In this lecture, we will solve some examples involving determinants of 3×3 matrices. |
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Find the value of the determinant of the matrix: [ \begin{pmatrix} 2 & 1 & 4 \ 3 & 0 & -2 \ -1 & 3 & 1 \ \end{pmatrix} ]
To compute the determinant, we can use the formula: [ \text{det}(A) = a_{11}C_{11} + a_{12}C_{12} + a_{13}C_{13} ] Where (a_{ij}) represents the entry in the (i)th row and (j)th column, and (C_{ij}) represents the cofactor of (a_{ij}).
Let’s calculate the cofactors:
Using the determinants of the cofactor matrices, we can now calculate the determinant of the original matrix: [ \text{det}(A) = 2(6) + 1C_{12} + 4C_{13} ]
Thus, the value of the determinant is (12 + C_{12} + 4C_{13}). |
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Find the value of the determinant of the matrix: [ \begin{pmatrix} -3 & 0 & 2 \ 1 & -2 & 0 \ 4 & 1 & -1 \ \end{pmatrix} ]
Using the formula for the determinant, we have: [ \text{det}(A) = -3C_{11} + 0C_{12} + 2C_{13} ]
To calculate (C_{11}):
Using the determinants of the cofactor matrices, we can now calculate the determinant of the original matrix: [ \text{det}(A) = -3(2) + 0C_{12} + 2C_{13} ]
Thus, the value of the determinant is (-6 + 2C_{13}). |
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Find the value of the determinant of the matrix: [ \begin{pmatrix} 1 & 2 & 1 \ 1 & -1 & 0 \ 3 & 1 & -2 \ \end{pmatrix} ]
Using the formula for the determinant, we have: [ \text{det}(A) = 1C_{11} - 2C_{12} + 1C_{13} ]
To calculate (C_{11}):
To calculate (C_{12}):
To calculate (C_{13}):
Using the determinants of the cofactor matrices, we can now calculate the determinant of the original matrix: [ \text{det}(A) = 1(2) - 2(-2) + 1(-4) ]
Thus, the value of the determinant is (2 + 4 + (-4) = 2). |
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This concludes the first three examples. We will continue solving more examples in the next set of slides. |