Aldehydes, Ketones & Carboxylic Acids - Chemical Reactions (Cleavage Of C-OH bond)
- In this lesson, we will learn about the various chemical reactions involving the cleavage of the C-OH bond in aldehydes, ketones, and carboxylic acids.
- These reactions play a crucial role in organic synthesis and have significant industrial applications.
- Let’s begin by understanding the different types of reactions that can occur with aldehydes, ketones, and carboxylic acids when the C-OH bond is broken.
Reaction 1: Acidic Hydrolysis
- Aldehydes, ketones, and esters can undergo acidic hydrolysis to yield carboxylic acids.
- The reaction is carried out in the presence of an acid catalyst, such as sulfuric acid or hydrochloric acid.
- The C-OH bond is cleaved, and a new carboxylic acid is formed.
- Example: Acetone undergoes acidic hydrolysis to form acetic acid.
CH3COCH3 + H2O -> CH3COOH
Reaction 2: Basic Hydrolysis
- Carboxylic acids, esters, and acid chlorides can undergo basic hydrolysis to yield carboxylate ions.
- The reaction is carried out in the presence of a strong base, such as sodium hydroxide or potassium hydroxide.
- The C-OH bond is cleaved, and a carboxylate ion is formed.
- Example: Propanoic acid undergoes basic hydrolysis to form propanoate ions.
CH3CH2COOH + NaOH -> CH3CH2COO- + Na+
Reaction 3: Reduction
- Aldehydes and ketones can be reduced to primary alcohols and secondary alcohols, respectively.
- The reduction reaction is carried out in the presence of reducing agents, such as sodium borohydride (NaBH4) or lithium aluminum hydride (LiAlH4).
- The C-OH bond is cleaved, and a new alcohol functional group is formed.
- Example: Formaldehyde is reduced to methanol.
HCHO + 2H2 -> CH3OH
Reaction 4: Decarboxylation
- Carboxylic acids can undergo decarboxylation, which involves the loss of carbon dioxide (CO2) to form an alkane.
- The reaction is usually carried out at high temperatures or in the presence of strong acid catalysts.
- The C-OH bond in the carboxylic acid is cleaved, leading to the formation of an alkyl group.
- Example: Acetic acid undergoes decarboxylation to form methane.
CH3COOH -> CH4 + CO2
Reaction 5: Esterification
- Carboxylic acids react with alcohols to form esters through esterification.
- The reaction is catalyzed by an acid catalyst, such as sulfuric acid or hydrochloric acid.
- The C-OH bond in the carboxylic acid and the O-H bond in the alcohol are cleaved, leading to the formation of an ester.
- Example: Ethanoic acid reacts with ethanol to form ethyl acetate.
CH3COOH + C2H5OH -> CH3COOC2H5 + H2O
Reaction 6: Cannizzaro Reaction
- The Cannizzaro reaction is a disproportionation reaction that occurs in aldehydes lacking hydrogen on their α-carbon.
- In this reaction, one molecule of aldehyde is reduced to an alcohol, while another molecule is oxidized to a carboxylic acid.
- The reaction is usually carried out in an alkaline medium.
- Example: Formaldehyde undergoes the Cannizzaro reaction to form methanol and formic acid.
HCHO -> CH3OH + HCOOH
Reaction 7: Aldol Condensation
- The aldol condensation involves the combination of two carbonyl compounds, such as aldehydes or ketones, to form a β-hydroxy carbonyl compound.
- The reaction is catalyzed by a base, such as sodium hydroxide or potassium hydroxide.
- The C-OH bond in one carbonyl compound is cleaved, allowing the formation of a new bond with the carbonyl carbon of another compound.
- Example: Ethanal undergoes aldol condensation with propanal to form 3-hydroxybutanal.
CH3CHO + CH3CH2CHO -> CH3CH(OH)CH2CHO
Reaction 8: Claisen Condensation
- The Claisen condensation is a reaction between two ester molecules or an ester and a ketone to yield a β-keto ester.
- The reaction is catalyzed by a base, such as sodium ethoxide or potassium ethoxide.
- The C-OH bond in one ester molecule is cleaved, allowing the formation of a new bond with the carbonyl carbon of another molecule.
- Example: Ethyl acetate undergoes Claisen condensation with ethyl propanoate to form ethyl 3-oxobutanoate.
CH3COOC2H5 + CH3CH2COOC2H5 -> CH3CH2COCH2COOC2H5
Reaction 9: Perkin Reaction
- The Perkin reaction involves the condensation of an aromatic aldehyde with an acid anhydride or carboxylic acid to produce a β-aryl carboxylic acid.
- The reaction is catalyzed by an acid catalyst, such as sulfuric acid or hydrochloric acid.
- The C-OH bond in the acid anhydride or carboxylic acid is cleaved, leading to the formation of a new bond with the aromatic aldehyde.
- Example: Benzaldehyde undergoes Perkin reaction with acetic anhydride to form cinnamic acid.
C6H5CHO + (CH3CO)2O -> C6H5CH=CHCOOH + CH3COOH
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Slide 11:
- Reaction 10: Beckmann Rearrangement
- The Beckmann rearrangement involves the conversion of an oxime into an amide.
- The reaction is typically carried out using a strong acid, such as sulfuric acid or hydrochloric acid.
- The C-OH bond in the oxime is cleaved, leading to the formation of a C-N bond with an amide.
- Example: Cyclohexanone oxime undergoes Beckmann rearrangement to form ε-caprolactam.
- Cyclohexanone oxime → H2SO4, Δ → ε-caprolactam
Slide 12:
- Reaction 11: Fischer Esterification
- The Fischer esterification is a reaction between a carboxylic acid and an alcohol to form an ester.
- The reaction is catalyzed by an acid catalyst, typically sulfuric acid or hydrochloric acid.
- The C-OH bond in the carboxylic acid and the O-H bond in the alcohol are cleaved, leading to the formation of an ester.
- Example: Acetic acid reacts with methanol to form methyl acetate.
- CH3COOH + CH3OH → H2SO4 → CH3COOCH3 + H2O
Slide 13:
- Reaction 12: Oxidation of Aldehydes
- Aldehydes can be oxidized to carboxylic acids using various oxidizing agents, such as potassium permanganate (KMnO4) or chromic acid (H2CrO4).
- The C-OH bond in the aldehyde is cleaved, and a carboxylic acid is formed.
- Example: Ethanal is oxidized to ethanoic acid using potassium permanganate.
- CH3CHO + [O] → KMnO4, H+ → CH3COOH
Slide 14:
- Reaction 13: Oxidation of Alcohols
- Primary alcohols can be oxidized to aldehydes and further oxidized to carboxylic acids, while secondary alcohols are oxidized to ketones.
- Oxidizing agents commonly used are potassium dichromate (K2Cr2O7) or acidified potassium permanganate (KMnO4).
- The C-OH bond in the alcohol is cleaved, forming either an aldehyde or a ketone.
- Example: Propan-1-ol is oxidized to propanal using acidified potassium dichromate.
- CH3CH2CH2OH + [O] → H2Cr2O7, H+ → CH3CH2CHO
Slide 15:
- Reaction 14: Haloform Reaction
- Ketones with a methyl group attached to the carbonyl carbon can undergo haloform reaction to form a haloform (halogen-substituted methyl ketone).
- The reaction is carried out in the presence of a strong base, such as sodium hydroxide (NaOH), and a halogen source, such as iodine (I2) or bromine (Br2).
- The C-OH bond in the methyl ketone is cleaved, resulting in the formation of a haloform and a carboxylate ion.
- Example: Acetone undergoes haloform reaction to form chloroform and acetate ion.
- CH3COCH3 + 3NaOH + I2 → CHCl3 + CH3COO- + 3NaI
Slide 16:
- Reaction 15: Tishchenko Reaction
- The Tishchenko reaction involves the disproportionation of an aldehyde in the presence of a metal catalyst.
- Two molecules of the aldehyde react to form one molecule of an ester and one molecule of a carboxylic acid.
- The reaction is often catalyzed by metal alkoxides, such as sodium methoxide (NaOMe).
- Example: Benzaldehyde undergoes Tishchenko reaction to form benzyl benzoate and benzoic acid.
- 2C6H5CHO → NaOMe, CH2Cl2 → C6H5CH2OCOC6H5 + C6H5COOH
Slide 17:
- Reaction 16: Wittig Reaction
- The Wittig reaction involves the transformation of an aldehyde or a ketone into an alkene using a phosphorus ylide.
- The phosphorus ylide acts as a nucleophile, attacking the carbonyl carbon and forming a carbon-carbon double bond.
- The C-OH bond in the aldehyde or ketone is cleaved, resulting in the formation of an alkene.
- Example: Benzaldehyde undergoes Wittig reaction to form stilbene (trans-1,2-diphenylethylene).
- C6H5CHO + Ph3P=CH2 → C6H5CH=CHC6H5 + Ph3P=O
Slide 18:
- Reaction 17: Claisen Rearrangement
- The Claisen rearrangement involves the rearrangement of an allyl vinyl ether to form a γ,δ-unsaturated carbonyl compound.
- The reaction is often carried out using a strong base, such as sodium ethoxide (NaOEt).
- The C-OH bond in the allyl vinyl ether is cleaved, resulting in the formation of the new unsaturated carbonyl compound.
- Example: An allyl vinyl ether undergoes Claisen rearrangement to form a γ,δ-unsaturated ketone.
- CH2=CH-CH2-O-C(CH3)2CH3 → NaOEt, heat → CH2=CH-C(O)-C(CH3)2CH3
Slide 19:
- Reaction 18: Nitrile Hydrolysis
- Nitriles can undergo hydrolysis to form carboxylic acids in the presence of an acid or a base.
- In acidic conditions, the C-N bond in the nitrile is cleaved, and a carboxylic acid is formed.
- In basic conditions, the nitrile is converted to an amide before undergoing hydrolysis to form a carboxylic acid.
- Example: Acetonitrile undergoes hydrolysis in acidic conditions to form acetic acid.
- CH3CN + H2O → H+ → CH3COOH
Slide 20:
- Reaction 19: Wolff-Kishner Reaction
- The Wolff-Kishner reaction involves the reduction of a carbonyl compound to a hydrocarbon using hydrazine (N2H4) and a strong base.
- A C-OH bond is formed through the reaction of the carbonyl carbon with hydrazine, followed by the cleavage of the C-N bond and formation of a C-N double bond.
- Example: Propanone undergoes Wolff-Kishner reaction to form propane.
- CH3COCH3 + N2H4, KOH → CH3CH3
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Slide 21:
- Reaction 20: Nucleophilic Addition
- Aldehydes and ketones can undergo nucleophilic addition reactions with various nucleophiles.
- A nucleophile attacks the carbonyl carbon, forming a new bond and breaking the C-OH bond.
- The product formed depends on the nature of the nucleophile used.
- Example: Formaldehyde reacts with hydrogen cyanide (HCN) to form hydroxyacetonitrile.
Slide 22:
- Reaction 21: Oxime Formation
- Aldehydes and ketones can react with hydroxylamine (NH2OH) to form oximes.
- The nucleophilic nitrogen attacks the carbonyl carbon, forming a new bond and breaking the C-OH bond.
- The product is an oxime, which contains a nitrogen-oxygen double bond.
- Example: Propanone reacts with hydroxylamine to form propanone oxime.
- CH3COCH3 + NH2OH → H3C-C(=N-OH)CH3
Slide 23:
- Reaction 22: Aldol Reaction
- The aldol reaction involves the condensation of two aldehyde or ketone molecules, resulting in the formation of a β-hydroxy carbonyl compound.
- The reaction is catalyzed by a base, such as sodium hydroxide (NaOH).
- The C-OH bond in one carbonyl compound is cleaved, allowing the formation of a new bond with the carbonyl carbon of another compound.
- Example: Propanal undergoes aldol reaction with propanal to form 3-hydroxybutanal.
- CH3CH2CHO + CH3CHO → NaOH → CH3CH(OH)CH2CHO
Slide 24:
- Reaction 23: Claisen-Schmidt Reaction
- The Claisen-Schmidt reaction is a variation of the aldol reaction, where one reactant is an aldehyde or ketone and the other is an aromatic compound with an active hydrogen.
- The reaction is catalyzed by a base, such as sodium hydroxide (NaOH).
- The C-OH bond in the carbonyl compound is cleaved, allowing the formation of a new bond with the carbonyl carbon of the aromatic compound.
- Example: Benzaldehyde reacts with acetophenone to form chalcone.
- C6H5CHO + CH3COCH3 → NaOH → C6H5CH=CHC(O)CH3
Slide 25:
- Reaction 24: Fischer Indole Synthesis
- The Fischer indole synthesis involves the condensation of a phenylhydrazine derivative with a ketone or aldehyde to form an indole compound.
- The reaction is catalyzed by an acid, such as hydrochloric acid (HCl).
- The C-OH bond in the carbonyl compound is cleaved, allowing the formation of a new bond with the phenylhydrazine derivative.
- Example: Benzaldehyde reacts with phenylhydrazine to form benzoin.
- C6H5CHO + C6H5NHNH2 → HCl → C6H5CH=C(NHPh)NH2
Slide 26:
- Reaction 25: Stephen Reduction
- The Stephen reduction involves the conversion of nitro compounds to corresponding substituted amines.
- In the reaction, a nitro compound is reacted with stannous chloride (SnCl2) and hydrochloric acid (HCl).
- The C-OH bond in the nitro compound is cleaved, forming an amine.
- Example: Nitrobenzene reacts with stannous chloride to form aniline.
- C6H5NO2 + SnCl2 + HCl → C6H5NH2 + SnCl4 + H2O
Slide 27:
- Reaction 26: Halogenation at α-carbon
- α,β-unsaturated carbonyl compounds can undergo halogenation at the α-carbon atom.
- The C-OH bond at the α-carbon of the unsaturated compound is cleaved, resulting in the formation of a halogen-substituted carbonyl compound.
- The reaction is usually carried out using halogenating agents, such as chlorine or bromine.
- Example: Acrolein undergoes halogenation at the α-carbon to form dibromopropanone.