Evaluate the following expressions: a) log_2(8)
b) log_3(1/27)
c) log_5(√5)
Solution: a) log_2(8) = log_2(2^3) = 3
b) log_3(1/27) = log_3(3^-3) = -3
c) log_5(√5) = log_5(5^(1/2)) = 1/2
Solve the following equation for x: log_2(x + 1) - log_2(x - 2) = 3
Solution: log_2(x + 1) - log_2(x - 2) = log_2((x + 1)/(x - 2)) = 3
2^3 = (x + 1)/(x - 2)
8(x - 2) = x + 1
8x - 16 = x + 1
7x = 17
x ≈ 2.43
Given the function y = log_4(x + 2), find the corresponding x-value for y = 2.
Solution: Setting y = 2, we have:
2 = log_4(x + 2)
4^2 = x + 2
16 = x + 2
x = 14
Find the domain and range of the function y = log_2(x - 3).
Solution: For the domain, we have:
x - 3 > 0
x > 3
Domain: (3, ∞)
For the range, since log_2(x - 3) is always positive, the range will be all positive real numbers.
Range: (0, ∞)
Given the function y = log_10(2x - 1), describe the transformations involved.
Solution: This function involves a horizontal shift to the right and a vertical stretch.
Horizontal shift: The function is shifted 1/2 units to the right.
Vertical stretch: The function is stretched vertically by a factor of 2.
Solve the following equation for x: log_4(1 - 3x) = log_4(2 + x)
Solution: Setting the expressions inside log_4 equal to each other, we have:
1 - 3x = 2 + x
4x = -1
x = -1/4
Given the function y = -log_3(2x + 1), describe the transformations involved.
Solution: This function involves a horizontal shift to the left and a reflection about the x-axis.
Horizontal shift: The function is shifted 1/2 units to the left.
Reflection about the x-axis: The function is flipped upside down.
Solve the following equation for x: 3log_5(x) + 2 = 1
Solution: Simplifying the equation, we have:
3log_5(x) = -1
log_5(x) = -1/3
5^(-1/3) = x
1/∛5 = x
Find the domain and range of the function y = log_3(4 - 2x).
Solution: For the domain, we have:
4 - 2x > 0
x < 2
Domain: (-∞, 2)
For the range, since log_3(4 - 2x) is always negative, the range will be all negative real numbers.
Range: (-∞, 0)
Given the function y = 3log_2(x) + 4, describe the transformations involved.
Solution: This function involves a vertical stretch and a vertical shift.
Vertical stretch: The function is stretched vertically by a factor of 3.
Vertical shift: The function is shifted 4 units up.
Evaluate the following expressions: a) log_2(8)
b) log_3(1/27)
c) log_5(√5)
Solution: a) log_2(8) = log_2(2^3) = 3
b) log_3(1/27) = log_3(3^-3) = -3
c) log_5(√5) = log_5(5^(1/2)) = 1/2
Solve the following equation for x: log_2(x + 1) - log_2(x - 2) = 3
Solution: log_2(x + 1) - log_2(x - 2) = log_2((x + 1)/(x - 2)) = 3
2^3 = (x + 1)/(x - 2)
8(x - 2) = x + 1
8x - 16 = x + 1
7x = 17
x ≈ 2.43
Given the function y = log_4(x + 2), find the corresponding x-value for y = 2.
Solution: Setting y = 2, we have:
2 = log_4(x + 2)
4^2 = x + 2
16 = x + 2
x = 14
Find the domain and range of the function y = log_2(x - 3).
Solution: For the domain, we have:
x - 3 > 0
x > 3
Domain: (3, ∞)
For the range, since log_2(x - 3) is always positive, the range will be all positive real numbers.
Range: (0, ∞)
Given the function y = log_10(2x - 1), describe the transformations involved.
Solution: This function involves a horizontal shift to the right and a vertical stretch.
Horizontal shift: The function is shifted 1/2 units to the right.
Vertical stretch: The function is stretched vertically by a factor of 2.
Solve the following equation for x: log_4(1 - 3x) = log_4(2 + x)
Solution: Setting the expressions inside log_4 equal to each other, we have:
1 - 3x = 2 + x
4x = -1
x = -1/4
Given the function y = -log_3(2x + 1), describe the transformations involved.
Solution: This function involves a horizontal shift to the left and a reflection about the x-axis.
Horizontal shift: The function is shifted 1/2 units to the left.
Reflection about the x-axis: The function is flipped upside down.
Solve the following equation for x: 3log_5(x) + 2 = 1
Solution: Simplifying the equation, we have:
3log_5(x) = -1
log_5(x) = -1/3
5^(-1/3) = x
1/∛5 = x
Find the domain and range of the function y = log_3(4 - 2x).
Solution: For the domain, we have:
4 - 2x > 0
x < 2
Domain: (-∞, 2)
For the range, since log_3(4 - 2x) is always negative, the range will be all negative real numbers.
Range: (-∞, 0)
Given the function y = 3log_2(x) + 4, describe the transformations involved.
Solution: This function involves a vertical stretch and a vertical shift.
Vertical stretch: The function is stretched vertically by a factor of 3.
Vertical shift: The function is shifted 4 units up.