Matrices - Invertibility of Matrix
- Today’s topic: Invertibility of Matrix
- An invertible matrix is a square matrix that has an inverse
- A matrix A is invertible if there exists a matrix B such that AB = BA = I, where I is the identity matrix
Conditions for Invertibility
- Matrix has to be a square matrix
- Determinant of the matrix should not be zero
- Matrix should have linearly independent columns or rows
Example: Invertible Matrix
Let’s consider a 3x3 matrix A:
A = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
- A is a square matrix (3x3)
- Determinant of A is non-zero (det(A) ≠ 0)
- Columns of A are linearly independent
Example: Non-Invertible Matrix
Consider a 2x2 matrix B:
B = [[2, 4], [1, 2]]
- B is a square matrix (2x2)
- Determinant of B is zero (det(B) = 0)
- Columns of B are linearly dependent
Properties of Invertible Matrix
- Inverse of an invertible matrix is unique
- If A is invertible, then A^(-1) is also invertible and (A^(-1))^(-1) = A
- If A and B are invertible matrices, then AB is also invertible and (AB)^(-1) = B^(-1) * A^(-1)
- If A is an invertible matrix, then (A^T)^(-1) = (A^(-1))^T
Example: Finding Inverse of a Matrix
Let’s find the inverse of matrix A:
A = [[1, 2], [3, 4]]
- To find A^(-1), we will first compute the determinant of A:
- Next, we will find the adjoint of A by interchanging the elements across the main diagonal:
adj(A) = [[4, -2], [-3, 1]]
- Finally, we can find A^(-1) by dividing the adjoint by the determinant:
A^(-1) = (1/-2) * [[4, -2], [-3, 1]] = [[-2, 1], [3/2, -1/2]]
Properties of Invertible Matrix (Continued)
- If A is an invertible matrix, then the matrix obtained by multiplying any row (or column) of A by a non-zero scalar k is also invertible
- If A is an invertible matrix, then the matrix obtained by adding a multiple of any row (or column) of A to another row (or column) is also invertible
- If A and B are invertible matrices of the same order, then the matrix A * B is invertible, and its inverse is given by B^(-1) * A^(-1)
- The product of two invertible matrices is also invertible, but the product of two non-invertible matrices may or may not be invertible
- If A and B are invertible matrices, then (A^(-1))^(-1) = A and (AB)^(-1) = B^(-1) * A^(-1)
Example: Product of Two Invertible Matrices
Let’s consider two invertible matrices:
A = [[2, 4], [1, 3]] B = [[5, 6], [7, 8]]
- A is an invertible matrix because its determinant is non-zero
- B is also an invertible matrix because its determinant is non-zero
Example: Product of Two Invertible Matrices (Continued)
We can find the product of A and B:
A * B = [[2, 4], [1, 3]] * [[5, 6], [7, 8]] = [[2*5 + 4*7, 2*6 + 4*8], [1*5 + 3*7, 1*6 + 3*8]] = [[38, 52], [26, 36]]
- The resulting matrix AB is also invertible
Example: Inverse of a Product of Two Matrices
Let’s find the inverse of the matrix AB:
(AB)^(-1) = [[38, 52], [26, 36]]^(-1)
- We can find the inverse of AB by finding the inverse of each individual matrix and multiplying them in reverse order
Example: Inverse of a Product of Two Matrices (Continued)
To find the inverse of AB, we can find the inverse of A and B:
A^(-1) = [[2, 4], [1, 3]]^(-1) B^(-1) = [[5, 6], [7, 8]]^(-1)
- We can use the previously discussed method to find the inverse of A and B
Example: Inverse of a Product of Two Matrices (Continued)
Let’s find the inverse of A:
A^(-1) = (1/2) * [[3, -4], [-1, 2]]
- Similarly, let’s find the inverse of B:
B^(-1) = (1/10) * [[8, -6], [-7, 5]]
Example: Inverse of a Product of Two Matrices (Continued)
Now, we can find the inverse of AB by multiplying the inverses of A and B in reverse order:
(AB)^(-1) = [[38, 52], [26, 36]]^(-1) = [[38, 52], [26, 36]]^(-1) = (1/10) * [[36, -52], [-26, 38]]
Invertibility of Identity Matrix
- The identity matrix I is an invertible matrix
- Its inverse is the same matrix I
Example:
I = [[1, 0], [0, 1]]
- I is the identity matrix
- I * I = I
- I^(-1) = I
Singular Matrix
- A square matrix that is not invertible is called a singular matrix or a non-invertible matrix
- A singular matrix has a determinant equal to zero
Example:
S = [[2, 4], [3, 6]]
- The determinant of S is zero
Properties of Singular Matrix
- A singular matrix does not have an inverse
- If A is a singular matrix, then kA is also a singular matrix for any non-zero scalar k
- If A and B are singular matrices of the same order, then AB is also a singular matrix
- If A is a non-singular matrix and k ≠ 0, then kA is a non-singular matrix
- The sum or difference of two non-singular matrices may or may not be non-singular
Example: Inverse of a Singular Matrix
Let’s find the inverse of a singular matrix S:
S = [[2, 4], [3, 6]]
- To find the inverse of S, we first compute the determinant of S:
- Since the determinant is zero, S does not have an inverse.
Finding Inverse using Elementary Row Operations
- The inverse of a matrix can also be found using elementary row operations
- The row operation is performed on the given matrix A, and the same row operation is applied to the identity matrix I
- The final form of matrix A should be the identity matrix, and the final form of the identity matrix should be the inverse of A
Example: Finding Inverse using Row Operations
Let’s find the inverse of matrix A using row operations:
A = [[1, 2], [3, 7]]
- We start with the given matrix A and the identity matrix:
[A | I] = [[1, 2 | 1, 0], [3, 7 | 0, 1]]
- Using row operations, we can transform the matrix A into the identity matrix:
[R2 = R2 - 3R1] [A | I] = [[1, 2 | 1, 0], [0, 1 | -3, 1]] [R1 = R1 - 2R2] [A | I] = [[1, 0 | 7, -2], [0, 1 | -3, 1]]
- The final matrix is the inverse of A:
A^(-1) = [[7, -2], [-3, 1]]
Non-Square Matrices
- Invertibility is applicable only to square matrices
- Non-square matrices do not have an inverse
Example: Non-Invertible Non-Square Matrix
Consider a 2x3 matrix B:
B = [[2, 4, 6], [1, 2, 3]]
- B is a non-square matrix (2x3)
- Since B is not a square matrix, it does not have an inverse
Invertibility and Linear Systems
- Invertible matrices play a crucial role in solving linear systems of equations
- An n x n matrix A is invertible if and only if the system of equations Ax = b has a unique solution for every vector b
- In this case, the unique solution is given by x = A^(-1)b
Example: Solving Linear System using Invertible Matrix
Let’s consider a linear system of equations:
``
5x + 4y = 13
``
- We can represent the linear system in matrix form as Ax = b:
A = [[2, 3], [5, 4]] x = [[x], [y]] b = [[8], [13]]
- Since the matrix A is invertible, we can find the unique solution using x = A^(-1)b.
Cramer’s Rule
- Cramer’s Rule provides a method to solve a linear system of equations using determinants
- The solutions for the variables in the system can be found by evaluating determinants
- The determinant of the coefficient matrix A is denoted as det(A)
Cramer’s Rule for a 2x2 Linear System
Consider a linear system of equations:
ax + by = p cx + dy = q
- The determinant of the coefficient matrix A is given by:
det(A) = ad - bc
- The solutions for the variables x and y can be found using Cramer’s Rule:
x = (pd - bq) / det(A) y = (aq - pc) / det(A)
Example: Solving Linear System using Cramer’s Rule
Let’s solve the following linear system of equations using Cramer’s Rule:
``
5x + 4y = 13
``
- The coefficient matrix A is:
A = [[2, 3], [5, 4]]
- The determinant of A is:
det(A) = 2*4 - 3*5 = -7
- Using Cramer’s Rule, we can find the values of x and y:
x = (8*4 - 3*13) / (-7) = 3 y = (2*13 - 8*5) / (-7) = -1
- Hence, the solution to the linear system is:
x = 3, y = -1