probability Theorem:
  • The total probability theorem is used to find the probability of an event A given that another event B has occurred.
  • It states that the probability of event A is the sum of the probabilities of A occurring in each possible way, considering all mutually exclusive and exhaustive events.
  1. Example:
  • Consider a bag containing 3 red balls and 5 blue balls.
  • A ball is drawn at random.
  • It is known that the ball is either red or blue.
  • What is the probability of the ball being red? Solution:
  • Let A be the event of drawing a red ball and B be the event of drawing either a red or blue ball.
  • The probability of drawing a red ball given that the ball is either red or blue can be calculated using the total probability theorem.
  • P(red) = P(red and B1) + P(red and B2)
  • Here, B1 represents drawing a red ball, and B2 represents drawing a blue ball.
  • P(red and B1) = (3/8)
  • P(red and B2) = 0
  • Therefore, P(red) = (3/8) + 0 = 3/8.
  1. Bayes’ Theorem:
  • Bayes’ theorem is used to calculate the probability of an event A given that another event B has occurred.
  • It is expressed as:
    • P(A | B) = (P(B | A) * P(A)) / P(B)
    • P(A) and P(B) are the probabilities of A and B occurring independently.
    • P(B | A) is the probability of B occurring given A has occurred.
    • P(A | B) is the probability of A occurring given B has occurred.
  1. Example:
  • Consider a factory that produces light bulbs.
  • The factory produces two types of light bulbs: Type A and Type B.
  • It is known that 10% of all produced bulbs are defective.
  • It is also known that 8% of Type A bulbs are defective, while 12% of Type B bulbs are defective.
  • What is the probability that a randomly selected defective bulb is of Type A? Solution:
  • Let A be the event of selecting a Type A bulb, and B be the event of selecting a defective bulb.
  • P(A) = 0.5 (assuming an equal number of Type A and Type B bulbs are produced)
  • P(B) = 0.1 (given that 10% of all bulbs are defective)
  • P(B | A) = 0.08 (given that 8% of Type A bulbs are defective)
  • By applying Bayes’ theorem, we can calculate P(A | B):
    • P(A | B) = (P(B | A) * P(A)) / P(B)
    • P(A | B) = (0.08 * 0.5) / 0.1
    • P(A | B) = 0.04 / 0.1
    • P(A | B) = 0.4