Determinants - Examples on Area of triangles
- In this lesson, we will learn how to calculate the area of triangles using determinants.
- Determinant is a mathematical concept used to solve a system of linear equations.
- Determinant of a matrix is denoted by |A| or det(A), where A is the given matrix.
- The formula to calculate the area of a triangle using determinants is:
- Area = 1/2 * determinant of matrix
Example 1:
Find the area of a triangle with vertices at (1, 2), (3, 4), and (5, 6).
Solution:
Let’s first create a matrix using the given coordinates:
A = | 1 2 |
| 3 4 |
| 5 6 |
Now, calculate the determinant of A:
det(A) = (1 * 4) - (3 * 2) = 4 - 6 = -2
Finally, plug the determinant value into the area formula:
Area = 1/2 * (-2) = -1
Therefore, the area of the triangle is -1 square units.
Example 2:
Find the area of a triangle with vertices at (-2, 1), (4, -3), and (5, 2).
Solution:
Let’s create the matrix A using the given coordinates:
A = | -2 1 |
| 4 -3 |
| 5 2 |
Calculate the determinant of matrix A:
det(A) = (-2 * -3) - (1 * 4) = 6 - 4 = 2
Using the area formula, we have:
Area = 1/2 * 2 = 1
Hence, the area of the triangle is 1 square unit.
Remember: The area of a triangle cannot be negative.
Example 3:
Let’s consider a triangle with vertices at (-1, 0), (2, 5), and (4, 1).
Solution:
Construct the matrix A using the given coordinates:
A = | -1 0 |
| 2 5 |
| 4 1 |
Find the determinant of matrix A:
det(A) = (-1 * 5) - (0 * 2) = -5
Using the area formula, we get:
Area = 1/2 * (-5) = -2.5
Thus, the area of the triangle is -2.5 square units.
- Determinants - Examples on Area of triangles
- In this lesson, we will continue exploring examples on calculating the area of triangles using determinants.
- Determinants are a powerful tool for solving systems of linear equations and finding the area of geometric shapes.
- The formula to calculate the area of a triangle using determinants is: Area = 1/2 * determinant of matrix
- Example 4:
- Find the area of a triangle with vertices at (0, 0), (3, 4), and (6, 0).
- Matrix A: | 0 0 |
| 3 4 |
| 6 0 |
- Calculate the determinant of A: det(A) = (0 * 4) - (0 * 3) = 0
- Using the area formula, we have: Area = 1/2 * 0 = 0
- Therefore, the area of the triangle is 0 square units, which indicates that the points are collinear.
- Example 5:
- Consider a triangle with vertices at (2, 1), (-3, 5), and (1, 6).
- Matrix A: | 2 1 |
| -3 5 |
| 1 6 |
- Calculate the determinant of A: det(A) = (2 * 5) - (1 * -3) = 7
- Using the area formula, we get: Area = 1/2 * 7 = 3.5
- Thus, the area of the triangle is 3.5 square units.
- Example 6:
- Find the area of a triangle with vertices at (-4, -5), (-2, 3), and (0, -1).
- Matrix A: | -4 -5 |
| -2 3 |
| 0 -1 |
- Calculate the determinant of A: det(A) = (-4 * 3) - (-5 * -2) = -2
- Using the area formula, we have: Area = 1/2 * (-2) = -1
- The negative area indicates that the triangle is oriented clockwise.
- Hence, the area of the triangle is -1 square unit.
- Alternate Formula for Area:
- While we have been using the determinant formula, there is an alternate formula for finding the area of a triangle using coordinates.
- Given points (x₁, y₁), (x₂, y₂), and (x₃, y₃), the area can be calculated as follows:
- Area = 1/2 * |x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|
- Example 7:
- Find the area of a triangle with vertices at (1, 2), (-3, 5), and (5, 6) using the alternate formula.
- Area = 1/2 * |1(5-6) - (-3)(6-2) + 5(2-5)|
= 1/2 * |-1 - (-12) + 15|
= 1/2 * |-1 + 12 + 15|
= 1/2 * 26
= 13
- Therefore, the area of the triangle is 13 square units.
- Example 8:
- Calculate the area of a triangle with vertices at (-1, 4), (3, -2), and (7, 1) using the alternate formula.
- Area = 1/2 * |-1(-2-1) + 3(1-4) + 7(4-(-2))|
= 1/2 * |-1 - 9 + 42|
= 1/2 * 32
= 16
- Hence, the area of the triangle is 16 square units.
- Properties of Triangle Area:
- The area of a triangle is always positive, irrespective of the orientation of the points.
- The area is zero if the points are collinear.
- The area remains the same when the triangle is translated, rotated, or scaled.
- Summary:
- Determinants help calculate the area of triangles.
- The formula for calculating the area using determinants is: Area = 1/2 * determinant of matrix.
- The alternate formula uses coordinates and is: Area = 1/2 * |x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|
- The area of a triangle is always positive, except when it’s zero for collinear points.
- The area remains unchanged under transformations.
- Practice Questions
- Find the area of a triangle with vertices at (6, 3), (2, 7), and (-1, -4).
- Calculate the area of a triangle with vertices at (-2, 3), (3, -5), and (4, 1).
- Using determinants, find the area of a triangle with vertices at (0, 0), (5, 0), and (3, 2).
- Find the area of a triangle with vertices at (4, 2), (1, 3), and (-2, 0) using the alternate formula.
- Calculate the area of a triangle with vertices at (-4, -1), (3, 2), and (0, -3) using determinants.
- Example 9:
- Find the area of a triangle with vertices at (2, -3), (-5, 4), and (3, 6) using the alternate formula.
- Area = 1/2 * |2(4-6) + (-5)(6-(-3)) + 3((-3)-4)|
= 1/2 * |-4 - (-45) + (-21)|
= 1/2 * 20
= 10
- Hence, the area of the triangle is 10 square units.
- Example 10:
- Calculate the area of a triangle with vertices at (-3, 2), (1, -1), and (-4, 5) using the alternate formula.
- Area = 1/2 * |-3(-1-5) + 1(5-2) + (-4)(2-(-1))|
= 1/2 * |18 + 3 + (-6)|
= 1/2 * 15
= 7.5
- Therefore, the area of the triangle is 7.5 square units.
- Example 11:
- Find the area of a triangle with vertices at (0, 0), (6, 0), and (4, 3) using determinants.
- Matrix A: | 0 0 |
| 6 0 |
| 4 3 |
- Calculate the determinant of A: det(A) = (0 * 0) - (0 * 6) = 0
- Using the area formula, we have: Area = 1/2 * 0 = 0
- Thus, the area of the triangle is 0 square units, indicating that the points are collinear.
- Example 12:
- Calculate the area of a triangle with vertices at (-4, -1), (3, 2), and (0, -3) using determinants.
- Matrix A: | -4 -1 |
| 3 2 |
| 0 -3 |
- Calculate the determinant of A: det(A) = (-4 * 2) - (-1 * 3) = -5
- Using the area formula, we have: Area = 1/2 * (-5) = -2.5
- Hence, the area of the triangle is -2.5 square units.
- Summary:
- Determinants can be used to find the area of triangles.
- The area can be calculated using the determinant formula: Area = 1/2 * determinant of matrix.
- Alternatively, the area can be found using the coordinates: Area = 1/2 * |x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|.
- The area is always positive, except when it’s zero for collinear points.
- Transformations such as translation, rotation, or scaling do not change the area.
- Practice Questions
- Find the area of a triangle with vertices at (3, 4), (-2, -5), and (7, 0) using the alternate formula.
- Calculate the area of a triangle with vertices at (0, -2), (4, 1), and (-1, 5) using the alternate formula.
- Using determinants, find the area of a triangle with vertices at (2, 0), (-1, 3), and (0, -1).
- Find the area of a triangle with vertices at (-5, 2), (1, -3), and (3, 4) using the alternate formula.
- Calculate the area of a triangle with vertices at (-2, 0), (4, 3), and (6, 2) using determinants.
- Formulas for Area:
- Determinants: Area = 1/2 * determinant of matrix
- Alternate formula: Area = 1/2 * |x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|
- Triangle area cannot be negative, except when the points are collinear.
- Area remains unchanged under transformations.
- Example 13:
- Find the area of a triangle with vertices at (1, 1), (4, -2), and (7, 3) using the alternate formula.
- Area = 1/2 * |1(-2-3) + 4(3-1) + 7(1-(-2))|
= 1/2 * |-2 + 8 + 21|
= 1/2 * 27
= 13.5
- Hence, the area of the triangle is 13.5 square units.
- Example 14:
- Calculate the area of a triangle with vertices at (0, -4), (3, 0), and (-1, 2) using the alternate formula.
- Area = 1/2 * |0(0-2) + 3(2+4) + (-1)(-4-0)|
= 1/2 * |0 + 18 + 4|
= 1/2 * 22
= 11
- Therefore, the area of the triangle is 11 square units.
- Recap:
- Determinants can be used to calculate the area of triangles.
- The formula using determinants is: Area = 1/2 * determinant of matrix.
- Alternatively, the area can be found using the coordinates with the alternate formula.
- Area is always positive, except when it’s 0 for collinear points.
- Transformations do not change the area of a triangle.
Please note that the slide numbers are not included in the slides.