Inverse Trigonometric Functions
- Domain, Range, and Graph of secinv(x)
Introduction
- Inverse Trigonometric Functions
- Inverse of secant function (sec⁻¹x)
- Properties and characteristics
Definition
- Inverse of secant function:
- It is the function that extracts the angle whose secant is given.
- sec⁻¹[sinθ/cosθ] = θ
Domain and Range
- The domain of sec⁻¹x is (-∞, -1] ∪ [1, ∞)
- The range is [0, π] ∪ (π, 2π]
Graph of secinv(x)
- The graph of sec⁻¹x is the reflection of the graph of secx with respect to the line y = x.
- It is a non-periodic function.
Graphical Representation
- Graph of sec⁻¹x:
- Increasing function from -∞ to -1
- Decreasing function from 1 to ∞
- Points of interest:
- (1, 0) - Minima
- (-1, π) - Maxima
Important Points
- Minimum value of secinv(x) = 0
- Maximum value of secinv(x) = π
Key Features
- Domain: (-∞, -1] ∪ [1, ∞)
- Range: [0, π] ∪ (π, 2π]
- Reflection of sec(x) graph
- Non-periodic function
Example 1
- Find the value of sec⁻¹(-2).
- Solution:
- The angle whose secant is -2 is π + π/3.
- Therefore, sec⁻¹(-2) = π + π/3 = 4π/3.
Example 2
- Determine the domain and range of sec⁻¹x.
- Solution:
- The domain is (-∞, -1] ∪ [1, ∞).
- The range is [0, π] ∪ (π, 2π].
Properties of sec⁻¹x
- sec⁻¹(-x) = sec⁻¹x
- sec⁻¹(1/x) = cos⁻¹(1/x)
- sec⁻¹(x) + cos⁻¹(x) = π/2
- sec⁻¹x = sin⁻¹(1/√(x²-1))
- sec⁻¹(√x) = sec⁻¹x
Derivatives of sec⁻¹x
- d/dx(sec⁻¹x) = 1/(|x|√(x²-1)), |x| > 1
- d/dx(sec⁻¹x) = -1/(|x|√(x²-1)), |x| < 1
Integration of sec⁻¹x
- ∫sec⁻¹x dx = xsec⁻¹x + ln|x + √(x²-1)| + C
- ∫sec⁻¹x dx = xsec⁻¹x - ln|x - √(x²-1)| + C
Trigonometric Equations
- sec⁻¹x = y, then x = secy
- sec⁻¹(secx) = x
- sec(sec⁻¹x) = x
Trigonometric Identities
- sec⁻¹x = sin⁻¹(1/x)
- sec⁻¹x = cos⁻¹(1/x)
- sec⁻¹x = tan⁻¹(√(x²-1))
Derivation of sec⁻¹x
- Let y = sec⁻¹x, then x = secy
- Differentiating both sides with respect to x:
- 1 = secy * tan y
- tan y = 1/secy = cos y
- y = π/4 or 5π/4
Example 3
- Find the value of sec⁻¹tan⁻¹(3).
- Solution:
- Let y = tan⁻¹(3)
- tan y = 3
- Using the identity tan⁻¹x = π/4 + tan⁻¹(1/x):
- x = secy = sec(π/4 + tan⁻¹(1/3))
Example 4
- Evaluate ∫sec⁻¹(2x) dx.
- Solution:
- Let y = 2x, then x = y/2
- ∫sec⁻¹(2x) dx = ∫sec⁻¹y/2 * (1/2) dy
- Using the integration formula, the result is:
- (1/2)(ysec⁻¹y - ln|y + √(y²-4)|) + C
- Substituting back y = 2x, the final result is obtained.
Summary
- Inverse of secant function is sec⁻¹x or arcsecx.
- It has a domain of (-∞, -1] ∪ [1, ∞) and a range of [0, π] ∪ (π, 2π].
- The graph of sec⁻¹x is the reflection of the graph of secx.
- There are properties, derivatives, and integration formulas for sec⁻¹x.
- Trigonometric equations and identities involving sec⁻¹x can be derived and used.
Recap
- Inverse Trigonometric Functions
- Definitions, properties, and characteristics of sec⁻¹x
- Domain, range, and graph representation
- Derivatives and integration formulas of sec⁻¹x
- Trigonometric equations and identities involving sec⁻¹x
Domain and Range of sec⁻¹x
- The domain of sec⁻¹x is (-∞, -1] ∪ [1, ∞).
- This means that the input x should be either less than -1 or greater than 1.
- The range of sec⁻¹x is [0, π] ∪ (π, 2π].
- This means that the output y lies between 0 and π, excluding π, and also between π and 2π.
Graphical Representation of sec⁻¹x
- The graph of sec⁻¹x is the reflection of the graph of sec x about the line y = x.
- As sec x is a periodic function, the graph of sec⁻¹x is not periodic.
- It is a non-periodic function that exhibits increasing and decreasing behavior.
Graph of sec⁻¹x
- The graph of sec⁻¹x starts from negative infinity and approaches -π/2 as x approaches -∞.
- At x = 1, the graph has a vertical asymptote.
- It reaches a minimum value of 0 at x = -1.
- It has another vertical asymptote at x = -1.
- At x = ∞, the graph approaches π/2.
Key Features of sec⁻¹x
- Domain: (-∞, -1] ∪ [1, ∞)
- Range: [0, π] ∪ (π, 2π]
- Non-periodic function
- Reflection of sec x graph
- Vertical asymptotes at x = -1 and x = 1
- Minimum value at x = -1, which is 0
- Approaches π/2 as x approaches ∞ and -π/2 as x approaches -∞
Derivatives of sec⁻¹x
- The derivative of sec⁻¹x can be found using the chain rule:
- d/dx(sec⁻¹x) = 1/(|x|√(x²-1)), for |x| > 1
- d/dx(sec⁻¹x) = -1/(|x|√(x²-1)), for |x| < 1
- Here, the absolute value of x is taken to ensure the non-negative values in the denominator.
Integration of sec⁻¹x
- The integral of sec⁻¹x can be found by integrating the expression:
- ∫sec⁻¹x dx = xsec⁻¹x - ln|x - √(x²-1)| + C
- ∫sec⁻¹x dx = xsec⁻¹x + ln|x + √(x²-1)| + C
- The constant of integration (C) is added at the end.
Trigonometric Equations
- Inverse trigonometric equations involving sec⁻¹x can be solved by applying the properties of sec⁻¹x.
- For example:
- sec⁻¹x = y, then x = secy
- sec⁻¹(secx) = x
- sec(sec⁻¹x) = x
- These equations can help us find the value of x when the value of the inverse secant function is given, or vice versa.
Trigonometric Identities
- There are several trigonometric identities involving sec⁻¹x:
- sec⁻¹x = sin⁻¹(1/x)
- sec⁻¹x = cos⁻¹(1/x)
- sec⁻¹x = tan⁻¹(√(x²-1))
- These identities relate sec⁻¹x to other inverse trigonometric functions such as sin⁻¹x, cos⁻¹x, and tan⁻¹x.
Summary
- Inverse trigonometric functions provide a way to find angles when the trigonometric ratios are given.
- The domain of sec⁻¹x is (-∞, -1] ∪ [1, ∞), and the range is [0, π] ∪ (π, 2π].
- The graph of sec⁻¹x is the reflection of the graph of sec x about the line y = x.
- The derivatives and integrals of sec⁻¹x can be found using specific formulas.
- Trigonometric equations and identities involving sec⁻¹x can be derived and used for problem-solving.
Recap
- Domain and range of sec⁻¹x
- Graphical representation of sec⁻¹x
- Key features of sec⁻¹x
- Derivatives and integrals of sec⁻¹x
- Trigonometric equations and identities involving sec⁻¹x