- In this lecture, we will be solving miscellaneous problems related to complex functions using definite integral and certain properties.
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Example 1: Find the value of $\int_{0}^{\infty} e^{-ax}\cos(bx) , dx$, with $a>0$ and $b^2>a$.
- Solution:
- Let’s consider the function $I(a) = \int_{0}^{\infty} e^{-ax}\cos(bx) , dx$.
- Differentiating both sides of the equation with respect to $a$, we get:
- $\frac{d}{da} I(a) = -\int_{0}^{\infty} xe^{-ax}\cos(bx) , dx$
- Now, differentiating the above equation again, we have:
- $\frac{d^2}{da^2} I(a) = \int_{0}^{\infty} x^2e^{-ax}\cos(bx) , dx$
- Substituting $a = \frac{1}{b^2}$ and integrating by parts, we can obtain the final value.
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Example 2: Evaluate $\int_{0}^{1} \frac{\ln(1+x)}{1+x^2} , dx$.
- Solution:
- We can first make the substitution $x = \tan(t)$.
- This will transform the integral into $\int_{0}^{\frac{\pi}{4}} \ln(1+\tan(t)) , dt$.
- Then, we can use the properties of definite integrals and certain trigonometric identities to simplify the expression.
-
Example 3: Calculate $\int_{0}^{\pi} \frac{x}{1+\sin(x)} , dx$.
- Solution:
- Using the substitution $u = \pi - x$, we can convert the integral into $\int_{0}^{\pi} \frac{\pi - u}{1 + \sin(u)} , du$.
- Adding the two integrals together, we get $\int_{0}^{\pi} \pi , du$.
- Simplifying further, the integral evaluates to $\pi^2$.
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Example 4: Find $\int_{0}^{1} \frac{\ln(x)}{\sqrt{1-x^2}} , dx$.
- Solution:
- Using the substitution $x = \sin(t)$, we can rewrite the integral as $\int_{0}^{\frac{\pi}{2}} \frac{\ln(\sin(t))}{\cos(t)} , dt$.
- Applying certain trigonometric identities and using properties of definite integrals, we will obtain the final result.
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Example 5: Determine $\int_{0}^{1} \frac{x^3}{(1-x^2)^4} , dx$.
- Solution:
- By using partial fraction decomposition, we can break the integrand into simpler fractions.
- This will allow us to solve each fraction separately and obtain the final result.
11. Definite Integral - Miscellaneous Problems (Related to Complex Function) - Examples
- Example 1: Find the value of $\int_{0}^{\infty} e^{-ax}\cos(bx) , dx$, with $a>0$ and $b^2>a$.
- Solution:
- Let’s consider the function $I(a) = \int_{0}^{\infty} e^{-ax}\cos(bx) , dx$.
- Differentiating both sides of the equation with respect to $a$, we get: $\frac{d}{da} I(a) = -\int_{0}^{\infty} xe^{-ax}\cos(bx) , dx$.
- Now, differentiating the above equation again, we have: $\frac{d^2}{da^2} I(a) = \int_{0}^{\infty} x^2e^{-ax}\cos(bx) , dx$.
- Substituting $a = \frac{1}{b^2}$ and integrating by parts, we can obtain the final value.
- Example 2: Evaluate $\int_{0}^{1} \frac{\ln(1+x)}{1+x^2} , dx$.
- Solution:
- We can first make the substitution $x = \tan(t)$.
- This will transform the integral into $\int_{0}^{\frac{\pi}{4}} \ln(1+\tan(t)) , dt$.
- Then, we can use the properties of definite integrals and certain trigonometric identities to simplify the expression.
- Example 3: Calculate $\int_{0}^{\pi} \frac{x}{1+\sin(x)} , dx$.
- Solution:
- Using the substitution $u = \pi - x$, we can convert the integral into $\int_{0}^{\pi} \frac{\pi - u}{1 + \sin(u)} , du$.
- Adding the two integrals together, we get $\int_{0}^{\pi} \pi , du$.
- Simplifying further, the integral evaluates to $\pi^2$.
- Example 4: Find $\int_{0}^{1} \frac{\ln(x)}{\sqrt{1-x^2}} , dx$.
- Solution:
- Using the substitution $x = \sin(t)$, we can rewrite the integral as $\int_{0}^{\frac{\pi}{2}} \frac{\ln(\sin(t))}{\cos(t)} , dt$.
- Applying certain trigonometric identities and using properties of definite integrals, we will obtain the final result.
- Example 5: Determine $\int_{0}^{1} \frac{x^3}{(1-x^2)^4} , dx$.
- Solution:
- By using partial fraction decomposition, we can break the integrand into simpler fractions.
- This will allow us to solve each fraction separately and obtain the final result.
Slide 21
Definite Integral - Miscellaneous Problems (Related to Complex Function)
- Examples
-
Find the value of $\int_{0}^{\infty} e^{-ax}\cos(bx) , dx$, with $a>0$ and $b^2>a$.
- Solution:
- Let’s consider the function $I(a) = \int_{0}^{\infty} e^{-ax}\cos(bx) , dx$.
- Differentiating both sides of the equation with respect to $a$, we get:
- $\frac{d}{da} I(a) = -\int_{0}^{\infty} xe^{-ax}\cos(bx) , dx$
- Now, differentiating the above equation again, we have:
- $\frac{d^2}{da^2} I(a) = \int_{0}^{\infty} x^2e^{-ax}\cos(bx) , dx$
- Substituting $a = \frac{1}{b^2}$ and integrating by parts, we can obtain the final value.
-
Evaluate $\int_{0}^{1} \frac{\ln(1+x)}{1+x^2} , dx$.
- Solution:
- We can first make the substitution $x = \tan(t)$.
- This will transform the integral into $\int_{0}^{\frac{\pi}{4}} \ln(1+\tan(t)) , dt$.
- Then, we can use the properties of definite integrals and certain trigonometric identities to simplify the expression.
Slide 22
Definite Integral - Miscellaneous Problems (Related to Complex Function)
-
Examples
3. Calculate $\int_{0}^{\pi} \frac{x}{1+\sin(x)} , dx$.
- Solution:
- Using the substitution $u = \pi - x$, we can convert the integral into $\int_{0}^{\pi} \frac{\pi - u}{1 + \sin(u)} \, du$.
- Adding the two integrals together, we get $\int_{0}^{\pi} \pi \, du$.
- Simplifying further, the integral evaluates to $\pi^2$.
-
Find $\int_{0}^{1} \frac{\ln(x)}{\sqrt{1-x^2}} , dx$.
- Solution:
- Using the substitution $x = \sin(t)$, we can rewrite the integral as $\int_{0}^{\frac{\pi}{2}} \frac{\ln(\sin(t))}{\cos(t)} , dt$.
- Applying certain trigonometric identities and using properties of definite integrals, we will obtain the final result.
-
Determine $\int_{0}^{1} \frac{x^3}{(1-x^2)^4} , dx$.
- Solution:
- By using partial fraction decomposition, we can break the integrand into simpler fractions.
- This will allow us to solve each fraction separately and obtain the final result.
Slide 23
Definite Integral - Miscellaneous Problems (Related to Complex Function)
-
Example 1 Summary:
- $\int_{0}^{\infty} e^{-ax}\cos(bx) , dx$
- $a>0$ and $b^2>a$
- Differentiate twice to obtain the final value
-
Example 2 Summary:
- $\int_{0}^{1} \frac{\ln(1+x)}{1+x^2} , dx$
- Substitute $x = \tan(t)$ and simplify using properties of definite integrals and trigonometric identities
Slide 24
Definite Integral - Miscellaneous Problems (Related to Complex Function)
-
Example 3 Summary:
- $\int_{0}^{\pi} \frac{x}{1+\sin(x)} , dx$
- Use the substitution $u = \pi - x$ and simplify to obtain the final result
-
Example 4 Summary:
- $\int_{0}^{1} \frac{\ln(x)}{\sqrt{1-x^2}} , dx$
- Substitute $x = \sin(t)$ and apply trigonometric identities and properties of definite integrals
-
Example 5 Summary:
- $\int_{0}^{1} \frac{x^3}{(1-x^2)^4} , dx$
- Break the integrand into partial fractions and solve separately to obtain the final result
Slide 25
Definite Integral - Miscellaneous Problems (Related to Complex Function)
-
Recap of the Examples
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Example 1:
- Value of $\int_{0}^{\infty} e^{-ax}\cos(bx) , dx$ for $a>0$ and $b^2>a$
-
Example 2:
- Evaluation of $\int_{0}^{1} \frac{\ln(1+x)}{1+x^2} , dx$
-
Example 3:
- Calculation of $\int_{0}^{\pi} \frac{x}{1+\sin(x)} , dx$
Slide 26
Definite Integral - Miscellaneous Problems (Related to Complex Function)
-
Recap of the Examples
-
Example 4:
- Finding $\int_{0}^{1} \frac{\ln(x)}{\sqrt{1-x^2}} , dx$
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Example 5:
- Determining $\int_{0}^{1} \frac{x^3}{(1-x^2)^4} , dx$
Slide 27
Definite Integral - Miscellaneous Problems (Related to Complex Function)
- Key Takeaways
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Definite integrals can be used to solve a wide range of problems related to complex functions.
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Properties of definite integrals, along with certain substitutions and trigonometric identities, can simplify the calculations.
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Differentiating and integrating twice can help solve specific types of problems.
Slide 28
Definite Integral - Miscellaneous Problems (Related to Complex Function)
- Key Takeaways
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Substitution technique, such as $x = \tan(t)$ or $x = \sin(t)$, can often simplify the integration process.
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Breaking the integrand into partial fractions allows us to solve each fraction separately and obtain the final result.
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It is important to carefully analyze the conditions and properties of the given integral to determine the appropriate approach.
Slide 29
Definite Integral - Miscellaneous Problems (Related to Complex Function)
- Practice Problems
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Find the value of $\int_{0}^{\infty} e^{-2x}\sin(3x) , dx$.
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Evaluate $\int_{0}^{1} \frac{x^2}{\sqrt{1-x^2}} , dx$.
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Calculate $\int_{0}^{2\pi} \frac{\sin^2(x)}{1+\cos^2(x)} , dx$.
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Find $\int_{0}^{1} \frac{1}{x^2 + 1} , dx$.
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Determine $\int_{0}^{\frac{\pi}{2}} \frac{\sin(2x)}{1+\cos^2(x)} , dx$.
Slide 30
Definite Integral - Miscellaneous Problems (Related to Complex Function)
- Stay curious and keep practicing!
- Practice makes perfect, so make sure to attempt more problems and explore different approaches.
- If you have any questions or need further clarification, feel free to ask.
- Good luck with your studies and remember, maths is all about continuous learning and exploration!