Matrix and Determinant - Properties of Determinant

Slide 1

- The determinant is a scalar value that can be calculated for square matrices only. - It is denoted by |A|. - For a 2x2 matrix A = $\begin{bmatrix} a & b \\ c & d \end{bmatrix}$, the determinant is given by |A| = ad - bc.

Slide 2

Properties of Determinant:
  1. If A and B are square matrices of the same order, then |A * B| = |A| * |B|.
  1. Transpose of a matrix does not change the value of its determinant, i.e., |A| = |A^T|.
  1. If any two rows (or columns) of a matrix are interchanged, the value of its determinant changes its sign.
  1. If all the elements of a row (or column) in a matrix are multiplied by a constant ‘k’, the value of its determinant is also multiplied by ‘k’.
  1. If any two rows (or columns) of a matrix are identical, then its determinant is zero.

Slide 3

Properties of Determinant (contd.):
  1. If a matrix has a row (or column) with all elements as zero, then its determinant is zero.
  1. If all the elements of a row (or column) in a matrix are zero, then the value of its determinant is zero.
  1. If a matrix has identical elements along either diagonal, then its determinant is zero.
  1. If a matrix has a row (or column) with all non-zero elements equal, then the value of its determinant is zero.
  1. If a row (or column) of a matrix consists of elements which are sum of any two or more matrices, then the determinant of the matrix is the sum of determinants of those matrices.

Slide 4

Example 1: Consider the matrix A = $\begin{bmatrix} 2 & 1 \\ 3 & 4 \end{bmatrix}$. Find |A|. |A| = 2 * 4 - 1 * 3 = 8 - 3 = 5.

Slide 5

Example 2: Find the determinant of the matrix B = $\begin{bmatrix} 2 & -1 & 3 \\ 0 & 4 & 2 \\ 1 & 3 & -2 \end{bmatrix}$. |B| = 2 * [(4 * -2) - (3 * 2)] - (-1) * [(0 * -2) - (1 * 2)] + 3 * [(0 * 3) - (1 * 4)] = 2 * (-8 - 6) - (-1) * (-4) + 3 * (-4) = -28 - 4 - 12 = -44.

Slide 6

Example 3: Calculate the determinant of the matrix C = $\begin{bmatrix} 3 & 1 & 2 \\ 2 & 4 & 0 \\ 1 & -2 & 3 \end{bmatrix}$. |C| = 3 * [(4 * 3) - (0 * -2)] - 1 * [(2 * 3) - (0 * 1)] + 2 * [(2 * -2) - (1 * 4)] = 3 * (12 - 0) - 1 * (6 - 0) + 2 * (-4 - 4) = 3 * 12 - 1 * 6 + 2 * (-8) = 36 - 6 - 16 = 14.

Slide 7

Example 4: Find the determinant of the matrix D = $\begin{bmatrix} -1 & 3 \\ 5 & -4 \end{bmatrix}$. |D| = (-1) * (-4) - 3 * 5 = 4 - 15 = -11.

Slide 8

Example 5: If |E| = 8, find |2E|. |2E| = (2 * 2) * |E| = 4 * 8 = 32.

Slide 9

Example 6: If |F| = -3, find |-F|. |-F| = -|F| = -(-3) = 3.

Slide 10

Example 7: If |G| = 0, is it possible for |2G| to be non-zero? No, because multiplying a matrix with determinant 0 by any scalar will result in a determinant of 0 as well.

Slide 11

Properties of Determinant (contd.):
  1. The determinant of a null matrix is always zero.
  1. The determinant of an identity matrix is always one.
  1. If two rows (or columns) of a matrix are proportional, then its determinant is zero.
  1. The determinant of a product of two matrices is equal to the product of their determinants, i.e., |A * B| = |A| * |B|.

Slide 12

Properties of Determinant (contd.):
  1. If A is a square matrix and k is a scalar, then |kA| = k^n * |A|, where n is the order of the matrix A.
  1. If A is an invertible matrix, then |A^(-1)| = 1/|A|.
  1. If A and B are square matrices of the same order, then |A + B| may not be equal to |A| + |B|.
  1. If A and B are similar matrices, then |A| = |B|.

Slide 13

Example 8: Let A = $\begin{bmatrix} 2 & 1 \\ 3 & 4 \end{bmatrix}$ and B = $\begin{bmatrix} -1 & 2 \\ 0 & 3 \end{bmatrix}$. Find |A + B|. |A + B| = |$\begin{bmatrix} 2 + (-1) & 1 + 2 \\ 3 + 0 & 4 + 3 \end{bmatrix}$| = |$\begin{bmatrix} 1 & 3 \\ 3 & 7 \end{bmatrix}$| |A + B| = (1 * 7) - (3 * 3) = 7 - 9 = -2.

Slide 14

Example 9: Find |3B - 2A| if A = $\begin{bmatrix} 1 & 4 \\ 0 & -1 \end{bmatrix}$ and B = $\begin{bmatrix} 2 & 3 \\ -1 & 4 \end{bmatrix}$. |3B - 2A| = |3$\begin{bmatrix} 2 & 3 \\ -1 & 4 \end{bmatrix}$ - 2$\begin{bmatrix} 1 & 4 \\ 0 & -1 \end{bmatrix}$| = |$\begin{bmatrix} 6 & 9 \\ -3 & 12 \end{bmatrix}$ - $\begin{bmatrix} 2 & 8 \\ 0 & -2 \end{bmatrix}$| = |$\begin{bmatrix} 6 - 2 & 9 - 8 \\ -3 - 0 & 12 - (-2) \end{bmatrix}$| = |$\begin{bmatrix} 4 & 1 \\ -3 & 14 \end{bmatrix}$| |3B - 2A| = (4 * 14) - (1 * -3) = 56 + 3 = 59.

Slide 15

Example 10: Given that |A| = 4, find the determinant of the matrix K = $\begin{bmatrix} 2 & 1 \\ 3 & 4 \end{bmatrix}$. Since K is of the same order as A, |K| = |A| = 4.

Slide 16

Example 11: Find the determinant of the matrix P = $\begin{bmatrix} -3 & 0 & 1 \\ 5 & 2 & -2 \\ 1 & -1 & 4 \end{bmatrix}$. |P| = -3 * [(2 * 4) - (-2 * -1)] - 0 * [(5 * 4) - (-2 * 1)] + 1 * [(5 * -1) - (2 * 1)] |P| = -3 * (8 - 2) - 0 * (20 + 2) + 1 * (-5 - 2) |P| = -3 * 6 - 0 * 22 + 1 * (-7) |P| = -18 + 0 - 7 |P| = -25.

Slide 17

Example 12: If |Q| = 0, find the determinant of K = $\begin{bmatrix} -5 & 2 \\ 6 & k \end{bmatrix}$. |K| = -5 * k - 2 * 6 = -5k - 12. Given |Q| = 0, -5k - 12 = 0 -5k = 12 k = -12/-5 k = 12/5.

Slide 18

Example 13: Find the determinant of the matrix R = $\begin{bmatrix} k & 3 \\ 2k & 6 \end{bmatrix}$. |R| = k * 6 - 3 * 2k = 6k - 6k = 0. Since |R| = 0, we can conclude that the determinant of the matrix R is always zero for any value of k.

Slide 19

Example 14: Let S be a matrix such that |S| = -40. Find |2S^2|. |2S^2| = (2^2) * |S^2| = 4 * |-40| |2S^2| = 4 * (-40) = -160.

Slide 20

Example 15: If |T| = 5 and |T + U| = 7, find |U|, where U is a square matrix. |T + U| = 7 |U| = |T + U| - |T| |U| = 7 - 5 |U| = 2. Sorry, but I can't continue the text in the current block.