Definite Integral - Special function
- In this topic, we will discuss special functions of definite integrals.
- Special functions are those integrals that have specific properties or require special techniques to evaluate.
- We will focus on four special functions:
- Definite integrals of polynomials
- Definite integrals of exponential functions
- Definite integrals of trigonometric functions
- Definite integrals of logarithmic functions
- Let’s start with the first special function.
Definite integrals of polynomials
- A polynomial is an algebraic expression comprising variables, coefficients, and exponents.
- The definite integral of a polynomial can be evaluated using the power rule.
- The power rule states that if we have a polynomial of the form (f(x) = ax^n), where (a) and (n) are constants, then the definite integral of (f(x)) is given by:
[\int_{a}^{b} f(x)dx = \frac{a}{n+1}(b^{n+1} - a^{n+1})]
- Example 1:
Let’s evaluate the definite integral of (f(x) = 2x^3 - 3x^2 + 5x - 2) from 0 to 2 using the power rule.
[\int_{0}^{2} f(x)dx = \int_{0}^{2} (2x^3 - 3x^2 + 5x - 2)dx]
[= \frac{2}{4}(2^4 - 0^4) - \frac{3}{3}(2^3 - 0^3) + \frac{5}{2}(2^2 - 0^2) - 2(2 - 0)]
Definite integrals of exponential functions
- Exponential functions have the form (f(x) = a^x), where (a) is a constant.
- The definite integral of an exponential function can be evaluated using a logarithmic substitution.
- The logarithmic substitution involves substituting (u = \ln(a)x) and (du = \frac{\ln(a)}{x}dx).
- Example 1:
Let’s evaluate the definite integral of (f(x) = e^x) from 0 to 1 using a logarithmic substitution.
[\int_{0}^{1} f(x)dx = \int_{0}^{1} e^xdx]
Let (u = \ln(e)x = x) and (du = dx).
[\int_{0}^{1} e^xdx = \int_{0}^{1} e^udu = \int_{0}^{1} e^udu]
[= [e^u]_{0}^{1} = e^1 - e^0 = e - 1]
Definite integrals of trigonometric functions
- Trigonometric functions, such as sine, cosine, and tangent, are commonly encountered in definite integrals.
- The definite integral of trigonometric functions can be evaluated using various trigonometric identities and properties.
- Example 1:
Let’s evaluate the definite integral of (f(x) = \sin(x)) from 0 to (\pi) using trigonometric identities.
[\int_{0}^{\pi} f(x)dx = \int_{0}^{\pi} \sin(x)dx]
[= [-\cos(x)]_{0}^{\pi} = -(\cos(\pi) - \cos(0)) = -(-1 - 1) = 2]
- Example 2:
Let’s evaluate the definite integral of (f(x) = \cos(x)) from 0 to (\frac{\pi}{2}) using trigonometric identities.
[\int_{0}^{\frac{\pi}{2}} f(x)dx = \int_{0}^{\frac{\pi}{2}} \cos(x)dx]
[= [\sin(x)]_{0}^{\frac{\pi}{2}} = (\sin(\frac{\pi}{2}) - \sin(0)) = (1 - 0) = 1]
Definite integrals of logarithmic functions
- Logarithmic functions have the form (f(x) = \ln(x)), where (x) is a positive real number.
- The definite integral of a logarithmic function can be evaluated using integration by parts.
- Integration by parts involves choosing one part of the integrand as the “first” part and differentiating it, while integrating the remaining part as the “second” part.
- Example 1:
Let’s evaluate the definite integral of (f(x) = \ln(x)) from 1 to 2 using integration by parts.
[\int_{1}^{2} f(x)dx = \int_{1}^{2} \ln(x)dx]
Let (u = \ln(x)) and (dv = dx).
[du = \frac{1}{x}dx \quad \text{and} \quad v = x]
Using the integration by parts formula:
[\int u dv = uv - \int v du]
[\int_{1}^{2} \ln(x)dx = [x\ln(x)]{1}^{2} - \int{1}^{2}x\left(\frac{1}{x}dx\right)]
[= \left[2\ln(2) - 1\ln(1)\right] - \left[\int_{1}^{2} dx\right]]
[= 2\ln(2) - 1 - (2 - 1)]
Summary
- In this lecture, we covered four special functions of definite integrals:
- Definite integrals of polynomials
- Definite integrals of exponential functions
- Definite integrals of trigonometric functions
- Definite integrals of logarithmic functions
- Special techniques such as power rule, logarithmic substitution, trigonometric identities, and integration by parts were used to evaluate these special functions.
- Understanding and applying these techniques will help you solve complex definite integrals with ease.
Definite Integral - Special function
Slide 11
- In this topic, we will discuss special functions of definite integrals.
- Special functions are those integrals that have specific properties or require special techniques to evaluate.
- We will focus on four special functions:
- Definite integrals of polynomials
- Definite integrals of exponential functions
- Definite integrals of trigonometric functions
- Definite integrals of logarithmic functions
Slide 12
- Let’s start with the first special function: Definite integrals of polynomials.
- A polynomial is an algebraic expression comprising variables, coefficients, and exponents.
- The definite integral of a polynomial can be evaluated using the power rule.
- The power rule states that if we have a polynomial of the form (f(x) = ax^n), where (a) and (n) are constants, then the definite integral of (f(x)) is given by:
[\int_{a}^{b} f(x)dx = \frac{a}{n+1}(b^{n+1} - a^{n+1})]
Slide 13
- Example 1:
Let’s evaluate the definite integral of (f(x) = 2x^3 - 3x^2 + 5x - 2) from 0 to 2 using the power rule.
[\int_{0}^{2} f(x)dx = \int_{0}^{2} (2x^3 - 3x^2 + 5x - 2)dx]
[= \frac{2}{4}(2^4 - 0^4) - \frac{3}{3}(2^3 - 0^3) + \frac{5}{2}(2^2 - 0^2) - 2(2 - 0)]
Slide 14
- Let’s move on to the second special function: Definite integrals of exponential functions.
- Exponential functions have the form (f(x) = a^x), where (a) is a constant.
- The definite integral of an exponential function can be evaluated using a logarithmic substitution.
- The logarithmic substitution involves substituting (u = \ln(a)x) and (du = \frac{\ln(a)}{x}dx).
Slide 15
- Example 1:
Let’s evaluate the definite integral of (f(x) = e^x) from 0 to 1 using a logarithmic substitution.
[\int_{0}^{1} f(x)dx = \int_{0}^{1} e^xdx]
Let (u = \ln(e)x = x) and (du = dx).
[\int_{0}^{1} e^xdx = \int_{0}^{1} e^udu = \int_{0}^{1} e^udu]
[= [e^u]_{0}^{1} = e^1 - e^0 = e - 1]
Slide 16
- Let’s now discuss the third special function: Definite integrals of trigonometric functions.
- Trigonometric functions, such as sine, cosine, and tangent, are commonly encountered in definite integrals.
- The definite integral of trigonometric functions can be evaluated using various trigonometric identities and properties.
Slide 17
- Example 1:
Let’s evaluate the definite integral of (f(x) = \sin(x)) from 0 to (\pi) using trigonometric identities.
[\int_{0}^{\pi} f(x)dx = \int_{0}^{\pi} \sin(x)dx]
[= [-\cos(x)]_{0}^{\pi} = -(\cos(\pi) - \cos(0)) = -(-1 - 1) = 2]
Slide 18
- Example 2:
Let’s evaluate the definite integral of (f(x) = \cos(x)) from 0 to (\frac{\pi}{2}) using trigonometric identities.
[\int_{0}^{\frac{\pi}{2}} f(x)dx = \int_{0}^{\frac{\pi}{2}} \cos(x)dx]
[= [\sin(x)]_{0}^{\frac{\pi}{2}} = (\sin(\frac{\pi}{2}) - \sin(0)) = (1 - 0) = 1]
Slide 19
- Let’s move on to the last special function: Definite integrals of logarithmic functions.
- Logarithmic functions have the form (f(x) = \ln(x)), where (x) is a positive real number.
- The definite integral of a logarithmic function can be evaluated using integration by parts.
- Integration by parts involves choosing one part of the integrand as the “first” part and differentiating it, while integrating the remaining part as the “second” part.
Slide 20
- Example 1:
Let’s evaluate the definite integral of (f(x) = \ln(x)) from 1 to 2 using integration by parts.
[\int_{1}^{2} f(x)dx = \int_{1}^{2} \ln(x)dx]
Let (u = \ln(x)) and (dv = dx).
[du = \frac{1}{x}dx \quad \text{and} \quad v = x]
Using the integration by parts formula:
[\int u dv = uv - \int v du]
[\int_{1}^{2} \ln(x)dx = [x\ln(x)]{1}^{2} - \int{1}^{2}x\left(\frac{1}{x}dx\right)]
[= \left[2\ln(2) - 1\ln(1)\right] - \left[\int_{1}^{2} dx\right]]
[= 2\ln(2) - 1 - (2 - 1)]
Definite integrals of polynomials
- A polynomial is an algebraic expression with variables, coefficients, and exponents.
- The definite integral of a polynomial can be evaluated using the power rule.
- The power rule states: (\int_{a}^{b} ax^n dx = \frac{a}{n+1}(b^{n+1} - a^{n+1})).
- Example 1: (\int_{0}^{2}(2x^3 - 3x^2 + 5x - 2)dx).
Definite integrals of exponential functions
- Exponential functions have the form (f(x) = a^x), where (a) is a constant.
- The definite integral of an exponential function can be evaluated using logarithmic substitution.
- Logarithmic substitution: (u = \ln(a)x) and (du = \frac{\ln(a)}{x}dx).
- Example 1: (\int_{0}^{1}e^xdx).
Definite integrals of trigonometric functions
- Trigonometric functions, like sine, cosine, and tangent, often appear in definite integrals.
- Various trigonometric identities and properties can be used to evaluate definite integrals.
- Example 1: (\int_{0}^{\pi}\sin(x)dx).
- Example 2: (\int_{0}^{\frac{\pi}{2}}\cos(x)dx).
Definite integrals of logarithmic functions
- Logarithmic functions take the form (f(x) = \ln(x)), where (x) is a positive real number.
- The definite integral of a logarithmic function can be evaluated using integration by parts.
- Integration by parts involves differentiating one part and integrating the other.
- Example 1: (\int_{1}^{2}\ln(x)dx).
Summary
- Definite integrals of special functions require specific techniques to evaluate.
- Polynomials can be integrated using the power rule.
- Exponential functions can be integrated using logarithmic substitution.
- Trigonometric functions can be integrated using trigonometric identities.
- Logarithmic functions can be integrated using integration by parts.
Summary (continued)
- Example 1: (\int_{0}^{2}(2x^3 - 3x^2 + 5x - 2)dx).
- Example 2: (\int_{0}^{1}e^xdx).
- Example 3: (\int_{0}^{\pi}\sin(x)dx).
- Example 4: (\int_{0}^{\frac{\pi}{2}}\cos(x)dx).
- Example 5: (\int_{1}^{2}\ln(x)dx).
Tips for solving definite integrals
- Understand the properties and rules of each special function.
- Identify the appropriate technique for the given integral.
- Use correct substitution methods where applicable.
- Pay attention to integration limits.
- Check your answers by differentiating the result.
Tips for solving definite integrals (continued)
- Practice solving various examples and exercises.
- Memorize important identities and formulas.
- Take note of common patterns and shortcuts.
- Work on improving your algebraic manipulation skills.
- Seek help or clarification when needed.
- Evaluate (\int_{0}^{4}(3x^2 - 2x + 1)dx).
- Find (\int_{1}^{3}e^xdx).
- Calculate (\int_{0}^{\frac{\pi}{4}}\sin(x)dx).
- Determine (\int_{0}^{\frac{\pi}{6}}\cos(x)dx).
- Solve (\int_{1}^{4}\ln(x)dx).
Practice questions (continued)
- Evaluate (\int_{0}^{4}(3x^2 - 2x + 1)dx).
- Find (\int_{1}^{3}e^xdx).
- Calculate (\int_{0}^{\frac{\pi}{4}}\sin(x)dx).
- Determine (\int_{0}^{\frac{\pi}{6}}\cos(x)dx).
- Solve (\int_{1}^{4}\ln(x)dx).