The limit of a function f(x) as x approaches a certain value a is denoted as:
lim (x->a) f(x)
It represents the value that the function approaches as x gets arbitrarily close to a
There are various techniques to evaluate the limit of a function:
We will discuss each of these techniques in detail
In this method, we substitute the value for x directly into the function to evaluate the limit
Example:
lim (x->2) (x^2 + x - 6)
Substitute x = 2:
= (2^2 + 2 - 6)
= (4 + 2 - 6)
= 0
In this method, we factorize the function and cancel out common terms to simplify the expression
Example:
lim (x->3) (x^2 - 9) / (x - 3)
Factorize numerator and cancel out common terms:
= lim (x->3) (x - 3)(x + 3) / (x - 3)
= lim (x->3) (x + 3)
= 6
L’Hospital’s rule is a technique used to evaluate limits involving indeterminate forms
Indeterminate forms include 0/0, ∞/∞, 0*∞, ∞ - ∞, etc.
The rule states that if the limit of the ratio of two functions f(x)/g(x) is indeterminate, then the limit of their derivatives f’(x)/g’(x) will give the same result
Example:
lim (x->0) sin(x)/x
Apply L’Hospital’s rule:
= lim (x->0) cos(x)/1
= cos(0)/1
= 1
The Squeeze theorem is used to evaluate limits by comparing the function with two other functions whose limits are known
If the function lies between these two functions for all x, then the limit of the function is the same as the limits of the other two functions
Example:
lim (x->0) x*sin(1/x)
Apply the Squeeze theorem:
-1 <= sin(1/x) <= 1
-x <= x*sin(1/x) <= x
As x approaches 0, the function is squeezed between -x and x:
lim (x->0) -x <= lim (x->0) x*sin(1/x) <= lim (x->0) x
= 0 <= lim (x->0) x*sin(1/x) <= 0
Therefore, the limit is 0
lim (x->4) (2x - 5)
= (2 * 4 - 5)
= (8 - 5)
= 3
lim (x->1) (x^2 - 4) / (x - 1)
= lim (x->1) (x - 2)(x + 2) / (x - 1)
= lim (x->1) (x + 2)
= 3
lim (x->1) (x^2 - 1) / (x - 1)
= lim (x->1) 2x / 1
= 2
lim (x->0) x^2 * sin(1/x)
-1 <= sin(1/x) <= 1
-x^2 <= x^2 * sin(1/x) <= x^2
lim (x->0) -x^2 <= lim (x->0) x^2 * sin(1/x) <= lim (x->0) x^2
= 0 <= lim (x->0) x^2 * sin(1/x) <= 0
lim (x->1) (x^2 - 1) / (x - 1)
= lim (x->1) (1^2 - 1) / (1 - 1)
= 0/0
= lim (x->1) (2x) / 1
= 2
lim (x->0) (3x^2 - 2x)
= lim (x->0) (3*0^2 - 2*0)
= 0
lim (h->0) (s(t + h) - s(t)) / h
= lim (h->0) (5(t + h)^2 + 3(t + h) + 2 - (5t^2 + 3t + 2)) / h
= lim (h->0) (10th + 10h^2 + 3h) / h
= lim (h->0) (10t + 10h + 3)
= 10t + 3
lim (b->∞) ∫(0 to b) e^(-x) dx
= lim (b->∞) [-e^(-x)](0 to b)
= lim (b->∞) (-e^(-b) - (-e^0))
= lim (b->∞) (-e^(-b) + 1)
= 1
lim (t->∞) 2500 / (1 + 9e^(-0.5t))
lim (t->∞) N_0 / (1 + be^(-kt))
lim (t->∞) P(1 + r/n)^(nt)
lim (n->∞) 1/2^n
lim (t->∞) (3t^2 - 2t + 5)