Aldehydes, Ketones & Carboxylic Acids - Chemical Reactions (Cleavage Of O-H bond)
- Aldehydes and ketones undergo cleavage of the O-H bond under specific conditions
- Cleavage of the O-H bond leads to the formation of a new compound
- This reaction plays a crucial role in the synthesis of various organic compounds
- Let’s explore some examples and equations for this reaction
- Remember, the O-H bond cleavage occurs through nucleophilic or acidic cleavage mechanisms
Nucleophilic Cleavage of O-H Bond
- In nucleophilic cleavage, a nucleophile attacks the carbonyl carbon of aldehydes/ketones
- This reaction results in the formation of two new compounds
Example:
R | R-C=O + Nu^(-) → (R-C)-O(-)Nu + R' | H
- Here, R and R’ denote alkyl or aryl groups, and Nu represents a nucleophile
Nucleophilic Cleavage of O-H Bond (contd.)
- Let’s explore some notable examples of nucleophilic cleavage reactions:
- Reaction with Grignard reagents:
R | R-C=O + R'-Mg-X → (R-C)-O(-)MgX + R' | H
- Reaction with Sodium cyanide:
R | R-C=O + NaCN → (R-C)-O(-)CN + Na^+ | H
- Reaction with Hydrazine derivatives:
R | R-C=O + NH_2-NH_2 → (R-C)-O(-)NH-NH_2 + H_2O | H
Acidic Cleavage of O-H Bond
- In acidic cleavage, water or other water molecules act as an acid and donate a proton
- This reaction results in the formation of an alcohol as one product
Example:
R | R-C=O + H_2O → R-C-(OH_2)^+ + OH^(-) | H
- Here, R represents an alkyl or aryl group
Acidic Cleavage of O-H Bond (contd.)
- Let’s look at some examples of acidic cleavage reactions:
- Reaction with dilute mineral acids:
R | R-C=O + H_2SO_4 → R-C-(OH_2)^+ + HSO_4^(-) | H
- Reaction with dilute alkali:
R | R-C=O + NaOH → R-C-(OH_2)^+ + Na^+ | H
- Reaction with phenols:
R | R-C=O + PhOH → R-C-(OH_2)^+ + PhO^(-) | H
Summary
- Cleavage of the O-H bond is a significant reaction in aldehydes, ketones, and carboxylic acids
- Nucleophilic cleavage results in the formation of two new compounds
- Acidic cleavage leads to the formation of an alcohol
- Various nucleophiles and acids can be used for this reaction
- Understanding these reactions can enable the synthesis of organic compounds
Remember, practice is essential for mastering these reactions!
Sure! Here are slides 11 to 20:
- Nucleophilic Cleavage of O-H Bond (contd.)
- Reaction with Sodium borohydride:
R | R-C=O + NaBH_4 → (R-C)-OH + NaBH_3=O | H
- Reaction with Lithium aluminum hydride:
O / \\ R-C O + LiAlH_4 → R-CH_2OH + LiAl(OH)_3 | H
- These reactions are often used for the reduction of aldehydes and ketones to alcohols
- Acidic Cleavage of O-H Bond (contd.)
- Reaction with hydroxylamine:
R | R-C=O + NH_2OH → R-C=NHOH + H_2O | H
- Reaction with phenylhydrazine:
R | R-C=O + C_6H_5NHNH_2 → R-C=N-NHC_6H_5 + H_2O | H
- These reactions are commonly used for the synthesis of oximes and hydrazones
- Aldol Condensation - Overview
- Aldol condensation is a reaction between two molecules of aldehyde or ketone
- This reaction results in the formation of a β-hydroxyaldehyde or β-hydroxyketone
- The process involves the nucleophilic addition of an enolate ion to the carbonyl group of another molecule
- The resulting compound is often dehydrated to generate an α,β-unsaturated carbonyl compound
- Aldol Condensation - Mechanism
- The aldol condensation reaction involves several steps, including:
- Formation of an enolate ion from the carbonyl compound
- Nucleophilic attack of enolate ion on another carbonyl compound
- Formation of a β-hydroxyaldehyde or β-hydroxyketone
- Dehydration to yield an α,β-unsaturated carbonyl compound
- The reaction is typically catalyzed by either an acid or a base
- Aldol Condensation - Example
- Example 1: Cross aldol condensation
O O //\\ //\\ CH_3-C-CH_3 + CH_3-C-CH_3 → CH_3-C-C-CH_3 + H_2O | | H H
- Example 2: Self-aldol condensation
O O //\\ //\\ CH_3-C-CH_2 + CH_3-C-CH_2 → CH_3-C-C-CH_2 + H_2O | | H H
- Cannizzaro Reaction - Overview
- The Cannizzaro reaction is a disproportionation reaction of an aldehyde
- This reaction involves the simultaneous oxidation and reduction of the same aldehyde molecule
- One molecule of the aldehyde is reduced to an alcohol, while another molecule of the aldehyde is oxidized to a carboxylic acid
- This reaction occurs in the presence of a strong base
- Cannizzaro Reaction - Mechanism
- The Cannizzaro reaction proceeds through the following steps:
- Deprotonation of the aldehyde to form an anion
- Nucleophilic attack of the anion on another aldehyde molecule
- Simultaneous oxidation and reduction reactions take place, forming an alcohol and a carboxylic acid
- The reaction is usually carried out in an alcoholic or aqueous alkaline medium
- Cannizzaro Reaction - Example
- Example: Formaldehyde undergoes the Cannizzaro reaction
H H OH OH | | | | H-C-C-H + KOH → H-C-C-K + H-C-C-OH | | | | H H H OH
- Decarboxylation - Overview
- Decarboxylation is a process that involves the loss of a carboxyl group (-COOH) from a compound
- This reaction is commonly observed in carboxylic acids
- Decarboxylation usually requires high temperatures or the use of catalysts
- It is an important reaction in the synthesis of various compounds, including hydrocarbons and organic acids
- Decarboxylation - Example
- Example: Ethanoic acid undergoing decarboxylation
CH_3-COOH → CH_4 + CO_2 | H
Remember to practice these reactions and their mechanisms for a better understanding.
Sure! Here are slides 21 to 30:
- Esterification - Overview
- Esterification is a reaction that involves the formation of an ester from a carboxylic acid and an alcohol
- This is a condensation reaction that releases water as a byproduct
- The reaction is catalyzed by an acid, such as sulfuric acid or hydrochloric acid
- Esterification is widely used in the synthesis of fragrances, flavors, and plasticizers
- Esterification - Mechanism
- Esterification proceeds through the following steps:
- Protonation of the carbonyl group of the carboxylic acid
- Nucleophilic attack of the alcohol on the carboxylic acid
- Formation of an intermediate compound
- Deprotonation and loss of water to yield the ester
- The reaction is typically reversible, meaning the ester can be hydrolyzed back into the carboxylic acid and alcohol under appropriate conditions
- Esterification - Example
- Example: Esterification of acetic acid with ethanol to form ethyl acetate
O O //\\ //\\ CH_3-C-C-OH + CH_3-CH_2-OH → CH_3-C-C-O-CH_2-CH_3 + H_2O | | H H
- Hydrolysis of Esters - Overview
- Hydrolysis of esters is a reaction that involves the cleavage of an ester bond using water
- This reaction can occur under acidic, basic, or enzymatic conditions
- Acidic hydrolysis forms the carboxylic acid and alcohol, while basic hydrolysis forms the carboxylate ion and alcohol
- Enzymatic hydrolysis is a biologically important process that occurs in the presence of specific enzymes
- Hydrolysis of Esters - Mechanism
- Hydrolysis of esters proceeds through the following steps:
- Protonation of the ester carbonyl group (acidic hydrolysis) or formation of the ester carboxylate ion (basic hydrolysis)
- Nucleophilic attack of water on the carbonyl carbon
- Cleavage of the ester bond, resulting in the formation of carboxylic acid (acidic hydrolysis) or carboxylate ion (basic hydrolysis) and alcohol
- Hydrolysis of Esters - Example
- Example: Acidic hydrolysis of ethyl acetate
O O //\\ //\\ CH_3-C-C-O-CH_2-CH_3 + H_2O → CH_3-C-C-OH + CH_3-CH_2-OH | | H H
- Reduction of Carboxylic Acid - Overview
- Reduction of carboxylic acids involves the addition of hydrogen or hydride ions to the carbonyl group
- This reaction leads to the formation of primary alcohols or aldehydes
- Different reducing agents, such as lithium aluminum hydride (LiAlH4) or sodium borohydride (NaBH4), can be used for this reaction
- The reaction conditions and the choice of reducing agent determine the product obtained
- Reduction of Carboxylic Acid - Example
- Example 1: Reduction of ethanoic acid to ethanol using lithium aluminum hydride
O H OH H // | | | H-C-C-OH + H_2 → H-C-C-OH + H_2 | | | | H H H H
- Example 2: Reduction of ethanoic acid to ethanal using lithium aluminum hydride
O H H // | | H-C-C-OH + H_2 → H-C-C-H + H_2O | | | H H OH
- Oxidation of Aldehydes - Overview
- Oxidation of aldehydes is a reaction that involves the conversion of an aldehyde into a carboxylic acid
- This reaction usually occurs in the presence of an oxidizing agent, such as potassium permanganate (KMnO4) or chromic acid (H2CrO4)
- The carbonyl group of the aldehyde is oxidized to a carboxyl group, resulting in the formation of a carboxylic acid
- Oxidation of Aldehydes - Example
- Example: Oxidation of ethanol to ethanoic acid using acidified potassium dichromate (K2Cr2O7)
H H O H | | | | H-C-C-H + [O] → H-C-C-OH + H_2O | | | | H H O OH
Make sure to understand the mechanisms and conditions for these reactions to score well in your exams!