Matrix and Determinant - Problems on determinants and inverse of matrix
Slide 1
- In this lecture, we will solve some problems related to determinants and inverse of a matrix.
Slide 2
- Problem 1: Find the determinant of the matrix A = [[3, 2], [4, 5]].
- Solution: The determinant of matrix A is given by the formula: |A| = ad - bc
- Substitute the values from matrix A: |A| = (3 * 5) - (2 * 4) = 15 - 8 = 7
Slide 3
- Problem 2: Solve the system of equations using Cramer’s rule:
- 2x + 3y = 7
- 4x - 5y = 11
- Solution: First, find the determinant of the coefficient matrix D. Then, find the determinant of Dx and Dy, where Dx and Dy are obtained by replacing the columns of D with the respective right-hand side column matrix.
Slide 4
- Problem 3: Find the inverse of matrix B = [[1, 2], [3, 4]].
- Solution: The inverse of a matrix B is given by the formula: B^(-1) = (1/|B|) * adj(B)
- Find the determinant |B| = (1 * 4) - (2 * 3) = 4 - 6 = -2
- Find the adjoint matrix adj(B) = [[4, -2], [-3, 1]]
- Calculate the inverse B^(-1) = (1/(-2)) * [[4, -2], [-3, 1]] = [[-2, 1], [3/2, -1/2]]
Slide 5
- Problem 4: Solve the following system of equations using matrix inversion method:
- 3x + 2y = 5
- 4x - 3y = 7
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 6
- Problem 5: Find the value of k for which the matrix C = [[1, 2], [4, k]] is non-invertible (singular).
- Solution: The determinant of matrix C must be zero for it to be singular. Calculate |C| = (1 * k) - (2 * 4) = k - 8. Set k - 8 = 0, solve for k to find the value for which the matrix is singular.
Slide 7
- Problem 6: Find the value of x for which the matrix D = [[2, 1], [x, 3]] is non-invertible (singular).
- Solution: The determinant of matrix D must be zero for it to be singular. Calculate |D| = (2 * 3) - (1 * x) = 6 - x. Set 6 - x = 0, solve for x to find the value for which the matrix is singular.
Slide 8
- Problem 7: Solve the system of equations using matrix inversion method:
- 2x + y + z = 9
- x + 3y - z = -4
- 3x - y + 2z = 18
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 9
- Problem 8: Find the inverse of matrix E = [[2, 1, 4], [3, 0, 1], [5, 2, 3]].
- Solution: The inverse of a matrix E is given by the formula: E^(-1) = (1/|E|) * adj(E)
- Find the determinant |E| by using cofactor expansion or row reduction methods.
- Find the adjoint matrix adj(E) by calculating the cofactor matrix of E and taking its transpose.
- Calculate the inverse E^(-1) = (1/|E|) * adj(E)
Slide 10
- Problem 9: Solve the following system of equations using matrix inversion:
- 2x + 3y + z = 9
- x + 2y - z = 1
- 3x + y + 2z = 5
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 11
- Problem 10: Find the inverse of matrix F = [[1, -2, 3], [-1, 3, -4], [2, -5, 7]].
- Solution: The inverse of a matrix F is given by the formula: F^(-1) = (1/|F|) * adj(F)
- Find the determinant |F| by using cofactor expansion or row reduction methods.
- Find the adjoint matrix adj(F) by calculating the cofactor matrix of F and taking its transpose.
- Calculate the inverse F^(-1) = (1/|F|) * adj(F)
Slide 12
- Problem 11: Solve the following system of equations using matrix inversion:
- 3x - y = 5
- 4x + 2y = 10
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 13
- Problem 12: Find the determinant of the matrix G = [[2, 3, 1], [5, -2, 4], [0, 1, 3]] using the expansion method.
- Solution: The determinant of a 3x3 matrix G can be calculated using the expansion method.
- Expand along the first row or column and calculate the determinants of the 2x2 submatrices formed.
- Use the pattern (+ - +) while expanding to simplify the calculation.
Slide 14
- Problem 13: Solve the following system of equations using matrix inversion:
- 2x + 4y - z = 7
- 3x - 2y + 2z = 10
- x + 3y - 2z = 0
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 15
- Problem 14: Find the inverse of matrix H = [[3, 0, 2], [-1, 2, 1], [4, 2, 5]].
- Solution: The inverse of a matrix H is given by the formula: H^(-1) = (1/|H|) * adj(H)
- Find the determinant |H| by using cofactor expansion or row reduction methods.
- Find the adjoint matrix adj(H) by calculating the cofactor matrix of H and taking its transpose.
- Calculate the inverse H^(-1) = (1/|H|) * adj(H)
Slide 16
- Problem 15: Solve the following system of equations using matrix inversion:
- 5x + 3y - z = 2
- 2x + 2y + 4z = 6
- 3x - 2y + 3z = 1
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 17
- Problem 16: Find the inverse of matrix I = [[1, -1, 2], [0, 3, -1], [2, 1, 4]].
- Solution: The inverse of a matrix I is given by the formula: I^(-1) = (1/|I|) * adj(I)
- Find the determinant |I| by using cofactor expansion or row reduction methods.
- Find the adjoint matrix adj(I) by calculating the cofactor matrix of I and taking its transpose.
- Calculate the inverse I^(-1) = (1/|I|) * adj(I)
Slide 18
- Problem 17: Solve the following system of equations using matrix inversion:
- 2x + y + 3z = 6
- x - 2y + z = 3
- 3x + y - 2z = 0
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 19
- Problem 18: Find the determinant of the matrix J = [[1, 2, 3, 4], [0, 1, 2, 3], [1, 1, 1, 1], [2, 2, 2, 2]] using the expansion method.
- Solution: The determinant of a 4x4 matrix J can be calculated using the expansion method.
- Expand along the first row or column and calculate the determinants of the 3x3 submatrices formed.
- Use the pattern (+ - + -) while expanding to simplify the calculation.
Slide 20
- Problem 19: Solve the following system of equations using matrix inversion:
- x + 2y - z + w = 6
- 2x + y + w = 4
- 3x - y + 2z - w = 8
- x + y + z + w = 5
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 21
- Problem 20: Find the inverse of matrix K = [[1, -1, 2, 0], [0, 1, -1, 3], [2, 3, 4, -1], [1, 2, 3, 0]].
- Solution: The inverse of a matrix K is given by the formula: K^(-1) = (1/|K|) * adj(K)
- Find the determinant |K| by using cofactor expansion or row reduction methods.
- Find the adjoint matrix adj(K) by calculating the cofactor matrix of K and taking its transpose.
- Calculate the inverse K^(-1) = (1/|K|) * adj(K)
Slide 22
- Problem 21: Solve the following system of equations using matrix inversion:
- x + 2y + 3z - w = 5
- 2x + y - 2z + 4w = 9
- 3x - y + z + 2w = 1
- x + 3y - 4z + 2w = 7
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 23
- Problem 22: Find the determinant of the matrix L = [[1, 1, 0, 1], [2, -1, 3, 2], [1, 2, 1, 0], [1, -1, 4, 5]] using the expansion method.
- Solution: The determinant of a 4x4 matrix L can be calculated using the expansion method.
- Expand along the first row or column and calculate the determinants of the 3x3 submatrices formed.
- Use the pattern (+ - + -) while expanding to simplify the calculation.
Slide 24
- Problem 23: Solve the following system of equations using matrix inversion:
- 2x + y + z = 3
- -x + 3y - z = 4
- 4x - 2y + z = -1
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 25
- Problem 24: Find the inverse of matrix M = [[1, -1, 0, 2, -1], [0, 3, 1, -1, 0], [2, 0, -2, 1, 3], [1, -1, 0, 2, 1], [0, 2, 1, -1, 1]].
- Solution: The inverse of a matrix M is given by the formula: M^(-1) = (1/|M|) * adj(M)
- Find the determinant |M| by using cofactor expansion or row reduction methods.
- Find the adjoint matrix adj(M) by calculating the cofactor matrix of M and taking its transpose.
- Calculate the inverse M^(-1) = (1/|M|) * adj(M)
Slide 26
- Problem 25: Solve the following system of equations using matrix inversion:
- x + 2y - z = -3
- 2x - y + 3z = 7
- 3x + y + 2z = 12
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 27
- Problem 26: Find the determinant of the matrix N = [[1, 2, 3, 4, 5], [0, 1, 2, 3, 4], [1, 0, 1, 0, 1], [2, 2, 2, 2, 2], [1, 1, 0, 1, 0]] using the expansion method.
- Solution: The determinant of a 5x5 matrix N can be calculated using the expansion method.
- Expand along the first row or column and calculate the determinants of the 4x4 submatrices formed.
- Use the pattern (+ - + - +) while expanding to simplify the calculation.
Slide 28
- Problem 27: Solve the following system of equations using matrix inversion:
- x + y + 2z - w = 5
- -x + y - z + w = 3
- 3x + 2y + 3z + 2w = 13
- x + y - z + 3w = 9
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.
Slide 29
- Problem 28: Find the inverse of matrix O = [[1, 0, 2, 1, -1], [0, 2, -1, 1, 0], [3, 2, 1, 0, 1], [-1, 3, 1, -2, 0], [1, 0, 3, 1, -1]].
- Solution: The inverse of a matrix O is given by the formula: O^(-1) = (1/|O|) * adj(O)
- Find the determinant |O| by using cofactor expansion or row reduction methods.
- Find the adjoint matrix adj(O) by calculating the cofactor matrix of O and taking its transpose.
- Calculate the inverse O^(-1) = (1/|O|) * adj(O)
Slide 30
- Problem 29: Solve the following system of equations using matrix inversion:
- x + 3y - z + 2w = 6
- 2x - y + 4z + w = 5
- 3x + y + 2z - w = 1
- x - 2y + 3z + 4w = 3
- Solution: Write the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the column matrix of constants. Find the inverse of matrix A and multiply it with matrix B to obtain the solution matrix X.